How many tiles are shared to build a square pool with a side length of 20 meters and use tiles with

A square pool with a side length of 20 meters needs to be pasted on a total of 5 sides, and the side length is 2 decimeters = meters.

The area of tiles is square.

The area of the pool on one side is 20*20=400 square meters, and 400 pieces are needed.

5 sides is 10,000 * 5 = 50,000 pieces.

20 meters = 200 decimeters.

200 2 = 100 blocks.

Each surface should be paved with 100x100=10,000 pieces.

There are 5 sides of the pool, so you need a total of tiles

10000x5=50000 blocks.

If you need to lay a circle of tiles around the edge of the pool, you have to add more:

100x4+4=404 blocks.

A total of tiles are needed: 50,000 + 404 = 50,404 pieces.

If I put two circles of tiles around the edges, I will have to add a few tiles to the corners, and it will be too late for me to figure it out.

The total area divided by the area of each tile is the total number of tiles used. S total = 20x20 = 400 m, s porcelain = m, total number of blocks: n = 400 (blocks).

200 2=100 rows.

200 2 = 100 columns.

100 100 = 10,000 blocks.

A: A total of 10,000 tiles will be used.

(1) If the pool is tiled around the pool and the bottom of the pool:

The area of tiles in the pool = bottom area + 2 (front surface + left surface area) = length x width + 2 (length x depth + width x depth).

3ox24+2 (30x12+24x12) = 2016 square decimeters.

2) If you put tiles only in the pool for 4 weeks

The area of tiles = front and rear side area + left and right side surfaces.

2 (length x depth + width x depth).

2(30x12+24x12)

2x6481296 square decimeters.

There are 4 rectangles around the pool, two rectangles of 30 12 and two rectangles of 24 12.

Therefore, the required tile area is:

2 30 12 + 2 24 12 1296 (square decimeter).

The area that needs to be tiled is.

20 8 (20 sqm).

Tiles are needed. 244 (block).

The area is 4 3+2 (4+3) 2=40 square meters.

So to 40 (blocks.)

The maximum water storage is 4 3 2 = 24 cubic meters.

Area = 4 3 + 2 (4 + 3) 2 = 40 square meters 2 dm = dm.

Tiles = 40 (blocks.)

Water storage = 4 3 2 = 24 cubic meters.

A rectangular cistern 20 meters long, 8 meters wide and 8 meters deep is tiled, and a total of 244 square meters of tiles are required.

This is to calculate the surface area of the reservoir, which should be five faces, so it is 20 square meters.

Bottom: 20 8 160 (sq.m.).

Front and rear sides: 8 sqm).

Left and right: 20 sq.m.).

160 + 24 + 60 244 (sq.m.).

The area of its base and four facades is 244 square meters.

Then you calculate the amount of tiles based on this area and the loss of tiles.

= 244 (sqm).

A total of 244 square meters of tiles are required.

A total of 244 square meters of tiles are required.

Multiply equals square meters equals 240 240 divided equals 6000 blocks.

The area to be tiled is 20 8 (20 square meters) and 244 tiles (blocks) are required

(20x8+ square meters square meters 404 divided by blocks.)

The area that needs to be tiled is.

20 8 (20 sqm).

Tiles are needed. 244 (block).

The length of the reservoir may be 3 meters, then the bottom area of the reservoir is 3*10 30 square meters, each tile area is square meters, and 30 tiles are needed.

Side area: (3+10)*2*square meters, tiles required: blocks.

Total tiles needed: 750 + 1430 2180 tiles.

3 cm long?

The tiles are almost 3 cm thick. Can you let it go?