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At the same power, the high-pressure sodium light has the highest efficiency and the longest life, but the color rendering is the worst
Light source: Luminous effect (lm w), average life (h).
Incandescent 7-18 750-1000
Tungsten halogen lamp 18-25 1500-2000
High pressure mercury lamps 40-60 2500-6000
High-pressure sodium lamp 80-100 12000-24000 Metal halide lamp 80-115 3000-6000 If the color rendering requirements are not high, it is recommended to use high-pressure sodium lamp, NG400
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The so-called brighter is due to the different color rendering and different luminous angles required by different use environments, and it is definitely wrong to only consider the light effect, that is, the lumens per watt.
At least the sodium lamp with the highest light efficiency but the worst color rendering is not possible, and the xenon lamp with a relatively short life but more suitable is generally used.
Mercury lamps are the most unsuitable light source due to their low luminous efficiency, short lifespan and poor color rendering.
The key to reducing glare is the design of the light distribution curve rather than the coating.
You can inquire.
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It is customary to say that the "brightness" of the bulb refers to the amount of luminous flux emitted by the bulb.
Comparison of three 400W gas discharge light fluxes.
Type of light source Model Luminous flux (lm lumens).
High Pressure Mercury Lamp GGY400 20000
High Pressure Sodium Lamp NG400 48000
Metal halide lamp ZLD400 36000
It can be seen that the high-pressure sodium lamp has the highest luminous flux.
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Summary. Twelve lights will be brighter than nine lights because twelve lights have more power than nine lights. The solution to this problem is:
First of all, to determine the power of the lamp, the power of nine lamps and twelve lamps should be the same; Secondly, to determine the current of the lamp, the current of nine lamps and twelve lamps should be the same; Finally, to determine the voltage of the lamp, the voltage of the nine lamps and the twelve lamps should be the same. If all three of the above conditions are met, then twelve lights will be brighter than nine. Because the power of twelve lights is greater than that of nine, twelve lights will be brighter than nine.
Twelve lights will be brighter than nine lights because twelve lights have more power than nine lights. The solution to this problem is: first, to determine the power of the lamp, the power of the nine lamps and the twelve lamps should be the same; Secondly, to determine the current of the lamp, the current of nine lamps and twelve lamps should be the same; Finally, to determine the voltage of the lamp, the voltage of the nine lamps and the twelve lamps should be the same.
If all three of the above are satisfied, then twelve lamps will be brighter than nine. Because the power of twelve lamps is greater than that of nine, twelve lamp bushes will be brighter than nine lights.
Can you elaborate on that a little bit more?
In addition, we can also consider some other factors, such as the type of bulb, the number of bulbs, the size of the bulb, the power of the bulb, the quality of the bulb, and so on. If the bulbs are of the same type, quantity, size, power, and quality, then twelve lamps will be brighter than nine. In addition, we can also consider the environmental factors of the bulb, such as the temperature of the bulb, the humidity of the bulb, the air circulation of the bulb, and so on.
If the bulbs all have the same circumference factors, then twelve lights will be brighter than nine. In conclusion, twelve lights will be brighter than nine lights because they possess more power. However, we also need to consider the type, quantity, size, power, quality, and environmental factors of the bulbs to ensure that twelve lights are brighter than nine.
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The basis for judging the brightness of the bulb is to look at its actual power, the greater the actual power, the brighter the bulb.
Therefore you are right.
There is a question like this: there are two light bulbs A and B, and the rated voltage of A is 220V and the rated power is 25WB has a rated voltage of 220V and a rated power of 100W, ask who is bright in a 220V circuit that connects them in series.
The answer is A, why?Isn't it true that the more power you have, the brighter the bulb?
In this problem, the respective resistance of A and B should be found according to R=U 2 P, so that we can know that RA》rB, and then according to the electric power formula in the series circuit: P=I 2R, because the current is equal everywhere, P is proportional to R, so the actual power of lamp A is greater than the actual power of lamp B, that is, lamp A is brighter. This is still in line with the principle that the actual power is higher, the brighter the bulb.
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The advantages and disadvantages of this approach are as follows:
1. Advantages: The brightness of the lamp can be adjusted by using a power supply of different power. A higher power supply can provide a higher brightness level, while a lower power supply can provide a lower brightness level.
This makes it more flexible to adjust the brightness of the luminaire in different scenarios. Energy can be saved by using a lower power source, as a lower power source typically consumes less power. This helps to reduce energy consumption and electricity bills.
2. Disadvantages: Using a lower power supply may limit the maximum brightness of the lamp. If a luminaire requires a higher brightness level, a lower power supply may not be able to provide enough power to meet the requirements.
Using a higher power supply will increase energy consumption and electricity bills. Although it can provide higher brightness than the Huai Yu, it will also increase the cost of electricity.
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So when choosing this light bulb, is it that the more power its bulb will be, the brighter it will be, I think this question should be divided into several aspects, first of all, you have to choose this type of bulb.
Then the first type is the ordinary bulb, so these are the halogen lamps.
Then the second type is the LED bulb, which is the new type of environmentally friendly bulb.
For LED lights, I think everyone is very familiar with many famous cars, they will choose to use this LED light, whether it is in the day or at night, their brightness is much clearer than this halogen lamp, and the LED light source is white in more cases, so it is very clear when it lights up, even if you turn on the light at night, it will be as bright as the day, but it will also not be very dazzling, after all, there must be a drop of light, its light source is quite soft, after special treatment, basically the damage to the eyes is very low, can effectively protect the eyes。
Finally, compared to these two light sources, then I still prefer LED lights, after all, the more power it is, the brighter it is, and it is much more power-efficient than ordinary bulbs. And to have a floor lamp, its performance is more stable, it illuminates for a longer time, so, in order to reduce the waste of resources, many people will choose LED lights basically do not need to be replaced for six or seven years, and halogen lamps are different.
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I think the more power you have, the more light the bulb will come on. After all, in family life, the lights we use are generally determined by the power to determine whether they are bright or not.
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When choosing a light bulb, it is not that the greater the power, the brighter the bulb, this still has to be distinguished according to the type of light bulb, the greater the power, it can only mean that the voltage consumed is greater, and it does not mean that the bulb will be brighter.
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It is indeed like this, whether it is an incandescent bulb or an LED bulb, as long as it is a powerful bulb, it must be on.
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Yes, the more power you have, the brighter the bulb. When we buy light bulbs, it is best to choose energy-saving lamps, which saves electricity and resources.
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The bulb with high power is not necessarily bright, because the brightness of the bulb is also related to the connected voltage, and the appropriate voltage must be selected.
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It is not that the more powerful the bulb, the brighter it is, the brightness of the bulb is determined by the product of the resistance in the bulb and the current.
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Voltage does not matter, luminous efficiency is mainly based on the ratio of the light emitted by the light source (per unit lumen) to the power consumed when emitting light.
In the traditional light source, the luminous efficiency (an important indicator of the light source) of incandescent lamp and tungsten halogen lamp is 12-24lm w, and the average is 15lm w; The luminous efficiency of high-efficiency fluorescent lamps and HID lamps is 50-120lm w, with an average of about 75lm w. The disadvantage of these light sources is that they convert only a small fraction of the electrical energy into visible light. With the rapid development of LED technology, at the end of 2004, the luminous efficiency of LED white light was only about 60LM W; By the end of 2006, the luminous efficiency of LED white light exceeded 80LMW; So far, the luminous efficiency of LED white light has exceeded 100lm W, and even the most advanced white light LED can reach 130lm W, which is more than double the target at the end of 2004.
Due to the high luminous efficiency and light utilization rate of LED light source, the power consumption of LED lighting products is 1 8 of incandescent bulbs and 1 2 of HID lamps and fluorescent tubes under the same lighting effect.
At present, the most efficient artificial light source is white LED.
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Set the bulbs to have the same power and ask which one is the brightest.
The rated power of the bulb is the same, and if the rated voltage is also the same, its resistance value is also the same; At the same time, it is assumed that the resistance of the bulb does not change with the change of the applied voltage at both ends, and it is set to r, so that the calculation can be analyzed.
At the same time, the power supply voltage is set to uThen the following parallel circuit is r 2r = 2r 3, the total resistance of the loop is r + 2r 3 = 5r3, then the series loop current is i = 3u (5r).
In this case, the power of the top bulb is P1=I R=9U (25R).
The parallel circuit voltage is U1=I 2R 3=2U 5
The power of the bulb on the left is P2=U1 R=4U (25R).
The two bulbs on the right are connected in series, and the voltage on each bulb is half of the voltage of the parallel circuit, i.e. u2=u1 2=u5
In two series bulbs, the power of each bulb is: P3=P4=U2 R=U (25R)
From the results, it can be seen that p1>p2>p3=p4
So, the upper bulb is the brightest, the left bulb is the second, and the two bulbs in series are the darkest.
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The resistance of a bulb with a large power is smaller than that of a bulb with a low power.
Power is the product of voltage and current, p=v*i, according to Ohm's law v=i*r, it can be obtained: p=v 2 r, the smaller the resistance of the electrical appliance, the greater the power. Therefore, under the condition that the power supply voltage remains the same, the current flowing through the bulb with high power is large, and the power consumption is large, so it will naturally be brighter.
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The magnitude of brightness is determined by the power of light.
The actual power of the bulb is higher, the more light power it is, and the brighter the light should be.
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w=ptThe greater the power in the same time, the more work done by electricity, for the lamp, the work done by the current is mainly converted into light energy and a part of the heat energy (internal energy), the more work done by the current, the more light energy converted, and the brighter the lamp....
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In junior high school physics, the brightness is generally considered to be the same, but the actual situation may be somewhat different.
In junior high school, it is generally believed that the brightness of a light bulb is determined by its actual power, but the real reason should be determined by the filament temperature. In this way, even if the actual power of the filament is the same, the heat dissipation of the filament of different specifications of the bulb is different, or the heat dissipation power is different, so that the bulb of different specifications with the same actual power is likely to achieve a stable final temperature that the filament can achieve, so the brightness is different.
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The same, because the brightness of the bulb is determined by its actual power.
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