For the second year of junior high factorization questions, the second year of junior high factoring

1.Knowing a=10000 and b=9999, find the value of a + b -2ab-6a + 6b + 9.

Solution: Original formula = (a-b) -6(a-b) + 9

a-b-3)²

2.Try to explain that (x+1)(x+2)(x+3)(x+4)+1 is a perfect flat method.

Solution: Original = (x+1)(x+4)(x+2)(x+3)+1(x +5x+4)(x +5x+6).

x²+5x)²+10(x²+5x)+25(x²+5x+5)²

That is: (x+1) (x+2) (x+3) (x+4) +1 is a perfect equal.

Decomposition factor) x - (y -y+

x²-(x+4.Knowing that a, b, and c are the lengths of the three sides of abc, and satisfying a +2b +c -2b(a+c)=0, try to determine the shape of this triangle.

Solution: Because a +2b +c -2b(a+c)=0, a -2ab+b +b -2bc+c =0 so (a-b) +b-c) =0

Because (a-b) 0, (b-c) 0

So a-b=0 and b-c=0

So a=b=c

So abc is an equilateral triangle.

Decomposition factor) x -y ) + ax + ay).

x+y)(x-y)+a(x+y)

x+y)(x-y+a)

There are too many questions, and I'm too lazy to play, so if you still want to ask questions, just add me, I'm in the third year of junior high school.

Usually multiplied with crosses.

Hope it helps!

Please see the following three sets of questions and answers:

There is mainly a perfect sum of squares: (a b) = a 2ab + b

Square difference: a -b = (a + b) (a-b).

1.If 4x2 mx 9 is a perfect square, then the value of m is 4x2 mx 9=(2x-3) 2=4x 2-12x+9m=12

2.If (a2 b2 1)(a2 b2 1) 15, then a2 b2 (a 2+b 2) 2-1=15

a^2+b^2)^2=16

a^2+b^2=4

3.Knowing that x y=3 and xy=10, find the value of 3x2 3y2 (x-y) 2=9

x^2+y^2-2xy=9

x^2+y^2=9+20=29

3(x^2+y^2)=87

4.Unsolve the system of equations 2x y=6 Find the value of 7y(x 3y)2 2(3y x)3.

x－3y=1

2x＋y=6

2x-6y=2

7y=4y=4/7

7y（x－3y）2－2（3y－x）3

7y-2=4-2=2

a^2+8ab+7b^2+a+b

a+7b)(a+b)+(a+b)

a+7b+1)(a+b)

2) If kx 2-5xy-12y 2=(x-3y)(kx+4y), then k=

x-3y)(kx+4y)

kx^2+(4-3k)xy-12y^2

kx^2-5xy-12y^2

So 4-3k = -5

k=3 factorization=(=

x 4 - x -20, which can be broken down by cross multiplication, x 4

x²+4)(x²-5) x² -5

x²+4)(x+√5)(x-√5)