Can anyone give me a copy of the physics of celestial motions? About 3000 words! Very urgent! 20

According to r 3 t 2 = r 3 t 2

The radius of Mercury is smaller than that of the Earth.

again by t=2 r 3 gm

It is not possible to derive the relationship of quality.

again a=gm r 2

The mass is unknown, so the acceleration cannot be determined here.

Density = mass volume.

So it can't be judged.

To sum up, choose D

dSolution: According to Newton's third law, the deformation obtains: gmm r = 4 mr t t= (4 r gm) So the period has nothing to do with the mass and density of the object with small mass. The larger the period, the larger the orbital radius, so choose D

According to Newton's third law, it is reduced to gm r = a because r(ground) r(water) so a(ground) a(water).

So C is wrong.

From Kepler's third law (the law of periodicity), that is, r 3 t 2 = k knows r (water) a (ground), c is wrong; And the mass and density are not comparable! In summary, the correct option is d

Since the motion of the planets in the planetary orbit model is only related to the mass of the sun, the mass of Mercury is not important, and AB is all about mass, so it is not chosen.

And since opening three can know that D is correct, C is wrong.

Can anyone give me a physical study of celestial motion?

The great achievements of fundamental physics research in the 20th century can be attributed to the establishment of the theory of relativity, quantum theory and gravitation. The theory of relativity, quantum theory, and gravitational theory all have universality, and an important manifestation of their universality is manifested in the three universal constants of c, h, and g. However, whether the three theories are really universal or not depends on their compatibility with each other, and the establishment of the general theory of relativity confirms the compatibility between the theory of gravity and the theory of relativity.

The development of quantum theory proves that all forms of motion of matter comply with the requirements of quantization, and at the same time, all relativistic fields, such as electromagnetic fields, should also be quantized. In the early stage of field quantization research, there were a series of divergent difficulties. At the end of the 40s, the divergence difficulty of quantized electromagnetic fields was initially solved by the renormalization theory.

The most radical solution to the divergent difficulties was completed in the 60s. The establishment of the unified theory of weak electricity not only solves the difficulty of divergence in weak interactions, but also hopes to solve the compatibility between relativity and quantum theory in the field of strong interactions in a framework similar to weak interactions. The most difficult step is the compatibility of gravitational theory with quantum theory, and one of the main goals of this step is to establish a quantized theory of gravity.

The study of quantum gravity theory also originated from the singularity problem of general relativity. The singularity theorem, proposed by Penrossey and later established by Hawking and Geraldge, shows that the solution of the gravitational field equation must be singular under a fairly wide range of conditions. The existence of singularity suggests that general relativity belongs to the category of classical material implicit theory that obeys the law of cause and effect, and at the singularity, this theory is no longer applicable.

It is possible that the singularity disappeared naturally after taking into account the quantum nature of the gravitational field, a speculation that was subsequently supported by the Hawking Black Luck Cave evaporation theory.

A p that does a uniform circular motion is definitely completely weightless.

Elliptical orbital motion: This motion is complex, and the gravitational pull of the central object is not in the direction of the orbital radius around the celestial body. Therefore, we orthogonally decompose the gravitational force into the component force in the tangential direction of the orbit of the celestial body at this moment, which is called the tangential force; and the second component of the force, which is perpendicular to the tangent direction and points towards the central celestial body, is called the normal force.

The effect of the normal force is to produce normal acceleration around the celestial body, which changes the direction of the velocity around the celestial body. The tangential force changes the velocity (when the angle between the gravitational force and the tangent direction of the orbit is less than 90 degrees, the tangential acceleration plays an acceleration role, such as in the process of satellite motion from apogee to perigee; When the angle between gravity and tangent direction is greater than 90 degrees, tangential acceleration plays a role in deceleration, such as in the process of satellite motion from perigee to apogee). Therefore, for satellites in elliptical orbits, the two effects of gravity still do not have the effect of gravity, so satellites in elliptical orbits around the earth are still completely weightless.

Personally, I think this question is too much... You don't have to dig deeper.

Direct PQ is the same... Take out a small original just to make it easier to understand].

The period of the satellite is 24 hours, and the radius of the earth r=6400km g=then gmm (r+h) =m*(r+h)*(2 t).

gm=gr h=t under the cube root g gr 4 r= the distance from the ground to the geostationary satellite is 29600000 The speed of the signal is equal to the speed of light = 3*10 8m s

Because the signal requires a round trip, the distance traveled is 59200000MT=s V.

Is there a mistake in your question, how is the radius of the track a unit of velocity?

The radius of the geosynchronous satellite is 36000000m, the radius of the earth is 6000000m, the distance from the ground to the satellite is 30000000m, the signal is a round trip: 30000000*2m, and the time is: 600000000 300000000=

Earth-orbital radius: 149,600,000 km (astronomical units from the Sun).

Mars: orbital orbit: 227,940,000 km (astronomical units) from the Sun

Radius and period are two different things.

The larger the radius, the greater the circumference.

But the cycle also needs to consider speed.

f gm1m2 r2 gravitational theorem know no, f is not only related to distance but also to mass, and then look at the form of a according to f=ma as angular velocity, you know whose angular velocity is greater.

The radius of Mars is about twice that of Earth.

Gravitational acceleration provides a centripetal acceleration draft.

gm/r^2=v^2/r

The solution is m=v 2*r key brother Xiaochen changed g

Black holes break away faster than the speed of light.

2gm/r>=c^2

The solution yields r<=gm c 2 2

Synoid r<=(v c) 2*r 2=(

There is a good chance that the calculation was wrong.

But that's the way it works.

Answer] C Answer Analysis] Test Question Analysis: The world is material, it is objectively existent, and it is not subject to human will, with the help of scientific experiments, astronomers have discovered many new forms of matter in the universe, and the continuous discovery and understanding of objective things further proves the objective reality of matter, C is correct; Phenomena are a reflection of reality, objective in nature, aerrous; b d does not correspond to the meaning of the title and fails to recognize the objective reality of matter.

Test Point: This question examines the objective nature of nature.