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1.Excess iron filings are added to the mixture solution of FeCl3 and CuCl2, and after the reaction is stopped, the solids are weighed to be equal to the mass of the added iron filings. What is the ratio of the amount of FeCl3 and CuCl2 in the solution of the original mixture?
a.1:1 b. 3:4 c. 2:7 d. 7:2
2.500ml, 1mol L FeCl3 solution, add iron powder to complete the reaction, remove the excess iron powder and add a sufficient amount of NaOH solution, what is the amount of precipitated substance?
a. b. 1mol c. d.Not sure.
3.There is a kind of iron"Oxides"The sample is completely dissolved with 5mol L of hydrochloric acid 140ml, and the resulting solution can also absorb chlorine under standard conditions, which happens to convert all Fe2+ into Fe3+.
a. fe2o3 b. fe3o4 c. fe4o5 d. fe5o7
4.In a mixture of 2 L of Fe2(SO4)3 and CuSO4, 30 g of pure iron powder was added, and finally 2 L of Feso4 solution and 26 g of solid precipitate were obtained. Find the amount and concentration of Fe2(SO4)3 and CuSO4 in the original mixture.
11 volume of H, oxygen o gas 5 volume 1 volume ci EDM Exactly the reaction to find the solution of the solute mass molecule number?
In the two beakers A and B, each containing 100ml of substance at a concentration of 3mol?l of hydrochloric acid and NaOH solution, the same mass of aluminum powder was added to the AB beaker, and the volume ratio of hydrogen produced after the reaction was measured to be va:vb 1:
2. What is the quality of aluminum powder? (Va and vb denote the volume of hydrogen produced by the A and B beaker reactions, respectively.) )
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Do all the chemistry problems here and you'll be a genius.
The condition is to do it right.
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The mixture of m grams of carbon dioxide, carbon monoxide and methane was introduced into a sufficient amount of Na2O2 to ignite the complete reaction with an electric spark, and the solid weight was increased to m grams, and the volume ratio of carbon dioxide and methane was obtained.
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Question 1:
A F are hydrogen H2 (flammable), oxygen O2 (flammable), helium HE (non-flammable, non-combustible), carbon monoxide, CO (combustible), carbon dioxide, CO2 (non-flammable), and methane, CH4 (combustible).
There are three types of flammable gases: hydrogen H2, carbon monoxide CO, and methane CH4, which are burned in oxygen to produce water.
Carbon monoxide is burned in oxygen to produce carbon dioxide.
Methane is burned in oxygen to produce water and carbon dioxide.
So b must be oxygen and f is carbon dioxide.
C and D are carbon monoxide and methane, and the mass ratio of the two elements in C is 3:1, so C is methane CH4D is carbon monoxide.
A reacts with carbon monoxide to produce methane and water, so there must be hydrogen in A, so A is H2 Answer: Co; he;co2;2H2 + O2 = Ignition = 2H2O; CH4 + 2O2 = ignition = CO2 + 2H2O
Question 2: Because the gas is passed through the clarified lime water, there is no turbidity, so the original gas does not contain CO2 (= = please ignore this analysis, none of the seven options contain CO2).
Because of the small water droplets, the white film is formed, and it is known that the products of combustion are water vapor and carbon dioxide.
Option: The combustion products are H2O and CO2, which is in line with the topicOption: The combustion products are CO2, which does not meet the topic.
Option: The combustion product is H2O, which does not fit the topic.
Option: The combustion products are H2O and CO2, which corresponds to the topicOption: The combustion products are H2O and CO2, which is in line with the topic Option:
The combustion products are H2O and CO2, which are in line with the question Option: There are three gases, and the question says that it consists of one or two gases, which does not fit the question so the answer is
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I really can't see clearly, and I can't help if I want to
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