A rectangle is 1 cm longer than it is wide, and the area is 132 square centimeters.

Set the length x cm, then the width is x - 1 cm.

x(x - 1) = 132

x² -x - 132 = 0

x - 12)(x + 11) = 0

x = 12 (x = -11 rounded).

So x - 1 = 11

Answer: The length of the rectangle is 12 cm and the width is 11 cm.

Solution: If the length is x cm, the width is x - 1 cm.

Available. x(x - 1) = 132

x² -x - 132 = 0

x - 12)(x + 11) = 0

x = 12 (x = -11 rounded).

So x - 1 = 11

Answer: The length of the rectangle is 12 cm and the width is 11 cm.

Solution: Set the width to x

x(x+1)=132

x squared + x = 132 formula.

x + half) = 132 + quarter.

x + half = 529 quarters of the positive and negative root numbers

x + 1/2 = plus or minus 23/23

So x1 = 11 x2 = -12

Depending on the situation, x cannot be rounded off to negative x2.

So, the width of the rectangle is 11 and the length is 12

If the width is x, then the nobunaga is x+1

x(x+1)=132

x-11)(x+12)=132

x=11 so the width is 11, and the imitation Chang is 12 for the grinding chop

Let the length of the rectangle be l and the width be w, then according to the meaning of the problem, two equations can be listed

l = w + 1 (the length of the rectangle is 1 cm more than the width).

l w = 132 (the area of the rectangle is 132 square centimeters).

Replace the l in the first equation with w+1 and substitute it into the second equation to get:

w+1)×w = 132

After simplifying, we get the quadratic equation:

w^2 + w - 132 = 0

Using the root finding formula, the value of w can be solved:

w = 1 ± 1^2 - 4×1×(-132)))2×1

Since w must be a positive number, take the positive root:

w = 1+528))/2 = 11

Substituting w=11 into the first equation gives l=12

Therefore, the length of this rectangle is 12 centimeters and the width is 11 centimeters.

Area formula for a rectangle: The area of a rectangle is equal to the length multiplied by the width, i.e., s = l w.

How to solve a quadratic equation: In this problem, you can list a quadratic equation and solve the root of the equation by finding the root formula. The general form of a quadratic equation is ax +bx+c=0, where a, b, c are known numbers and x are unknowns.

The formula for finding the root is x = b b -4ac)) 2a, the number of roots depends on the positiveness and negativity of the discriminant d = b -4ac. If d>0, the equation has two real roots; If d=0, the equation has a real root; If d "Mamstein 0, the equation has no real root, but can be represented by imaginary numbers.

How to solve a unary equation: If the length of the rectangle is 1 cm longer than the width, you can list a unary equation l = w + 1, and then solve the unknown quantity by shifting the term and simplifying. The general form of a unitary equation is ax+b=0, where a and b are known numbers and x are unknowns.

Methods for solving equations can be achieved by shifting, simplifying, and canceling out.

Unit Conversion: The unit of area of the rectangle given in the question is the square centimeter of the meter, and it is necessary to pay attention to the conversion relationship with other units. 1 square centimeter is equal to a square meter, or 100 square millimeters.

In mathematics, unit conversion is a common concept, and it is necessary to grasp the conversion relationship between common units.

These knowledge points are relatively basic content in mathematics, and they will often be encountered when learning mathematics. By constantly practicing similar problems, you can improve your math ability and problem-solving skills.

Set, the length is xcm, the width is the fight slippery (x-1) cm, by the uproar of the title.

x(x-1)=132

x=12 or x=-11 (base house).

x-1=11

It is 12cm long and 11cm wide

It is 12cm long and 11cm wide

In this problem, we solve it by using a column equation:

Set, the length is xcm, then the width is (x-1) cm, from the title:

x(x-1)=132

x = 12 or x = -11 (rounded).

x-1=11

So the length is 12cm and the width is 11cm.

Let the width of the rectangle be x, then the long clear spike is x+1, and x(x+1)=132 x 2+x-132=0 (x-11)(x+12)=0 according to the title

Solution: x1 = 11 x2 = -12 (abandoned) Answer: No.

So the length of the rectangle is 12 and the width is 11

Let the length of the rectangle be a

a×（a－1）＝132

The solution is a = 12cm

a×（a－1）=132

a^2-a-132=0

Just like this, Yu Xiao holds the list, the topic is to list the equations carefully, and there is no such thing as finding it, and there is no vertical form of a quadratic equation when it is found.

Analysis: The length and width can be found by decomposing the prime factors.

231 = 1 231 Length is 231 cm, width is 1 cm Circumference: 231 2 + 1 2 = 464 (cm).

231 = 3 77 Length is 77 cm, width is 3 cm Circumference: 77 2 + 3 2 = 160 (cm).

231 = 7 33 The length is 77 cm, the width is 3 cm Circumference: 33 2 + 7 2 = 80 (cm).

231 = 11 21 Length is 21 cm, width is 11 cm Circumference: 21 2 + 11 2 = 64 (cm).

Overall comparison: the maximum circumference of this rectangle is 464 cm.

Decompose 231 into prime factor = 3 7 11

The length and width of this rectangle can be as follows:

1. Length 3 7 = 21cm, width 11cm;

2. Length 3 11 = 33cm, width 7cm;

3. Length 7 11 = 77cm, width 3cm

Decompose the prime factors first, and get 132 = 1x132 = 2x66 = ....= 11x12, it was found that only 11x12 met the requirements and the length was 1cm wider than the fight, so the length of the rectangular base was 12cm, and the width was 11cm

So x*(x+1)=132

Therefore, the answer tells x=11, so the length of the rectangle is 12 meters for the pin, and the width is x meters.

Wangqi is satisfied, the width is 11 meters, because the area is 132, the length is x+1 meter.