How the atoms that make up the delocalized bond calculate the valency

The valency in the delocalized bond, the ozone and azide ions you are talking about are generally used as the average valence, and when the equation is balanced, it is generally considered that the oxygen in the ozone O3 element is 0 valence, just as the phosphorus in the white phosphorus P4 element is also regarded as 0 valence. And azide ions, such as silver azide, the azide is -1 valence, and each nitrogen atom is -1 3 valence, which is generally considered to be so.

It is also the same as (1,3) H2C=CH-CH-CH2 carbon in butadiene, C4H6, you are not sure what valence the carbon in it is, generally like Fe3O4, specifying an average valence is just ......

If it is azide acid, then of course the valency of the nitrogen linked to hydrogen is minus 1, then in the azide root, as I said upstairs, it is no longer meaningful to discuss the valency, if you really want to discuss, because of the delocalization bond, the three nitrogen atoms are equally divided by the 1 negative charge, that is to say, the valence state of the three nitrogen atoms is minus one-third.

However, my point of view is a bit different from that of the first floor, that is, the three nitrogen are not exactly the same, so to speak, the two nitrogen on both sides are exactly the same, but the middle one is different from them, it has two ordinary covalent bonds, and only one on each side. Even so, there is no doubt that the three nitrogen atoms are bisected by that 1 negative charge due to the delocalized bond.

If we analyze it theoretically, the three N's are indeed different.

However, what the first floor said is actually not wrong, if you use spectral analysis, the three n are the same.

It's all because of the delocalization.

Its effect can be considered as a kind of averaging, so 3 n can be averaged with valency -1 3 although our analysis is different

It is necessary to determine the approximate direction of electron shift by analyzing electronegativity (qualitative should also be possible, but that involves quantum chemistry, which is very troublesome and has not yet been learned).

The common electron withdrawing order is -n(+)r3>nitro"cyano"carboxy"alkoxycarbonyl (i.e., lipid group)>carbonyl"-f>-cl>-br>-i>methoxy""hydroxy""pheny""vinyl"-h>methyl"ethyl"isopropyl"tert-butyl.

Since the delocalized bond is formed, then in the azide the three n is exactly the same (spectrally confirmed), that is, the valence state is the same, which is the negative third, and if the three n in azide acid are different, but the question is not to ask the valence state problem at this time, but there is a bond number.

Attachments to the same atom are considered to be 0 valence. When connected with different kinds of atoms, electronegativity is seen as electronegativity, which is generally a common valence state in organic compounds.

If it's a delocalized key, it doesn't make sense to calculate valence.

You're going to participate in a chemistry competition, and I can tell you for sure that the competition doesn't ask questions about valency at all.

The valence is an average. When discussing pie bonds, don't use the concept of valence.

The valency of the ion is used to subtract the valency of the coarse pure limb in the ion except for the remaining elements of the element.

Such as (pants friend SO4) 2- to find the sulfur valency.

Usable -2-(-2x4)=+6

To calculate the valency of an atom, we must first know what valence states the atom has, and then calculate it according to the sum of the valency is equal to zero.

Valence tables of common elements and atomic clusters.

Potassium k + 1 chlorine c1-1, +1, +5, +7

Sodium Na + 1 Oxygen O-2

Silver ag +1 sulfur s-2, +4, +6

Calcium, Ca+2, C+2, +4

Magnesium mg + 2 silicon si + 4

Barium BE+2 nitrogen n-3, +2, +4, +5

Zinc Zn + 2 phosphorus p-3, +3, +5

Copper Cu +1, +2 sulfate SO42--2

Iron Fe + 2, +3, carbonate CO32--2

Aluminum Al+3 nitrate NO3--1

Manganese Mn+2, +4, +6, +7 hydroxide OH--1

Hydrogen H+1 ammonium NH4++1

Fluorine F-1 phosphate PO43--3

For example, Fe2O3 must have a valence of -2 for oxygen, so iron is +3 valence. In Fe3O4, oxygen is -2 valence, so the total valence states of the three irons add up to +8 valence, while iron has two valence states, +2 and +3, so that there are two moles of ferric tetroxide and one mole of ferric tetroxide.

An ion is a stable structure in which an atom loses or gains one or several electrons due to its own or external action, bringing it to the outermost shell with an electron number of 8 or 2 (hydrogen or helium atoms).

Atoms refer to the basic particles of chemical reactions, and atoms are inseparable in chemical reactions. An atom is made up of a nucleus and electrons outside the nucleus.

Molecules are made up of atoms, elemental molecules are made up of atoms of the same element, and compound molecules are made up of atoms of different elements.