How can these mathematical ideas be done with unary equations?

2x-1｜＋｜x+3｜=16

When 2x-1 =2x-1 x+3 =x+3.

2x-1｜＋｜x+3｜=16

2x-1+x+3=16

3x=14x=3/14

List the 4 types of positive, positive and negative, negative positive, and negative negative.

1. Segmented discussion.

When x<-3, 1-2x-x-3=16 3x=-18 x=-6, when -3<=x<1 2, 1-2x+x+3=16 x=-12 rounds.

When x>=1 2, 2x-1+x+3=16 3x=14, x=14 3So, x=-6 or 14 3

2. Shejia traveled x kilometers.

x+4x/3=70*5

7x/3=350

x = 150 km.

A 150 km, B 350-150 = 200 km.

1. Segmented discussion.

When x<-3, 1-2x-x-3=16 3x=-18 x=-6, when -3<=x<1 2, 1-2x+x+3=16 x=-12 rounds.

When x>=1 2, 2x-1+x+3=16 3x=14, x=14 3So, x=-6 or 14 3

2. Shejia traveled x kilometers.

x+4x/3=70*5

7x/3=350

x = 150 km.

A 150 km, B 350-150 = 200 km.

Standard form. The standard form of a univariate equation (i.e., the form in which all unary equations can be collated together) is ax+b=0 (a, b is constant, x is unknown, and a≠0).where a is the coefficient of an unknown, b is a constant, and x is an unknown.

Unknowns are generally set to x, y, z

Equation features. (1) The equation is an integer equation.

2) The equation has one and only one unknown.

3) The highest number of unknowns in this equation is 1

The equation that satisfies the above three points is a one-dimensional equation.

Judgment method. To determine whether an equation is a univariate equation, first look at whether it is an integral equation. If so, sort it out.

If it can be organized in the form ax+b=0(a≠0), then the equation is a univariate equation. There should be an equal sign in it, and there should be no unknown number in the denominator.

Deformation formula. ax=b (a, b is constant, x is unknown, and a≠0). Usual solution.

Remove denominator Remove parentheses Shift terms Merge similar terms The coefficient is reduced to 1

1 Student x person Adult 12-x 35x 2+35(12-x)=350 x=4 2 16 times 35 times equals 336

Set the time of the encounter to be x hours.

160+140)x=4500

x = 15 This little bird flew 15 300 = 4500 km

The little bird flew x kilometers.

x/300=4500/(140+160)

x=4500

Detailed answers.

1.This problem is more suitable for solving a system of binary equations;

2.One of the difficulties: the number of people available in one restaurant is unknown, and the number of people available in another restaurant is not well represented;

3.Difficulty 2: According to which equivalence relation series equation, in fact, the equivalence relationship is still very clear, there are two 1680 and 2280;

4.When solving equations, it is not particularly simple, and it is easy to make mistakes;

5.Look at the whole problem, ponder and ponder, and check whether the solution of the equation is correct;

6.Do it yourself!

4x-2m=3x-1

4x-3x=2m-1

x=2m-1

x=2x-3m

x-2x=-3m

The solution of the equation x=3mx, 4x-2m=3x-1, is twice the solution of the senfu source of the equation x=2x-3m.

2m-1=2*3m

4m=1m=1/4

I didn't listen to the lecture in class, it's just to move the item, and the one on the left is x=2m-1; The one on the right is x=3m; That is, 2m-1=2*3m, that is, m=-1 4.

The solution of the equation 4x-2m=3x-1 about x is twice the solution of the equation x=2x-3m.

4x-2m=3x-1

4x-3x=2m-1

x=2m-1

x=2x-3m

x-2x=-3m

The solution of the equation x=3mx, 4x-2m=3x-1, is twice the solution of the equation x=2x-3m, and 2m-1=2*3m

4m=1m=1/4

Scheme 1: 2 2+(10-2) 2 RMB;

Option 2: 10 2 RMB; Option 2 is cost-effective.

Solution: The two options of buying x balls have the same amount of money; 2×2+（x-2）×2×

solution, x=6

Set to buy y balls2×2+（y-2）×2× >0Solution, y < 6; That is, when the purchase quantity is less than 6, option 1 is cost-effective; When equal to 6, the same; If it is greater than 6, option 2 is cost-effective