Find a 5th grade math problem. Remember to write down the detailed process.

The class has 50 students.

Calculation process: 1 Calculate the undercount of the score: 96 69 27 points.

2 Calculate the average score difference: 85 77 85 23 0 54 points.

3 The total score undercounted is divided by the average score of the undercounted total class size.

That is, 27 divided by 0 54 equals 50 people

The equation is (96 69) (85 77 85 23) 50 (person)Answer: There are 50 students in this class

Of course, after the fifth grade, it is more convenient to calculate algebraically.

Set: There are x people in the class.

27=x=27÷

x=50A: There are 50 students in this class.

Solution: There are x students in this class.

x=50A: There are 50 students in this class.

There are x students in this class.

27=x=50A: There are 50 students in this class.

On average, there are 3 of the 6 monkeys left, which can also be understood as 3 less, which becomes a typical profit and loss problem.

Monkeys (2+3) (6-5) = 5.

Peaches 5 * 5 + 2 = 27 pcs.

Answer: 2 2 5 = 20

We know that one side is painted red in the middle of each face, three faces are painted red on the corners, and two faces are painted red on the edges. There are exactly 12 small cuboids painted red on two sides, and there are many cases 2 3 4 = 24, 3 3 3 = 27, 2 2 5 = 20.

Divide into at least 20.

12 12 1 (12 ribs).

1 1 1 3 (3 on each edge).

3 3 3 27 pcs.

The class has 50 students.

Calculation process: 1 Calculate the undercount of the score: 96 69 27 points.

2 Calculate the average score difference: 85 77 85 23 0 54 points.

3 The total score undercounted is divided by the average score of the undercounted total class size.

That is, 27 divided by 0 54 equals 50 people

The equation is (96 69) (85 77 85 23) 50 (person)Answer: There are 50 students in this class

Of course, after the fifth grade, it is more convenient to calculate algebraically.

There are 30 days in September, so there is an interval of 30 days between October 1 and September 1.

So October 1 is Wednesday + 2 = Friday.

30/7=4……2 (days).

A: October 1 is a Friday.

Friday. There are 30 days from September 1st to October 1st. There are seven days in a week. Thirty divided by seven equals four and two remains. Wednesday is two days back, and it's Friday.

The time of the encounter is:

30+30) (50-40)=6 (hours)

6x(50+40)=540 (km).

Use equations to solve it.

Let the total distance be x, because the speed of car A is faster, then.

x/2+30)/50=(x/2)/40

So, x=240

Solution: Let A and B travel for t hours to meet, and the question can be obtained:

50t-30=40t+30solvable t=6

The distance between abs is: (40*6+30)*2=540km

First of all, divide the 48 people into eight groups, six people in each group, the first seven groups buy 5 bottles for one bottle each, the remaining seven empty bottles, then one bottle, the remaining two empty bottles, the eighth group buys four bottles, plus the previous one bottle, a total of five bottles, drink it, and then change the bottle, so that each person drinks one bottle, and there are three empty bottles left.

The number of soda bought with money is 5 7 + 4 = 39 (bottles).

Spend at least $39.

Buy at least x bottles of soda.

x+x/5=48

Solution x=40

A: Spend at least 60 yuan to get a bottle of soda for everyone.

Solution: Buy at least x bottles of soda.

x+x/5=48

Solution x=40

A: Spend at least 60 yuan to get a bottle of soda for everyone.

From the meaning of the title, five empty bottles are exchanged for one bottle of soda, that is, 6 students only need to buy five bottles of soda, that is, 6 people spend yuan, 48 6 = 8, yuan.

Buy at least x bottles of soda.

x+(x 5)=48 gives x=40

At least 60 yuan can make everyone drink a bottle of soda.