The known function f x x x 1 out of 5

f(x) = (x+1) / (x-5)

Substituting x=3 yields: y= (x+1) (x-5) = (3+1) (3-5) = -2≠2

The dots (3,2) are not on the image of f(x).

Substituting x=4 yields: f(4) = (4+1) (4-5) = -5 Substituting f(x)=2 yields: 2= (x+1) (x-5)x+1 = 2x-10

x=11

1) Substituting x=3, y=2 into the equation (3+1) (3-5)=-2≠2, so (3,2) is not on the image.

2) f(4)=(4+1) (4-5)=-53) when x=4 i.e. (x+1) (x-5)=2x+1=2x-10

Solution x=11

f(x) = x-5 x+1

1+6/(x-5)

1)x=3,y=-2

The dots (3,2) are not on the image of f(x).

2) When x=4.

f(x)=-5

3) When f(x)=2, find the value of x.

1+6/(x-5)=2

x=11

Let x+1 0, that is, when x -1, f(x+1)=1 (x+1) scatter width; Let the punch Yuliang x+1 0, that is, when x -1, f(x+1)=(x+1)false detection?That's analytical.

Let a=1 state dust x

Then the book of jujube Zen x = 1 a

So f(a)=(1 a) (1-1 rock burn a)=1 (a-1) so f(x)=1 (x-1).

f(1)=1

The method is as follows, please do the demolition resistance pure travel test: acres.

f(1) is the value of the function f(x) when x=1, and directly substitute x=1 into f(x)=x 5 to get f(1)=1 5=1

Summary. f(x+1)=x-5, find f(x).

f（x+1）=x+1-6

So substitution can be obtained.

f（x）=x-6

f(x+1)=x-5, find f(x).

f(x+1)=x-5, find f(x)f(x+1)=x+1-6, so substitution can give f(x)=x-6

If this kind of question is more complicated, it can also be done using the commutation method

Thank you.

Let 1 x=t, then muffled x=1 ant knows t

f(t)=x 2+5x=(1 t) 2+5 t, so f(x)=1 x 2+5 Lingma xx≠0

f(x)=x²/(1+x²)

f(2)=2²/(1+2²)=4/5

f(1/2)=(1/2)²/1+(1/2)²]1/4)/(5/4)=1/5

f(3)=3²/(1+3²)=9/10

f(1 3)=(1 3) Bi Huan[1+(1 3) Lifting Beam]=(1 9) (10 9)=1 10

f(2)+f(1/2)=4/51/5=1 f(3)+f(1/3)=9/10+1/10=1

Conjecture: f(x)+f(1 x)=1, is a fixed value.

Certificate: f(x)+f(1 x)=x (1+x) 1 x) 1+(1 x)].

x²/(1+x²)+1/x²)/1+ 1/x²)

x²/(1+x²)+1/(x²+1)

x noisy number luck +1) (1+x ).