What is the Shiva Radius? Big Brother Rush 5

When a black hole is formed, all matter collapses toward the center into a very small mass called the singularity, and the surface layer of the black hole is called the event dome.

The distance between this surface layer and the central singularity is the Swa-radius. For any matter to travel outside the Shiva radius of a black hole, it will have to escape faster than the speed of light.

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It's actually quite simple:

rs = 2gm c2, where m is the mass of the object, g is the gravitational constant (g = minus eleven square m3 kg*s2), and c is the speed of light. (in meters, seconds).

Knockdown process: the escape velocity is V> root number (2gm r), g is the mass, m is the mass, and r is the radius, which can be expressed by density as:

v > root number (8 g r2 3), = m v, v is the volume.

If the escape speed of an object is greater than the speed of light, it will become a black hole, and no object will leave it, there are two kinds of black holes, one is the Schwarzschild black hole, which does not rotate and is not charged; The other is a Kerr black hole, which rotates faster than a pulsar.

Schwarzschild black holes have one event horizon, while Kerr black holes have two.

Is there any direct evidence for people to imagine it, on the first floor, do people have direct evidence of the structure of black holes?

01 Schwarzschild radius is a critical radius eigenvalue that exists for any substance with mass. It is a very important concept in physics and astronomy, especially in the theory of universal gravity and general relativity.

02 The Schwarzschild radius was first discovered in 1916 by Karl Schwarzschild who discovered that the radius is an exact solution to the gravitational field of a spherically symmetrical, non-rotating object.

03 The Schwarzschild radius of an object is directly proportional to its mass. The Schwarzschild radius is about 3 km, while the Schwarzschild radius of the Earth is only 9 mm.

04 The sphere formed by the Schwarzschild radius forms a horizon. (The situation is slightly different for rotating black holes.) Neither light nor particles can escape the sphere. The Schwarzschild radius of the supermassive black hole at the center of the Milky Way is about 7.8 million kilometers.

Schwarzschild radius is: a critical radius eigenvalue that exists for any substance with mass.

The formula for Schwarzschild Radius is actually derived from the formula for the escape velocity of an object. The implication of this value is that if a particular mass of matter is compressed within that radius value, there will be no known type of force that can prevent the matter from compressing itself into a singularity by its own gravity.

It sets the escape velocity of an object to the speed of light, and by combining the gravitational constant and the mass of the celestial body, its Schwarzschild radius can be obtained.

The Schwarzschild radius of a celestial body is calculated according to the formula for calculating the escape velocity of the celestial body (v1).

v1=√（2gm/r）

v1 refers to the escape velocity of the celestial body, g is the gravitational constant, m is the mass of the celestial body, and r is the distance between the centroid of the celestial object and the center of gravity of the attracted object. If an object cannot exceed the escape velocity of a celestial body, it cannot get rid of its restraints, and will be attracted by the celestial body, and cannot escape from orbit.

Derivation process: by the gravitational formula:

Newton's second law: Here a is g

Easy to obtain. The formula aWill.

Substitution. and h=r thus.

Epitope energy. b.The velocity of the matter attracted by the star corresponds to the potential energy to obtain the critical radius rs (Schwarzschild radius).

Do the Lorentz transform.

Thereinto. Get.

When v=c finds the critical straight of r.

When v is greater than or equal to c (c is the speed of light), light cannot escape the gravitational pull of the celestial body, and even light can only enter and cannot exit. then the full formula is available.

The Schwarzschild radius of a celestial body is the value of r when the escape velocity is equal to the speed of light. So rs=2gm c 2 (rs is the Schwarzschild radius of the celestial body).

Finally, to summarize the formula:

rs=2gm/c^2

rs is the Schwarzschild radius of the celestial body, g is the gravitational constant, m is the mass of the celestial body, and c is the speed of light.

Text version: The Schwarzschild radius of a celestial body is equal to the gravitational constant multiplied by the mass of the celestial body multiplied by two and divided by the square of the speed of light.