Physical celestial motion, how celestial bodies move

First the velocity, because the AC angular velocity is the same, the radius of A is greater than C, so Va > VC, then compare A and B, because MV2 R=MMG R2, so the larger R, the smaller V, so VB>VA>VC

In the same way, va>vc, wa=wc, so aa>ac, a=mv 2 r, vb>va, rbaa, so ab>aa>ac

I don't know how to continue to ask

Upstairs, don't mislead people, acceleration and linear speed are also related

The conditions of the other satellite B are not complete

For satellites, the higher the altitude, the smaller the linear velocity. VC is the smallest because C is on the ground, and its velocity is the rotation linear velocity of the Earth, which is very small, less than 500 ms, and the speed of a synchronous satellite is 3100 ms. Therefore, vcab>aa, (FSL19920721 reminds correctly, this is gravitational acceleration, not the answer).

The answer is centripetal acceleration, when on the ground, the centripetal acceleration should be much less than the gravitational acceleration, the calculation formula is a = 2*r (FSL19920721 here to pay attention to this clerical error, acceleration does not need to add m), because the angular velocity of A and C is the same, the radius is different, and the radius of A is large, so ACAA. The result is ab>aa>ac.

Let the perihelion be r1, the aphelion is r2, the perihelion velocity is v1, the aphelion velocity is v2, and the mass of the planet is m

Then the angular momentum is conserved: mv1r1=mv2r2 , so: v1r1=v2r2....1)

According to the conservation of mechanical energy: MV1 2+GMM R1=MV2 2+GMM R2....2)

1) (2) Simultaneous solution: v1 = v2 = solve it yourself.

gmm r1 gmm r2 are the gravitational potential energy of the planet at perihelion and aphelion, respectively.

Think of perihelion as a circular motion with a radius of the minor half axis.

Think of aphelion as a circular motion with a radius of the major half axis.

The velocity is calculated with g*mm r=mv r, respectively.

(1) Let the mass of the three stars be m, and choose one of the two stars around ** as the object.

The gravitational force of it and the ** star is gm 2 r 2, and the gravitational force of it and another star revolving around the ** star is gm 2 (2r) 2. Therefore, the net force experienced by this star is: f=gm 2 r 2+gm 2 (2r) 2

The resultant external force provides the centripetal force: f=mv 2 r=m(4 2 t 2)r

Solution: v = under the root number (5gm 4r) t = under the root number (16 2r 3 5gm).

2) Let the side length of the equilateral triangle be r', if you choose any one of these stars as the object, then the gravitational attraction of the other two stars is: gm 2 r';^2

The angle between these two forces is 60 degrees, so the combined external force on the star is: f=root number 3*gm 2 r'^2

According to the geometric relation, the center of the circular motion is the center of the triangle, and the radius of the circular motion is r=(r'*Root No. 3) 3

The resultant external force provides the centripetal force: f=m(4 2 t'^2)r

Solution: t'= root number (4 2r.)'^3/3gm)

t'=t yields:r'=r*under the cubic root number (12 5).

This is the first question of the preliminary round of the physics competition. The third power of the second question.

1. The planet moves around the central celestial body, f=mw2r (with the central celestial body as the reference frame) This is correct.

2. It is wrong to select both the research object and the reference object as the reference object in the same question (i.e., to use two different reference systems at the same time).

Moreover, if you use the central object as a frame of reference, you assume that the central body is not moving.

f=mw2r.

Progressive faith is not an event, but a necessity.

In the gravitational formula: f = gmm r 2, if the total mass of the moon and the earth is fixed, the maximum gravitational force is that the mass of the two is equal to the previous time, if the mass of the moon is originally small to move to the earth, it will only reduce the gravitational force, so a is wrong b to the return osmosis filial piety.

And because the gravitational force decreases, the rotation of the moon should be slowed down a bit, so it can resist the gravitational pull of the earth, so it should be an increase in the period, it should be c, but the missing answer is d, this is not a clue.

He is not multiplied by 2 3

Here's how: Originally: Qing Chao e = e (dynamic) + e (potential) = later: e = so the orbital radius is 2r, and the planetary kinetic energy is converted into potential wisdom energy!

It seems that the answer is indeed incorrect.

It should be found in this equation simply the gravitational potential energy after the reduction, which is not calculated as kinetic energy, and that has to be calculated separately, so it can be directly multiplied by 2 3

Celestial motion Celestial motion is the original driving force for the movement of space celestial bodies, that is, the power source of material motion, after the occurrence of the universe. The original dynamics of the universe constituted the formation of the gravitational field of matter and the birth of electric and magnetic fields, followed by the centrifugal force of the movement of celestial bodies and the repulsion field between celestial bodies. The space-time of the universe was formed after the great **, and under the action of gravity, we humans saw different celestial clusters of galaxies, which included countless star systems and planets in star systems.

Under the action of the primordial force and the gravitational field, celestial bodies have the orbit and autobiography of celestial motion, and many galaxies, including the Milky Way, have to revolve around the center of the universe in addition to autobiography. In our Milky Way, the celestial motion of the solar system is a good example, the nine planets in the solar system revolve around the sun in addition to autobiography, and in the galaxy, our solar system revolves around the center of the galaxy, also known as the orbital motion of the solar system. It takes 23 hours and 56 minutes to rotate the Earth, the celestial body where we humans live, and it takes one year for the Earth to revolve around the Sun (365 days, 6 hours, 6 minutes, 9 seconds).

The formula for the motion of celestial bodies is gm=gr*r gmm (r*r)=ma

The movement of celestial bodies constitutes the colorful starry sky world of the universe, and under the action of the gravitational field of celestial bodies, it also forms the space-time changes of the material in the universe, making our cosmic material space more and more mysterious.

It revolves around an elliptical orbit and rotates itself at the same time.