The friction of an object placed on a slope?

The same. The object itself has gravity, so the inclined plane will give the object a support force perpendicular to the contact surface, because the supporting force is not vertically upward because of the relationship between the inclined plane, so the gravity does not completely act on the inclined plane (the supporting force is less than the gravity), part of the gravity will give the object a downward movement trend along the inclined plane, and what hinders this movement trend is the frictional force of the inclined plane to the object, and when the gravity of this part is greater than the frictional force, the object will slip. However, regardless of whether the object is placed horizontally or vertically, the friction force is the same (the friction force is only related to the mass of the object and the roughness of the contact surface, not the contact area), so the degree of slippage is the same.

Personal thoughts.

Same. The friction generated by an object placed on a slope is related to the roughness of the contact surface and is related to the area.

It slips back because its downward gravitational component is greater than the friction it produces when it touches the contact surface, regardless of how it is placed.

Unless the material on the transverse side of the object is not the same as the vertical side. Then the rougher the side, the less slippery it is.

The friction generated by the object placed on the slope is related to its own gravity and the roughness of the contact surface, according to the calculation formula, the friction force is equal to the component of its gravity on the inclined plane, no matter how the gravity of the object is placed, and the roughness of the contact surface of the whole process has not changed, that is, the friction force is unchanged, so it has nothing to do with horizontal and vertical placement.

Personal insights, I hope it can help you.

It is necessary to judge the two items according to the center of gravity of the object, the component of the force in the perpendicular direction of the object and the inclined plane.

You see that the contact area is small.

Vertically, because in this way the force of gravity is large and easy to go downward.

When the object is at rest on the inclined plane, the downward component of the gravitational force along the inclined plane is equal to the frictional force and is a static frictional force, and the magnitude of the frictional force is mgsin

When the object slides at a constant speed, the maximum static friction experienced by the object is equal to the component of gravity, i.e., mgcos = mgsin

When this component is greater than the maximum static friction, the object will slide downwards and the experienced friction force is mgcos, which is not necessarily equal to the component of gravity.

The object is at rest.

f=mgsinθ

f= mgcos when sliding

Friction ForceWhen two objects in contact with each other are in relative motion or have a relative motion tendency, a force that hinders the relative motion or relative motion tendency will be generated on the contact surface, and this force is called frictional force. Friction is a contact force, i.e., there can be friction between objects that are in contact with each other.

Friction generation conditions:

First, objects are in contact with each other;

Second, there is a mutual squeezing effect between objects;

Third: rough contact surface of the object;

Fourth, there is a tendency or relative motion between objects;

Classification of friction:

Static friction. Rolling friction.

Sliding friction.

The magnitude of friction.

on a horizontal plane.

The magnitude of friction when at rest.

f=f The direction of friction is opposite to the direction of thrust.

The amount of friction when sliding.

f= fnfn refers to the positive pressure, and the direction of friction is opposite to the relative direction of motion on an inclined plane.

If the object is stationary on an inclined plane, frictional force.

f=f1=mgsinθ

The direction is upwards along the inclined plane.

If the object is moving on an inclined plane, the frictional force is sliding friction.

f=μf2＝μmgcosθ

The direction of friction is opposite to the relative direction of motion of the object.

In the case of static friction, the object is subjected to friction, but no relative motion occurs. In this case, the static friction experienced by the object is the external force exerted. Another case is kinetic friction, which is often mentioned in physics textbooks, where objects are subjected to friction and tremble to produce relative motion.

The code bond cultivates a coefficient of friction, and then is subjected to an external force, which has its own gravity. In this case, the frictional force is * n, and n is the positive pressure on the object, which is the pressure on the surface of the object perpendicular to the frictional force (the component of gravity on the surface of the frictional force).If you put it on a slope, n is equal to the cosine of gravity g multiplied by the angle of the slope, n = g*cos(a), a is the angle of the slope, and the friction force is * n

Note that in this dynamic friction situation, the friction force on the object has nothing to do with the physical external force, but only the gravity and friction coefficient of the object. Traction is the component of gravity g in the relative direction of motion of an object. g*sin（a）.

It will be very difficult to solve the situation of the static plane with the overall method, and it may even enter the misunderstanding.

The motion of an object is relatively simple, so it is better to analyze the motion and force of the object, so that the force on the inclined plane can be inferred. If the ground is smooth, it is easier to use the whole method.

The object has pressure on the inclined plane, and it is this pressure that produces a horizontal thrust on the inclined plane, but the inclined plane remains stationary, so the inclined plane is also subjected to the static friction of the ground, which is balanced by the horizontal force mentioned above.

According to the formula: baif = fn fn: positive pressure (du is not necessarily equal to the gravitational force of the object to which the force is applied) : kinetic friction factor (is a numerical value.

within, unitless).

Rolling friction is the friction force on which the contact surface of the object changes all the time when it rolls. It is essentially static friction. The contact surface is soft, and the greater the shape change, the greater the rolling friction.

In general, the rolling friction between objects is much less than the sliding friction. Rolling bearings are widely used in the transportation and mechanical engineering industries to reduce friction. For example, the friction of the driving wheels of a train is the driving force that pushes the train forward.

The static friction of the driven wheels is the rolling friction that hinders the progress of the train.

Properties: First: Objects are in contact with each other.

Second, there is a mutual squeezing effect between objects;

Third: the contact surfaces of the objects are rough.

Fourth, there is a tendency or relative motion between objects;

Ways to increase beneficial friction:

1) Increase the roughness of the contact surface.

2) Increase the pressure.

3) Transform rolling friction into sliding friction.

Ways to reduce harmful friction:

1) Replace sliding friction with rolling friction.

2) Separate the contact surface and form a layer of air cushion or magnetic levitation on the contact surface of the object.

3) Reduce stress.

4) Reduce the roughness of the contact surface of the object.

To be clear.

Only the body of matter is in complex motion, while the inclined plane is stationary, and the acceleration of baiacosa is only the acceleration of the DU object, so.

zhi resultant force only uses to multiply daom.

For the problem of inconsistent motion of various objects in this system, the whole method should not be blindly used, so in this problem, when the inclined plane is subjected to the friction force of one side, it is balanced by the positive pressure of the block on the inclined plane, so it is not incomprehensible that the inclined plane is stationary. Hope to adopt.

The acceleration is block, not beveled, and if (m+m)acosa thinks that the inclined plane also has acceleration, in fact it does not. It is true that the object of your study is the whole, but it is confusing the movement, and it is a formal application of the holistic approach without considering the physical meaning behind it. If the system is viewed as a whole, there is acceleration, after all, the blocks are accelerating downward, and everything is not balanced, and it is seen as balance because the balance condition is missed or the motion analysis is not thorough enough.

Why does it seem to mislead you into thinking that balance, because if you look at the inclined plane in isolation, it is balanced, so it is better to follow the force analysis and motion analysis step by step, don't intuitively feel, physics is a science.

The situation you are talking about is oblique.

The copy surface moves with the body, and in this problem only the object moves. The bevel is in zhi

The frictional force is applied horizontally, which is equivalent to the horizontal external force on the whole system, so the system will not be balanced, and it will be manifested as an accelerated slide of the object. The resultant external force experienced by the system is ma, and the horizontal frictional force is macosa.

How can we use the holistic method, one is moving and the other is not moving, and if you say the wrong thing, one is accelerating and moving.

The direction is up the inclined plane and the magnitude is mgsin( ).

If f=mgsin, then the friction of the inclined plane is 0, if f>mgsin, then the friction is f-mgsin, and the friction is f-mgsin, and the friction is f, and the friction force is f, and the friction force is f