What is the binary number of 97 98?

What is the base system?

If it's not a decimal one:

First convert to decimal and then convert to 2.

If it's a decimal:

The binary number is a cyclic decimal and it is verbose

The binary number of 97 is 1100001

2|97...Remaining 1

2|48...Remainder 0

2|24...Remainder 0

2|12...Remainder 0

.2|6...Remainder 0

.2|3...Remaining 1

.2|1..Remaining 1

The binary number of is.

The integer part is 1

The integer part is 1

The integer part is 1

The integer part is 1

The integer part is 1

The integer part is 0

The integer part is 1

The integer part is 0

The integer part is 1

The integer part is 1

The integer part is 1

The integer part is 0

The integer part is 0

The integer part is 0

The integer part is 0

The integer part is 1

The integer part is 0

The integer part is 1

The integer part is 0

The integer part is 0

The integer part is 0

The integer part is 0

Counting this, I found a duplicate number in fact, the first repeated number is, I didn't find it at first), so it's a circular section for 1111010111000010100.

The last binary number obtained is.

There is a very simple way, open the calculator that comes with Windows, select the scientific type in the view, then enter the number you want to look up, and then select the type (binary, octal).

First of all, you need to know the representation of the integer part, it's too simple to say. The number after the decimal point is similarly represented as 1 2 1 4 1 8 ......In this way, most of the numbers cannot be accurately represented in this way, and this leads to accuracy problems, such as the following representations.

Float-type single-precision floating-point variables, on the other hand, occupy 4 bytes and include 1 single bit (sign bit), a binary exponent with 8 bits over 127 (integer part), and a 23-bit mantissa (decimal part + 1). The mantissa here represents a number between and . Since the number in the higher order of the mantissa is always 1, it is not stored in the integer part (which is what it means in between).

This definition makes the number of float types roughly between to both scientific notation).

Therefore, it cannot be accurately represented, only approximately.

The binary of 7 is 111. Binary, discovered by Leibniz.

is in mathematics and digital circuits.

The notation system with 2 as the base number of the slippery hill is a binary system with 2 as the base number to represent the system.

In this system, it is usually represented by two different symbols: 0 (for zero) and 1 (for one).

Binary Operations:Addition: There are four cases of binary addition: 0+0=0,0+1=1,1+0=1,1+1=10 (0 is rounded to 1).

Multiplication: Binary multiplication has four missing cases: 0 0=0, 1 0=0, 0 1=0, 1 1=1.

Subtraction: There are four cases of binary subtraction: 0 0 = 0, 1 0 = 1, 1 1 = 0, 0 1 = 1.

Division: Binary division has two types of love letter (divisor.

Can only be 1): 0 1 = 0, 1 1 = 1.

Convert decimal integers to binary numbers.

The divide by 2 reverse remainder method is adopted:

Read the remainder of each session from the bottom up.

That's the result of the conversion:

Convert decimal pure decimal numbers to base numbers by multiplying 2 by rounding up:

Reading the integer part of each quotient from top to bottom is the result of the conversion:

Combining the results of integer and decimal conversions is the overall answer:

Base conversion: 98 (decimal) = 1100010 (binary).

The integer part is adopted"Divide by 2 and take the remainder and arrange them in reverse order"Law. The specific method is: divide the decimal integer by 2 to get a quotient and remainder; Removing the quotient with 2 again gives a quotient and remainder;

This is done until the quotient is less than 1, and then the remainder obtained first is used as the lower significant digit of the binary number, and the remainder obtained later is used as the high significant digit of the binary number, and then arranged in order.

1÷2=0……Source slag 1

The inverse order is called the oak remainder, and the binary and fissure systems of 97 are 1100001, a total of seven digits.

Answer: Decimal 97 to binary is (1100001) beam scatter.

The steps to solve the rubber problem are as follows:

97÷2=48…The remaining number is 1,1 2 0=1,48 2=24....The remainder 0,0 2 1=0,24 2=12....The remainder 0,0 2 2=0,12 2=6....The remainder 0,0 2 3=0,6 2=3....The remainder 0,0 2 4=0,3 2=1....The remainder 1,1 2 5=32,1 2=0....Remainder 1,1 2 6=64, validation: 64+32+0+0+0+0+1=97, result: (97) 1100001).

Please see the answer, otherwise you will not be able to understand if there is no branch display].

87 is the decimal 87

Turn to base: Write the base number of binary cards first.

128 64 32 16 8 4 2 1 Start with the single digit 1 and write to the left, each digit is the previous digit multiplied by 2, until it is greater than or equal to 87.

Calculated from the highest (leftmost):

87 128 = 0 more than 87, write the quotient 0 below the bit, and continue to calculate with the remainder in the next step.

87 64 = 1 surplus 23, 64 write 1 below

23 32 = 0 surplus 23

23 16 = 1 surplus 7, 7 8 = 0 surplus 7, 7 4 = 1 surplus 3, 3 2 = 1 surplus 1, 1 1 = 1 surplus 0

Calculate until the remainder is 0, and fill in 0 if there are any remaining digits

Then decimal 87 is equal to 1010111 in binary

Rotate 8 base: It is about the same as base 2, the difference is in the calculation of the base number on each bit.

512 64 8 1 Write from single digit 1 to the left, each digit is the previous digit multiplied by 8, until it is greater than or equal to 87.

Calculated from the highest (leftmost):

87 512 = 0 surplus 87, write the quotient 0 below the bit, and continue to calculate with the remainder in the next step.

87 64 = 1 surplus 23, 64 write 1 below

23 8 = 2 remainder 7, 7 1 = 7 remainder 0, calculated until the remainder is 0, if there are any remaining digits are filled in 0

Then the decimal system 87 is equal to 8 and the grandson system 127, so that the hand calculation is simple, and other wonderful decimal systems can be calculated in this way.

Binary to octal directly, starting with the lowest (rightmost bit) and separated every 3 digits:

1010111=1,010,111 and convert the separated number as an independent binary number to a decimal number.

The result is that 127 is octal data.

97 (decimal.)

1100001 (binary).

Convert decimal integer to binary integer:

Decimal integers are converted to binary integers"Divide by 2 and take the remainder and arrange them in reverse order"Law. The specific method is: divide the decimal integer by 2 to get a quotient and remainder;

Removing the quotient with 2 will make another move or to a quotient and remainder, and so on until the quotient is 0, and then the remainder obtained first will be used as a binary number.

, and the resulting remainder is arranged sequentially as the high significant digits of the binary number.

Specific method: 97 2 = 48 surplus 1

48 2 = 24 remainder 0

24 Balance 2 = 12 and 0

12 2 = 6 and 0

6 2 = 3 and 0

3 2 = 1 and 1 remains

1 2 = 0 more than 1

97 (decimal.)

1100001 (binary).

The binary number of 97 is the seven bits with the nucleus: (1100001).

97÷2=48…1,1×2^0=1,48÷2=24…0,0×2^1=0,24÷2=12…0,0×2^2=0,12÷2=6…0,0×2^3=0,6÷2=3…0,0×2^4=0,3÷2=1…1,1×2^5=32,1÷2=0…1,1 2 6=64,97) Hidden Sell = (1100001).

98 to binary is 1100010.

Binary refers to a numerical system based on 2 in mathematics and numerical circuits, and the base number of 2 means that the system is binary. In this system, it is usually represented by two different symbols, 0 and 1.

The conversion of a decimal number to a binary number is divided into integer parts and decimal parts, and finally combined.

The integer part is adopted"Divide by 2 and take the remainder and arrange them in reverse order"Law. The specific method is: divide the decimal integer by 2 to get a quotient and remainder; Removing the quotient with 2 will give a quotient and remainder again, and so on until the quotient is less than 1, and then the remainder obtained first will be used as the lower significant digit of the binary number, and the remainder obtained later will be used as the high significant digit of the binary number, and then arranged in turn.

The decimal part is rounded by 2. That is, multiply the decimal decimal by 2 and take away the integer of the result (must be 0 or 1), and then repeat the previous steps with the remaining decimal until the remaining decimal is 0, and finally arrange the integer part obtained each time from left to right to obtain the corresponding binary decimal number.