In high school biology, the second question is analyzed, and the second high school biology question

Anaerobic respiration is not the most suitable for storing plants. The release of CO2 in B is about 8O2, and the absorption is about 4, that is, the ratio of CO2 produced by anaerobic respiration to aerobic respiration is 1:1.

aCorrect, it should be stored in an oxygen-deprived environment.

B error, not to 5 times. A glucose releases 2 or 6CO2, and you can know it by dividing it, probably: 3

C is false, stronger than D.

d error, fully aerobic respiration. Aerobic respiration C6H12O6 + 6O2 6H20 6CO2 + 12H2O oxygen uptake is equal to carbon dioxide emissions.

The second data is not clear.

aThere should be no oxygen absorption, only anaerobic respiration, which will produce alcohol, which is not suitable for storage.

b Mark the data in the figure and send it to me, which can be calculated by the formula of aerobic and anaerobic respiration.

At this time, the oxygen absorption is more than the carbon dioxide emittion, and there is anaerobic respiration, and there is no anaerobic respiration in d, so c is not the weakest.

DD is aerobic respiration only.

The emission of BB and CO2 is about 8, and the absorption of O2 is about 3

A false: The degree of anaerobic respiration is the largest.

bWrong reading the equation.

CD mistakes you will know by writing equations.

b and d satisfy a 3-to-1 relationship, you look at the equation.

It should be incorrect is ACD

a If y indicates glucagon, the activity of the cell at the blood glucose concentration (too low) is enhancedb If y indicates antibodies, the cell is proliferated and differentiated from B cells or memory cells, correct c If y indicates gonadotropin, the cell is mainly present in the (pituitary) d If y indicates growth hormone, then the cell is a secretory cell in the (pituitary) pituitary gland secretes growth hormone and various hormones (thyroid-stimulating hormone, adrenocorticotropic hormone, gonadotropin).

Leak Troubles Pairing a=t c=g

A is correct, a on one chain is another chain t

b is correct in the search of the ante, a chain g c = 2On the other chain, it is c g=2, which is also known as g c=

c is wrong, the other chain is t:a:g:c=1:2:3:4, then a:t:c:g=2:1:4:3

d is correct, and the other chain is c:a=

c is wrong, explained as follows:

There are 2 types of DNA base pairs: A is paired with T, and C is paired with G, i.e., the number of A on one strand is equal to the number of T on the other strand, and the number of C on one strand is equal to the number of G on the other strand.

c selects the hand item and says: If a chain is a:t:

c：g=1：2：

3:4, then A on the other chain should be equal to the number of T on the chain, the number of T should be equal to the number of A on the chain, the number of C should be equal to the number of G on the chain, and the number of G should be equal to the number of C on the chain, so:

a：t：c：g=2：1：4：3，。

Choose A. The probability of getting normal (aa) is 1 4, and the probability of having a boy is 1 2, so 1 4 times 1 2 is 1 8

A dominant genetic disease is selected, the causative genotype is AA or AA, and the normal genotype is AA. The probability of the offspring being aa is 1 4, and the probability of giving birth to a boy is 1 2, so the probability of giving birth to a normal boy is 1 4 * 1 2 = 1 8

Solution: a. Measles virus attenuated vaccine is a macromolecular substance, which belongs to antigens, and the antigenic determinants on its surface can be recognized by immune cells, so a is wrong;

b. After the initial vaccination of the vaccine, both specific immune cell immunity and humoral immunity play a role, which can produce effector T cells and antibodies, so B is correct;

c. After re-vaccination with the vaccine, memory cells rapidly differentiate to form effector B cells and produce a large number of antibodies, so C is wrong;

d. The invading measles virus is bound by antibodies and loses its pathogenic ability, and is engulfed and digested by phagocytic cells, so D is wrong

Therefore, b

The mistake in choosing B A is that the vaccine is an inactivated virus, not a small molecule substance; c The fault is that plasma cells release lymphokines, plasma cells can only secrete and synthesize antibodies, but cannot release lymphokines, and it is T cells that release lymphokines; D Answer: T cells cannot engulf the digestive virus, and it is macrophages that engulf the digestive virus. Hope to adopt.

T agrees upstairs, choose B, A option inactivated virus is a protein shell, belongs to a macromolecule, the explanation of CD upstairs is clearer.