Mathematics Ancient Fun Problems Urgent!! 15 Math Fun Questions!!!!

Li Bai walked on the street without incident, carrying a wine jug to drink.

Double the hotel when you encounter it, and drink a bucket when you meet the flowers.

Sanyu Hotel Sanyu Flower, just after drinking the wine in the pot.

How much wine was in the jug? (7 8 buckets).

(1) In the "guess the fan" competition of the six (3) class party, there are 10 questions to answer, and it is stipulated that 5 points will be awarded for 1 correct answer, 8 points for 1 wrong answer, and 0 points for those who do not answer, Lingling will get a total of 12 points, how many questions will she answer correctly? How many questions did you get wrong?

2) If the side view of a cylinder is a square, how many times the height of this cylinder is the radius of the bottom surface of the cylinder? (3) A 2-meter-long steel bar, after being cross-cut into two sections, increases the surface area by square centimeters. What is the volume of this rebar in cubic centimeters?

4) The school bought a bundle of plastic ropes 135 meters long, and first cut 27 meters to make 15 skipping ropes. According to this calculation, how many jump ropes can be made with the remaining rope?

5) The elder brother has 100 yuan and the younger brother has 80 yuan, how many yuan does the elder brother give to the younger brother, and the ratio of the two brothers is 7:11?

6) Mix 10 small flags of red, white and blue. If you are asked to close your eyes and take it, how many small flags will be held at least at a time to ensure that there must be two small flags of the same color?

7) There are 129 people in a meeting, and if you shake hands with each person once, then you shake hands ( ) times.

8) Put the 7 kittens in 3 cages each, no matter how you put them, there will always be at least ( ) cats in one cage.

9) The minimum seven-digit number that is not read by using "2", "7", "8", "5" and 3 "0" to form a "0" is ( )10) If the circumference of a square and a circle is the same, ( The area of ( is the largest.

11) Wang Fang and Li Gang each have a certain amount of money, and if Wang Fang gives Li Gang her original amount of money, and Li Gang gives Wang Fang his original amount of money, then the two of them have exactly the same amount of money. Originally, the ratio of money to each of them was ( ).

12) A line segment divides a rectangle into two parts, and 4 line segments can divide a rectangle into ( ) parts at most. (13) Two shepherd boys were tending their sheep, and A said to B, "Give me one of your sheep, and my sheep will be exactly twice as many as yours."

B said to A, "It would be better to give me one of your sheep, so that I and your sheep will be equal." "Tell me that A has ( ) sheep and B has ( ) sheep.

14) The price of 7 kg of apples and 4 kg of pears is equal, and 1 kg of pears is more expensive than 1 kg of apples. How much do pears and apples cost per kilogram?

15) There are two bags of sugar, one bag is 84 grains, and the other bag is 20 grains, each time take out 8 grains from the more bag and put it in the less bag, take ( ) times to make the two bags of sugar the same amount?

Answers to fun math problems:

1) 4 correct answers and 1 incorrect answer.

2) 2 times.

3) 628 cubic centimeters.

4) 60 roots.

5) 30 yuan.

6) 4 sides. 7) 128 times. 8) 3pcs.

10) Circle. 12) Part 11.

13) A has (7) sheep and B has (5) sheep.

14) Pears per kilogram, apples per kilogram.

15) Take 4 times.

Upstairs isn't all right.

The first two examine the concept of absolute values:

1. The absolute value represents the distance between two points on the number line, so according to the title, there are:

a-(-2)│=3 │b-2│=6

The solution yields a = 1 or -5 b = 8 or -4

when a=-5, b=-4, ab=1;

when a=-5, b=8, ab=13;

When a=1, b=-4, ab=5;

When a=1, b=8, ab=7

2. The algebraic sum is -18

Absolute sum of values: 6 + 15 + 3 = 6 + 15 + 3 = 24 algebra sum is smaller than the sum of absolute values: 24-(-18) = 42, so choose d3, except for the first term, every sum of the following two items is -1, and there are a total of 2008 numbers behind, so there are a total of 1004 -1

So the original formula = 1 + (2-3) + (4-5) + (6-7) + (8-9) + ·2006-2007) + (2008-2009).

4. Every two sums are 1, and there are 2010 numbers in total, so there are 1005 1 original formulas = (-1+2)+(3+4)+(5+6)+·2009+2010).

5. A positive number is +8, one-third, and a negative number is neither.

So positive and minus negative numbers and:

Rational numbers are best calculated using fractions.

1. a=-5 or 1; b = -4 or 8

when a=-5, b=-4, ab=1;

when a=-5, b=8, ab=13;

When a=1, b=-4, ab=5;

When a=1, b=8, ab=7

2. The algebra sum is -18, and the sum of absolute values is 24, so it is 42. Choose d3, original = 1 + 1 + 1 + ......1=1+1×（2009-1）÷2=1005

4. Original formula = 1+1+1+......1 = 1 2010 2 = 10055, (8+ (137 out of 6)

Question 1: From the number line, we can know that a = 1 or -5, b = 8 or -4, so the distance between a and b is 7, 5, 13 or 1

Question 2: The algebraic sum is -6 + (-15) + 3 = -18, the absolute sum is 6 + 15 + 3 = 24, 24 - (-18) = 42, choose d

Question 3: Original formula = 1 + (2-3) + (4-5) + ...2008-2009)=1-1-1-…-1=1-1004=-1003

Question 4: Original formula = (-1+2)+(3+4)+....2009+2010)=1005

Question 5: Positive number addition: 8+ Negative number addition: -3 + ( Positive number minus negative number: 253 30-(-72 5) = 137 6

。。。The above three digits are the same. All right.

Such questions are too boring, and it's best not to ask them again.

Proportional form is the form in which it is written as a ratio.

3 4 = 2 6, written proportionally.

It can also be written as a fraction.

3×4=2×6

Changed to: 12=12

Proportionality is to write the ratio as a fraction.

Solution: Because the quadrilateral ABCD is a square, ad=ab=bc

a=∠b=90°

dh=ae=bf=ab/3

then ah=be=2ab3

aeh≅△bfe

eh=efahe=∠bef

In the same way, ef=fg

fg=ghgh=he

he=ef=fg=gh

The quadrilateral EFGH is rhomboidal because AHE+ AEH=90°

BEF+ AEH = 90° (equivalent substitution).

hef=180-90=90°

The quadrilateral efgh is a square. (one corner is a diamond at right angles) s square efgh = eh 2 = ((ab 3) 2) + (2ab 3) 2).

5(ab^2)/9

S shade S square ABCD = 5 9

The problem of not knowing the number of things comes from the ancient mathematical masterpiece "Sun Tzu's Arithmetic" 1,600 years ago. Originally titled:"Today, there are things that do not know their number, three or three numbers, five or five numbers, seven or seven numbers, ask the geometry of things? "

Divide 3 by 2, divide 7 by 2, so divide by 2, the least common multiple of 3 and 7 21 divides by 2, and the number 21 divided by 2 we first think of 23; 23 happens to be divided by 5 by 3, so 23 is an answer to this question.

1. Today Arita wide fifteen steps, from sixteen steps. Q: Geometry for the field?

Answer: One acre.

2. There are twelve steps from Tian Guang, and from fourteen steps. Q: Geometry for the field?

Answer: One hundred and sixty-eight steps.

Fang Tianshu said: Guangcong multiplies the number of steps to get the steps.

Divide it by 240 steps by the mu method, that is, the number of mu. A hundred acres is one acre.

3. Today, Arita is wide and one mile, from one mile. Q: Geometry for the field?

Answer: Three acres and seventy-five acres.

Fourth, there are two miles of Tian Guang, and three miles. Q: Geometry for the field?

Answer: Twenty-two acres and fifty acres.

Sarita said: Wide from the number of miles multiplied to get the product. Multiply it by three hundred and seventy-five, that is, the number of acres.

In "Zhang Qiu Jian's Sutra", it is the 38th question under the original volume, and it is also the last question of the whole book: Today, there is a chicken Weng, which is worth money; The hen is one, and it is worth three; Three chickens are worth one. Where you buy 100 chickens for 100 dollars, ask the chickens, mothers, and catfishes?

Answer: Chicken Weng four, worth twenty; Eighteen hens, worth fifty-four; Seventy-eight chickens are worth twenty-six. And again:

Eight chickens, worth forty; The hen is eleven, which is worth thirty-three, and the chicken is eighty-one, which is worth twenty-seven. And he replied: Twelve chickens, worth sixty; Hens.

Fourth, it is worth twelve; Eighty-four chickens are worth twenty-eight. The importance of this problem is that it creates a precedent of "one question and multiple answers", which was not found in ancient Chinese arithmetic books in the past.

The meaning of this question is: there is a batch of items, and I don't know how many there are. If three pieces are counted in three pieces, there will be two pieces left; If five pieces count five pieces, there will be three pieces left; If seven pieces are counted in seven pieces, there will be two pieces left. Q: How many items are in this batch?

What becomes a purely mathematical problem is: there is a number, divide it by 3 by 2, divide it by 5 by 3, divide it by 7 by 2. Find this number.

The problem is very simple: divide 3 by 2, divide 7 by 2, so divide 2 by the least common multiple of 3 and 7 21, and divide 2 by 21 The number of 2 we will first think of 23; 23 happens to be divided by 5 by 3, so 23 is an answer to this question.

The reason why this problem is simple is that the remainder of the division by 3 and the division by 7 is the same. Without this peculiarity, the problem would be less simple and much more interesting.

Let's take another example; Han Xindian had more than two soldiers in a group of three, three more in a group of five, and four in a group of seven. Q: How many soldiers are there in this group at least?

The problem is to ask for a positive number divided by 3 by 2, 5 by 3, 7 by 4, and the number is as small as possible.

If a student has never been exposed to this kind of problem, he can also use the method of trial and analysis to increase the conditions step by step to introduce the answer.

It's hard to read, but where is it?