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Anonymous users2024-02-07U represents the object distance, V represents the image distance, and F represents the focal length.
When u f, that is, when the object distance is less than one time the focal length, it becomes an upright virtual image with magnification. (magnifying glass) when u=f, that is, when the object distance is equal to one time the focal length, no image is imaging. This one is best to memorize.
When f u 2f, that is, the object is in.
When the focal length is between one and two times, it becomes a magnified inverted real image. When U=2F, that is, when the object distance is equal to twice the focal length, it is an inverted real image of equal size.
When U 2F, that is, when the object distance is greater than twice the focal length, it becomes a reduced inverted real image. (Camera) notation: double the focal length is divided into virtual and real, and double the focal length is divided into size.
When it is a real image, the object is close and far away, and it is like a large image. (The object distance decreases, the image distance increases, the image becomes larger), and the object is far away and small than the near image.
When it is a virtual image, the object is far away and far like and large, and the object is close and small.
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Anonymous users2024-02-06u v f object image focus ('you wei aifu object image focus' read it 10 times and forget it after looking at it).
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Anonymous users2024-02-05According to English, these are abbreviations in English, focal length: f, focus;
The remaining two are not clear, try to study it yourself, and you will definitely not forget the answer you found, and you have to learn English well!
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Anonymous users2024-02-04f focus u thing wu distance (there is u in the thing) the remaining one is like the distance.
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Anonymous users2024-02-03You don't have to learn this. The high school entrance examination is not examined. Easy way to "rote memorization".
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Anonymous users2024-02-02Analysis: The force analysis of the object shows that the object moves in a uniform and accelerated linear motion under the combined action of horizontal tension and friction.
f-f=ma, f=8n, f=2n, can get a=3m s, the velocity after 3s is v=at=3*3=9m s, the displacement in 3s is s=1 2*a*t =, I hope it can help you
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Anonymous users2024-02-01By Newton's second law f=ma
8-2=2a
a=3m/s^2
The velocity at the end of 3s v=at=3*3=9m s
The displacement in 3s s=1 2*a*t 2=1 2*3*3 2=
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Anonymous users2024-01-31The net force acting on the object is 8n-2n = 6n, the acceleration is a = f, m = 6, 2 = 33, the velocity at the end of the second, v = at = 3*3 = 9m, s3, the displacement in 3 seconds, s = 1, 2 a*t =
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Anonymous users2024-01-30It is known that the speed of the ant in the distance hole or on the center of the world. v for.
v=k1m2/s=
m2 s, so when.
l2=2m.
v2 = defined by the velocity return to the wild: ant from. l to.
L+δl takes time δt to . t
lllvksvtv
AT is analogous to the two basic formulas of uniform acceleration and linear motion with zero initial velocity. At. t to. t+δt
The displacement δs at the moment is. s
ATT comparison and two formulas can be seen that the expression form of the two formulas is the same.
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Anonymous users2024-01-29The electric potential at each point in the space from positive charge to negative charge gradually decreases, but because on the same conductor, the conductor is in electrostatic equilibrium at this time, it is an equipotential body, so the electric potential at the two points is equal, and the electric potential is also equal in the same way. But the proximity to positive charge potential is higher and close to the negative charge potential is lower. So the correct answer is b
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Anonymous users2024-01-28The mass of a brick: m v, v
So: m 2000
m total 4t 4000kg
Number: 4000 pieces, take: 1428 pieces.
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Anonymous users2024-01-27Density * Volume = Weight! First, find the weight of a single brick, divide the load by the weight of a single brick, which is the number of bricks.
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Anonymous users2024-01-26To put it bluntly, this is a basic problem in elementary school mathematics.
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Anonymous users2024-01-25First, the volume unit of the brick is replaced by cubic meters, and then the density is multiplied by the volume to get the mass of a brick, and then the load of a car is divided by the mass of a brick, and the number obtained is the number of bricks that the car can load.
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Anonymous users2024-01-241) Big stuffiness next to the virtual cover old (2) Uniform speed straight line (difference 3) (4) Right b look.
A sliding rheostat slide p when moving to the right sliding rheostat resistance increases, so the total resistance increases, the total current decreases, so the ampere representation number becomes smaller, the lamp becomes dim. The voltmeter measures the voltage of the sliding rheostat, which is equal to the voltage of the supply voltage minus the lamp. Because the voltage of the supply does not change, the voltage of the lamp decreases, so the indicator of the voltmeter becomes larger. Choose A
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