A project A, B and C are done separately, each taking 24 days, 20 days, and 30 days.

Solution: For this project, it takes 24 days, 20 days, and 30 days for A, B, and C to do it separately.

Then A, B, and C complete 30 of the total works every day

Therefore, A, B, and C can work together to complete the total project in one day (1 24 + 1 20 + 1 30) = 1 8

Therefore, the joint completion of this project A, B, and C requires: 1 (1 8) = 8 (days).

In 8 days, A did 8 * 1 24 = 1 3 of the amount of work, so A's contract fee should be: 24000 * 1 3 = 8000 (yuan).

In 8 days, B did 8 * 1 20 = 2 5, so A's contract fee should be: 24000 * 2 5 = 9600 (yuan).

In 8 days, C has done 8 * 1 30 = 4 15, so A's contract fee should be: 24000 * 4 15 = 6400 (yuan).

Answer: The contracting fees of teams A, B and C are: 8,000 yuan, 9,600 yuan and 6,400 yuan.

Set A, B, and C to do x days each.

x（1/24+1/20+1/30）=1

x=8A: 8 1 24=1 3 24000 1 3=8000 yuan.

B: 8 1 20 = 2 5 24000 2 5 = 9600 yuan.

C: 8 1 30 = 4 15 24000 4 15 = 6400 yuan.

The work efficiency of A, B and C is 1 24, 1 20, 1 30, and the work efficiency of three-person cooperation is: 1 8

It takes 8 days for the three to work together.

The total project cost is 24,000 yuan.

A: 24000*1 24*8=8000

B: 24000*1 20*8=9600

C: 24000*1 30*8=6400

Time is certain, and the ratio of the amount of work completed by team A, B and C is the ratio of the work efficiency of team A, B and C.

Therefore, the ratio of the amount of work completed by team A, B and C = (1 24) :( 1 20) :(1 30) = 5:6:4

A24000*5 (5+6+4)=8000 yuan.

B 24000*6 (5+6+4)=9600 yuan.

C24000*4 (5+6+4)=6400 yuan.

Time = total amount of work Sum of efficacy.

5 (days) Congratulations: 5 days, 2, 3 4 (1 20 + 1 30 + 1 15) = 5 days, 2, time = total amount of work Efficacy and.

3 4 2 Zen Rough 20

5 (days) Answer: 5 days, 1, a project, A alone to do 20 days to complete, B alone to do 30 days to complete, C alone to do 15 days to complete, how many days can the three teams to complete the project 3 4?

After 5 days, A is left with 1-5 20=3 4

The remaining A, B and C cooperation still needs 3 4 (1 20 + 1 24 + 1 30) Kai bend = 6 days.

So when the finger is finished, A does all (5+6) 20=11 20 B does all 6 24=1 4

C does all 6 30 = 1 5

Therefore, A gets 6000 11 20 = 3300 yuan.

B gets 6000 1 4 = 1500 yuan.

C gets 6000 1 5 = 1200 yuan.

1/36+1/30=11/180

C is 1 48 per day, so let the number of days A and B work together is x, and the number of days C works is y x>=y

11 180*x+y 48=1 Then find the integer solution.

There is only one set of integer solutions, y=4 x=15. C. Number of days off = x-y = 11

Let B be x days, then C is x - 3 days.

14 40+(14-x) 30+(14-x+3) 24=1 multiplied by 120

42+4（14-x）+5(17-x)=12042+56-4x+85-5x=120

9x=183-120

9x=63x=7

Let B leave x days halfway, then C leaves x 3 days, A does 1 40 per day alone, B does 1 30 per day alone, C does 1 24 per day alone, A does 14 days, B does 14-x, and C does 14-(x-3)=17-x

1 40*14+1 30*(14-x)+1 24*(17-x)=1 multiplied by 120 on both sides

3*14+4*(14-x)+5*(17-x)=12042+56-4x+85-5x=120

4x-5x=120-42-56-85

9x=-63

x=7 so B leaves for 7 days.

Let B leave for x days.

A did it for 14 days, B for (14-x) days, and C for (17-x) days.

14/40+(14-x)/30+(17-x)/24=1x=7

Team A completes in 20 days, which means that Team A completes 1/20 in 1 day.

Team B completed in 30 days, indicating that Team B completed 30/1 in 1 day.

Team C completed in 40 days, indicating that Team C completed 1/40 in 1 day.

A and B cooperate, one day to complete 2/20 + 1/30 = 5/60 = 1/12. 1/12 a day, which means that it can be completed in 12 days.

A and C cooperation, one day to complete 20 + 1 40 = 3 40, that is, 3 out of 40 days can be completed. 40/3<15 is also available.

B and C are known as slow work, one day to complete one-30th + one-40th = 7/120, that is, 7-ths of the Qinghuai mold can be completed in 120 days. But 120/7 of a day is 15 days, so it can't be done in 15 days.

A, B and C cooperate, 13/120 can be completed in one day, that is, 120/13 can be completed, 120/13 < 15 days, so it can also be.

Therefore, the cooperation of A and B, the cooperation of A and C, and the cooperation of A, B and C can be completed in 15 days, but B can not cooperate with C.

As you can tell from the title.

The amount of A doing for two days = the amount for B doing four days.

A's velocity = 2 times B's velocity.

A does it for 10 days first, and B does it for 24 days, so A does it for 10 days, and then it can be completed after 12 days.

A alone can be completed in 22 days.

Because A's velocity = 2 times B's velocity.

then B alone can be completed in 44 days.

If my is helpful to you, please choose it as a satisfactory answer in time, thank you

Suppose A works alone and takes x days to complete, then A does 1 x of the project every day.

1-10/x）/24=(1-12/x )/20

x=22 (1-10 22) 24=1 44 1 1 44=44, so it takes 22 days for A to work alone, and 44 days for B to work alone.

A do. 12 10 2 (day).

B needs to do it. 24 20 4 (day).

A alone is required to complete the completion.

10 24 4 2 22 (days).

B alone does the completion of the need.

24 10 2 4 44 (day).

Let A and B do m days, and B does n days, then you can get the equation m 36 + m 30 + n 48 = 1, and after finishing it you can get 44m + 15n = 720, because m and n are integers, and 720 and 15n can be divisible by Zen cave 15, then 44m must be divisible by good brother 15 to ensure that mn is a positive integer, so friendly attack m must be a multiple of 15, and m 16, then m = 15, and n = 4.

Let C rest for x days, then according to the question (1+x 48) (1 30+1 36+1 48)=integer, from this equation can be calculated (x+48) 48 59 720=(x+48) 48 720 59, this equation in the fraction situation 48+x to 59 about the whole bucket of missing numbers, 48 and 720 divide to get the integer (15), but 59 is a prime number, so 48 + x must be a multiple of 59, so in line with the unprecedented debate of the topic there is only one answer x=11

1+x 48) (1 30+1 36+1 48) = integer, the result of this equation is (48+x) 48 720 59 = integer, in this equation 48 and 720 are approximately divided into 15 1, 48+x) to be divided with 59, since 59 is a prime number, so 48+x can only be a multiple of 59 to get the imitation only integer, closed.

As a result, only one x=11 was prepared

For a project, A completes it in 15 days alone, B does it in 20 days, and C does it alone in 30 days. If A and B cooperate, how many days can this project be completed?

1 (1 15 + 1 20) = 60 7 days.

If A and C cooperate, two-thirds of the project can be completed in a few days?

2 3 (1 15 + 1 30) = 20 3 daysAfter 5 days of cooperation between A and B, how many days does it take for the remaining C to do it alone?

1-(1 15+1 20) 5] 1 30=25 2 days.

solution, let the total workload be 1, then the work efficiency of A is 1 15, B is 1 20, and C is 1 30

Then 1 (1 15+1 20)=60 7