If you have some rabbits and chickens, you have 40 heads and 134 legs, so how many chickens are ther

This is the so-called chicken-rabbit cage problem. There are 40 heads indicating that the number of chickens and rabbits is 40 and there are 134 legs. Implicit in the title here is that the chicken has two legs and the rabbit has four legs.

So, it can be done in this way. The 40 chickens are all chickens, and there are only 80 legs. Now if you exchange a rabbit for a chicken, you need to add 2 legs, and to add 134-80 = 54 feet, you need to replace 54 2 = 27 (feet).

That is to say, among these 40, there are 40-27 = 13 chickens and 27 rabbits.

The rabbit has 4 legs, the chicken has 2 legs, a total of 40 heads, 134 legs, then the rabbit has 27 legs, 108 legs, and the chicken has 13 legs, 26 legs. A total of 40 heads, 134 legs.

40 legs x 4-134 legs) (4 legs - 2 legs).

26 legs 2 legs.

13 (chickens).

A: There are 13 chickens.

Solution: If there are x chickens, then there are 40-x rabbits.

2x+4（40-x）＝134

2x+160-4x＝134

2x＝26x＝13

A: There are 13 chickens.

There are 13 chickens. Rabbits have:

27 (only) chickens: 40-27 = 13 (only) check:

Meet the requirements of the question. Thank you.

Assuming that all go to chickens, then the legs have 40 2 = 80 (only) 134 - 80 = 54 (only).

54 2 = 27 (only) is the number of rabbits.

40-27=13 (only) is the number of chickens.

Assuming that they are all rabbits, the number of legs is 40 4 = 160 (strips) and 160-134 = 26 (strips).

26 2 = 13 (only).

A: There are 13 chickens.

There are 13 chickens. The problem of chickens and rabbits in the same cage is a problem, which can be done with the "foot lifting method", which is very simple. First of all, it is clear that chickens have two legs and rabbits have four legs.

First the chicken and the rabbit lift one foot at the same time, then lift one foot, and the rest is the rabbit's foot, at this time each rabbit has two feet, and the number of rabbits is (134 40 40) 2 27 The number of chickens is 40 27 13

Solution: Let the rabbit have x, the chicken has Y, and the title has a relationship with Chi Yan:

x+y=16

x+2y=34

Obtained from enlightenment: x=16-y

Bring x=16-y into to get:

4（16-y）+2y=34

64-4y+2y=34

2y=-30

y=30÷2

y=15 (only).

So: from x+y=16 we get:

x=16-15

x=1 (only).

Answer: There are 15 chickens and 1 rabbit.

16 4 = 64, 64-34 = 30, nucleus.

30 2 = 15, 16-15 = 1, answer Zheng: There are 15 chickens, and 1 rabbit is old.

Set up chickens x and rabbits only ruler bridge Lu Lingqing.

x+y=36 2x+4y=104 The solution is: x=20 y=16

A: 20 chickens and 16 rabbit socks.

35 12 47 (only).

A: There are 35 chickens and 47 rabbits.

Xie Hui Shi Bang: There are 35 heads, that is, there are 35 chickens and rabbits.

set, there are chickens x and rabbits.

Equations according to the question:

x+y=35①

2x+4y=94②

by , x=35-y

Bring it back to the forest, and get to:

2×(35-y)+4y=94④

solution, gets: y=12

Bring in, get:

x=23A: There are 23 chickens and 12 rabbits.

It can also be solved by talking about the second equation of one element and one omission.

Let's say, there are x chickens, then the rabbits are 35-x.

According to the equation of the problem: 2x+4 (35-x)=94, we get: x=23, 35-x=12

Chickens and rabbits in the same cage: Think of it this way, chickens have 2 legs, rabbits have 4 (2+2) legs. Suppose all the chickens, then there will be 2 rabbit feet thought to be chicken feet, and the remaining 2 feet are not counted in the feet, then how many rabbits are counted in this way, that is, with (total feet - assuming all the feet are calculated by chickens) 2, so the calculation is the number of rabbits.

Suppose it's all chickens: 13 2 = 26 (only).

Number of rabbits: (34-26) (4-2) = 4 (chickens) Number of chickens: 13-4 = 9 (chickens).

Solution 2: Binary Equation.

Solution: There are x chickens and y rabbits.

x+y=13 (only).

2x+4y=34 (only).

The solution is x=9 and y=4.

If it's not all chickens, the legs should be 13 2 = 26.

The number of free is: (34-26) (4-2) = 4.

The number of chickens is: 13-4=9

Equations with unknown sequences can be solved.

The unary equation: Let the chickens be x, then the rabbits (13-x). Then there are equations.

2x+4（13-x）=34

Finding x=9 means that there are 9 chickens and 13-9=4 rabbits.

A system of binary linear equations.

Set up x chickens and rabbits.

Then there is: x+y=13

2x+4y=34

x=9 and y=4.

Assuming that 13 heads are all chickens, there are legs 13 2 = 26 legs;

Now there are 40-26 = 14 extra legs, of course, which are child-free;

According to the calculation that each rabbit has more legs than the chicken, 14 rabbits 2 = 7;

Therefore, it is known that there are 7 free children and 13-7 = 6 chickens.

Column: rabbit (40-13 2) 2=7;

Chickens 13-7 = 6.

This is a problem of chickens and rabbits in the same cage, you can set the chicken as x, then the rabbit is 88 x only. The column equation is 2xten4 (88-x) = 244, and the solution equation is x=54, then rabbits = 88-54 = 34. So the product is 54 and the rabbit is 34.

Calculate the number of rabbits using the foot lifting method: we make all their heads lift 2 feet, and divide the remaining number of feet by 2 to get the number of rabbits: (244-88x2) 2=34 (only).

Then count the number of chickens: 88-34 = 54 (chickens).

No column equations, simple algorithms:

1. Divide the number of feet by 2 to get: 122

2. Subtract the number of heads to get: 122-88=44, which is the number of rabbits.

3. Subtract the number of rabbits from the total number of heads to get the number of chickens: 88-44=44