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Take any point a on the circle, and a is the diameter n of the diameter m and the perpendicular m (i.e., the circle is divided into four equal parts).
It is assumed that it is divided into four parts: 1, 2, 3, and 4. The other two points A and B can make the triangle abc an acute triangle or a right triangle only in the opposite part (i.e., 1, 3 or 2, 4). It is not difficult to calculate the probability of this.
If the triangle ABC is a right triangle, one of its angles must be right angles, and the probability of right angles is 0.
If the angle c is a right angle, there are n ways to take point A, and point B has been determined (ab is the diameter) and point C has n-2 ways to take it.
There are n(n-1)(n-2) ways to take any three points on a circle.
Then the probability of taking three points and being at right angles is n(n-2) n(n-1)(n-2), and n approaches infinity with a probability of 0.
then the probability of an acute triangle is.
The probability of a right triangle is 0
The probability of an obtuse triangle is .
Actually, there's a good way, please see.
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A triangle has at least two acute angles.
Up to one right angle or one obtuse angle.
Acute angle 18 36 1 2
Right and obtuse angles are 9 36 1 4, respectively
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There is a probability of this... Take the picture out and say it...
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A right triangle has one right angle, two acute angles, and no obtuse angles. A right triangle is a geometric figure, which is a triangle with a right angle angle, and there are two types: ordinary right triangle and isosceles right triangle.
In a right-angled triangle, the two sides adjacent to the right angle are called right-angled edges, and the edges opposite by right-angled angles are called hypotenuses. The sides of a right triangle that are opposite by right angles are also called "chords". If the two right-angled sides are not the same length, the short side is called the "hook" and the long side is called the "strand".
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Triangle. There are only three corners. The sum of the inner angles is 180 degrees. So a triangle can only have one right angle, and the other two can only be acute angles.
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Right triangle with 1 right angle, 2 acute angles, no obtuse angles.
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According to the analysis, it can be seen that
A triangle with an angle that is an acute angle may be an acute triangle, a right triangle, or an obtuse triangle, so a triangle with an acute angle may be an obtuse triangle, which is true;
So the answer is:
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From the analysis, it can be seen that there is a triangle with an acute angle, which may be an obtuse triangle;
So the answer is: true
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Suppose the range of three numbers is (0,l), in the xyz coordinate system, we find a region in this cube of length l, satisfying that x,y,z are blind to form an acute triangle. Then put l to infinity and find the limit.
You might as well set z>x, z>y, then.
The constraint of an obtuse triangle is.
x^2+y^2z
At this time, a conical surface and a plain area are sandwiched.
The integral (dxdydz) integral interval is the above constraint and is all within (0,l). The obtained value must be approximate with l 3 to obtain a constant value. This value does not change when l tends to infinity. So first of all, make sure that the probability of an obtuse triangle is positive.
Then the above is to assume z>x, z>y
Then the actual three sides act as the largest edges and the cluster space are all equal probabilities, so multiplying the value obtained above by 3 is the probability of an acute triangle.
The probability of a right triangle is 0 because it is not a region, but a curve;
The probability of an obtuse triangle is also a positive value.
Finally, add to the probability that the triangle cannot be formed, and the sum of Zheng is exactly 1
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There are at least (2) acute angles and a maximum of (1) right angles (or obtuse angles) in a triangle
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In the triangular collision of a hole, if one angle is obtuse and one angle is acute, then the third angle is acute.
The triangle is three inner pei angles and 180 degrees.
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Determination of right triangles:
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