Middle School Mathematics Finding Explanations for Fractional Equations Help

Updated on educate 2024-04-10
14 answers
  1. Anonymous users2024-02-07

    Solution: If the walking speed is x, the bicycle speed is 4x

    According to the title, 7 x + (19-7) 4 x = 2

    7+12/4=2x

    x=5 km.

    Answer: Slightly.

  2. Anonymous users2024-02-06

    If you can walk at a speed of x kilometers per hour, then you can ride a bicycle at a speed of 4 kilometers per hour! The distance traveled by the bicycle is (19 7) kilometers, and according to the question: 7 x (19 7) 4 x 2, and the solution is x 5 4 x 20, so the speed of walking is 5 kilometers per hour, and the speed of cycling is 20 kilometers per hour.

  3. Anonymous users2024-02-05

    Let the walking speed be x km h, then the bicycle speed is 4x km h x 7 + 4x 12 2 Multiply 4x on both sides of the equation to get x=5, so 4x=20 so the walking speed is 5 km h The bicycle speed is 20 km h

  4. Anonymous users2024-02-04

    Let the walking speed be x, then 7 x+12 4x=2, and the solution is: x=5

  5. Anonymous users2024-02-03

    If the walk is x, then the bicycle is 4x 19-7=12

    7 divided by x) + (12 divided by 4x) = 2

  6. Anonymous users2024-02-02

    If the speed of walking is x, the speed of the bicycle is 4x.

    7--- plus --12-- equals 2 solution; x is equal to 5Check, when x is equal to 5, 4x is not 0Then x is equal to 5 and is the original fractional equation.

    x 4x.

  7. Anonymous users2024-02-01

    It can only be said to be a half-pair, first of all, in the process of "multiply both sides by (x-3), get x-3=-2(x-3)" This error may be that you made a mistake (you should get x a=-2 (x-3)).

    And then you have to say it at the end because of X-3≠0

    So x≠3, so (a+6) 3≠3

    Therefore, a≠3 so the value range of a is a -6, and a ≠ 3

  8. Anonymous users2024-01-31

    No, make sure that the numerator is not 0, i.e. x≠3

    That is, (a+6) 3≠3 gives a≠3

    In summary, a -6 and a ≠3

  9. Anonymous users2024-01-30

    1.Assuming that the original plan is to repair x meters per day, then the equation is solved to get x=80

    2.Let A process x pieces per day and B process y pieces per day, then 1200 x-10 = 1200 y, y =, solve the equation to obtain x=40, y=60;

    3.Let A spread x kilometers per week and B spread y kilometers per week, then x+1=y, 18 x-3=18 y solve the equation to get x=2, y=3

  10. Anonymous users2024-01-29

    Set the normal trace key, highway speed, attitude, and block x

    600/x=2*480/(x+45)

    600x+600*45=960x

    360x=600*45

    x=75600 plus 75=8 hours.

  11. Anonymous users2024-01-28

    Put 1 generation into -x square + 3 into the calculation When you encounter a constant, you will bring it, it should be calculated like this, I counted two parts, but I have to sleep.

  12. Anonymous users2024-01-27

    It's very unclear, give you a clear answer.

  13. Anonymous users2024-01-26

    5x=-y-z

    So x 2=(y+z) 2

    So y 2+z 2-x 2=-2yz

    y^2=(x+z)^2

    So z 2+x 2-y 2=-2xz

    z^2=(x+y)^2

    So x 2 + y 2-z 2 = -2xy

    So the original formula =1 (-2yz)+1 (-2xz)+1 (-2xy) =x (-2xyz)+y (-2xyz)+z (-2xyz) =(x+y+z) (-2xyz) =0

    6x/3y=y/2x-5y

    2x^2-5xy-3y^2=0

    x-3y)(2x+y)=0①

    x/3y=6x-15y/x

    x^2-18xy+45y^2=0

    x-3y)(x-15y)=0②

    y/2x-5y=6x-15y/x

    xy=3(2x-5y)^2

    x-3y)(12x-25)=0③

    If both are true, x-3y=0, x=3y

    4x^2-5xy+6y^2)/(x^2-2xy+3y^2)=[4(3y)^2-5*(3y)*y+6y^2]/[(3y)^2-2*(3y)*y+3y^2]

  14. Anonymous users2024-01-25

    1.From the known, x+y=-z, (x+y) 2=z 2, can be reduced to: x 2+y 2-z 2=2xy, the same way is y 2+z 2-x 2=2yz, z 2+x 2-y 2=2xz, the original formula =1 2yz+1 2xz+1 2xy=(x+y+z) 2xyz=0

    2.From the known x=3y, the original formula = [4(3y) 2-5 3y·y+6y 2] [(3y) 2-2 3y·y+3y 2]=9 2

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