A math problem solved with a one dimensional equation .

Solution: Suppose the car has been driving on an ordinary highway for x hours, then.

60x：100（：2

x=1A: The car has been driving on a normal highway for 1 hour.

Solution: If an ordinary highway is x kilometers long, then the highway is 2 kilometers long.

x/60+2x/100=

Solution: x=60, then 2x=120

So the highway is 120 kilometers and the ordinary road is 60 kilometers.

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x Ordinary time.

2*60x=100(

120x=220-100x

220x=220

x = 1 hour on ordinary roads, 1 hour on highways.

The length of ordinary roads is 60 km, and the length of highways is 120 km.

Ordinary roads are x km and expressways are 2x km.

x/60+2x/100=

5x+6x=660

11x=660

x = 60 It is known that the length of ordinary roads is 60km, and the time is 60 60 = 1 hour.

A: The car drove on the ordinary road for 1 hour.

The time on the high speed was x ordinarily 202-x

There are two ways to solve it yourself and add it upstairs.

It is located on ordinary highways for h hours.

100*（ 2*60*h

200-100h = 120hh=1

x*60*2=( Suppose the car has been on a normal highway for x hours.

Find the distance traveled on an ordinary highway and divide the distance by the speed according to the time equals....

Solution: The car set up drove for a total of x hours.

x=25/60+(360-25/60*72)/(72+48)+100/(72+48)

Solution x = 4 hours.

A: The car drove for a total of 4 hours.

The car traveled for a total of x hours.

x=25/60+(360-25/60*72)/(72+48)+100/(72+48)

x = 4 hours.

On a calendar, the sum of three adjacent numbers on a vertical column is 30, and if the middle number is x, then the other two numbers can be expressed as --- equation --- according to the title

Solution: Set the annual interest rate to x.

3000+3×3000x=3243

x = A: The annual interest rate is.

If factory A actually produces x tons and plant B produces 4000-x tons, then A plans to produce x 112%, and B plans to produce (4000-x) 110%, so x 112% + (4000-x) 110% = 4000-400x = 2240

Therefore, the original production task of factory A was 2240 112% = 2000 tons.

Let the velocity of A be x km/h, then the velocity of B is x+1 kmh, and the equation is according to the meaning of the problem

2x+（x+x+1）×10=120

That is, 2x+20x+10=120

i.e. 22x = 110

x = 5 (kilometer hours).

Then B's velocity is: 5+1=6 (km/h).

Hello Hani, Hello:

Directly let the distance between the two villages of A and B be x kilometers, then the time used by Xiaohong is x 4, and the time used by Xiaolin is x 5+, and the time is equal, so there is x 4 = x 5 + 1 + 1 4, and the solution is x = 25, answer: The distance between the two villages of A and B is 25 kilometers.

Set the distance between the two places is xkm

Because the two people set off at the same time and arrive at the same time, the total time taken is equal, and the equation is:

x 4 = solution x = 25km

Let the distance between the two villages be x

As the time taken is the same.

x=15

(1)(64+126) a=950, a=50(2) with carton packing x boxes and woven bags packed with y bags, then 64x+126y=7280;8x+18y=1000 solution x=35;y= 40 Assuming that it can be achieved, the rest is the same as above, then; 64x+126y=7280； 8（x+b)+18y=1000；This is a linear programming problem, and the key to solving the problem is rounding, because x, y, and b are all positive integers. You see, the objective function b=(1000-18y) 8-x linear constraint is 64x+126y=7280; x>=0; y>=0;x,y n in a Cartesian coordinate system, you can do it. ps：

I don't know if you've studied linear programming, but if not, this problem is a bit out of the ordinary, because its variables are three, and it's not a matter of solving equations, but an optimal selection idea.

Solution: (1) From the meaning of the question, 64a+126a=950, solution: a=5, answer:

The value of a is minutes (2) set the carton to pack x boxes, then the woven bag is packed to pack y bags, from the title, 8x+18y 100064x+126y 7280, solution: x 35y 40 Answer: 35 boxes are packed in the carton From 8x+18y=1000, you can get x 1000 18y8 125 9y4, from the title, 64 (125-9y4-b)+126y=7280, solution:

y=40-32b9, x,y,b are all integers, and x 0,y 0,b 0, b=9,x=107,y=8, the value of b is 9 Answer: The value of b is 9

(64+126)a=950,a=5 Don't know. That's all I know so far. I have limited abilities (o Ahh

The purchase price is set to be x, x(1+80%)=360x=200

It can be reduced by up to 120 yuan.

Let the purchase price be x, then, x=200, that is, the purchase price is 200 yuan.

The minimum selling price is 240 yuan, and the store owner can reduce the price by up to 120 yuan.

It's easier to solve this problem directly, but let's just list the equations

Set down x yuan, the same amount is the original price.

360 (1+80%)=(360-x) (1+20%), which gives x=120

Person. 2, k = 3 grinding 14

3、a=2,1,0,-1,-2,-3,..

4、a=2/3

km Object travel annihilation cover rush h

20/（1/20+1/12）=6h

1.Let the profit x, according to the meaning of the question, there is 280 + x = 280 * (1 + 25%) * solution x = profit yuan.

2.Profit margin ** (p+10)%-p%=, profit margin = selling price purchase price - 1, because the purchase price is reduced by 8% and the selling price remains the same, so the selling price purchase price - selling price purchase price = set selling price purchase price = k, that is, there is k - k =, the solution k = then the original profit margin is, then p = 15

3.There were originally x students in the math interest group, and it should be noted that the second transfer did not transfer out the girls, so the number of girls left after the second transfer was 1 more than the first one. According to the meaning of the question, 1 7 (x-1)=1 5 (x-2)-1, and the solution is x=22, that is, there are 22 students.

4.This question is an inequality question. And it should be sold for 30

Set the original price to x, 88% off the sale according to the title of 30*. Solution x 24.

10% off sales according to the title has 30*. So the original price of the product is between yuan.

1. Solution: Set a profit of x yuan.

280*(1+25%)*85%=280+x gives x=yuan2,

1, x=280x(1+25%)x85%-280=yuan2, let the purchase price be x or 1, get x(1+p%)=x(1-8%)(1+(p+10)%) to get p=15

3,1 7(x-1)+1=1 5(x-2), get x=224, x*88%>=30x(1+10%), get x>=, x*90%<30x(1+20%), get x<40, so <=x<40