Can KMnO3 be oxidized by H2O2?

It cannot be oxidized. Hydrogen peroxide itself is unstable. Contact with metal ions. will decompose.

The oxidation of H2O2 is stronger than that of KMno4 and is stronger than that of KMno3.

There is no contradiction between the fact that KMno4 can oxidize H2O2 and H2O2 is stronger than KMno4.

Hydrogen peroxide is more oxidizing than potassium permanganate, which can be seen from their standard electrode potential under acidic conditions

h2o2 + 2e + 2h(+)== 2h2o；φθ= +

mno4(-)5e + 8h(+)== mn(2+) 4h2o；φθ= +

Because (mNO4(-) mn2+) H2O2 H2O, H2O2 is more oxidizing than KMno4 under acidic conditions.

However, the standard electrode potential for H2O2 to be oxidized to O2 is much lower than that of Mno4(-).

o2 + 2e + 2h(+)== h2o2；φθ= +

Therefore, mno4(-) can oxidize H2O2 to O2, which is not contradictory to the fact that H2O2 is more oxidizing than Mno4(-).

In other words, the strong oxidation of H2O2 is reflected in the process of being reduced to H2O, but it is difficult to protect itself because it is easily oxidized to O2, and its attack ability is strong, but its defense ability is very poor.

2 KMnO4 + Na2SO3 + 2 NaOH = = 2 Na2MNO4 + K2SO4 + H2O

Two slag kmno4 + three na2so3 + h2o = = two mno2 + three na2so4 + two koh

Analysis: In the KMno4 solution, the acidification of concentrated hydrochloric acid does not play the role of acidification, because KMno4 has strong oxidation, and the oxidation of hydrochloric acid is generated into Cl2, and KMno4 is reduced to form manganese chloride, hydrogen ions are combined with oxygen atoms to form water, and when the solution is acidified, KMno4 has been completely reduced, at this time, the solution is no longer an acidic KMno4 solution with strong oxidation. The chemical equation is:

kmno4+16hcl=mncl2+8h2o+kcl+cl2↑；

If acidified with dilute sulfuric acid, KMno4 can oxidize H2O2 to produce O2 oxygen, and the chemical equation is very complex, because the amount of various substances is different, and the chemical equation of the reaction is also written differently. However, H2O2 is reductive and produces oxygen.

Therefore, KMno4 acidified with concentrated hydrochloric acid cannot react with H2O2, but.

KmNO4 acidified with dilute sulfuric acid can oxidize H2O2, and H2O2 is reducible.

Does not have !! Reacting with H2O2 with a concentrated hydrochloric acid acidified KMno4 solution does not prove that H2O2 is reducible:

2mno + 6h+ +5h2o2 ＝ 2mn2+ +5o2↑ +8h2o

Because: there is no problem with the ion equation itself, but the strong oxidation performance of KMno4 oxidizes the concentrated hydrochloric acid, and the purpose of proving that H2O2 is reductive (reducibility: HCl H2O2, HCl reacts first)!

First of all, you need to know that there must be reducing and oxidizing properties in a reaction. Secondly, you look at the mantra (high (valency). loss (electron). Also (reducible). is oxidized.

The element hydrogen has two valences.

It is both reducing and oxidizing.

Ion equation 2mNO4 - 5H2O2 + 6H+ = 2MN2+ +5O2 + 8H2O If you write a chemical equation, add KMno4, and H+ is H2SO4 i.e. the acidic KMno4 solution is generally acidified with H2SO4.

2mno4- +5 h2o2 + 6h+ = 2mn2+ +5o2↑ +8h2o

This reaction can be used to determine the amount of H2O2. The speed of adding KmNO4 during titration should not be too fast, otherwise it is easy to produce MnO2 precipitation, which can promote the decomposition of H2O2 and increase the determination error. When the first drop of KMno4 solution is dropped, it is not easy to fade, and after the generation of Mn2+, due to the catalytic effect of Mn2+, the reaction speed is accelerated, and the determination speed is also accelerated, and the titration is until it presents a stable reddish color, which is the end point.

Chemical Reaction Formula:

5so2+2kmno4+2h2o=k2so4+2mnso4+2h2so4

Ionic formula: 5SO2 + 2H2O + 2MNO4-=5SO42 - +2Mn2 + + 4H+

In this question, SO2 and H2O generate H2SO4

H2SO4 then reacts with KMno4 to form K2SO4.

The final answer to MnSO4 is 5SO2+2KMno4+2H2O=K2SO4+2MnSO4+2H2SO4

Under acidic conditions:

2kmNO4 + 5H2O2 + 2H2SO4 ====K2SO4 + MNSO4 + 5O2 (gas) + 2H2O

Under neutral or alkaline conditions:

2kmNO4 + 3H2O2 ====2KOH + 2MNO2 + 2H2O + 3O2 (gas).

Acidic conditions, can react, NH4+ is oxidized to N2 or NO2 or NO2 or HNO3

5 (nh4)2co3 + 6kmno4 + 9 h2so4 = 5 co2 + 5 n2 + 3 k2so4 + 6 mnso4 + 29 h2o

nh4)2co3 + 2 kmno4 + 3 h2so4 = co2 + 2 no + k2so4 + 2 mnso4 + 7 h2o

5 (nh4)2co3 + 14 kmno4 + 21 h2so4 = 5 co2 + 10 no2 + 7 k2so4 + 14 mnso4 + 41 h2o

5 (nh4)2co3 + 16 kmno4 + 24 h2so4 = 5 co2 + 10 hno3 + 16 mnso4 + 8 k2so4 + 39 h2o

KMNO4 has strong oxidation, and the oxidation is stronger under acidic conditions, so when re-acidifying, it is necessary to pay attention to whether it will oxidize the acid used for acidification, such as hydrochloric acid, it can oxidize chloride ions, and the sulfur element in sulfuric acid is 6 valence and can not be back oxidized. Nitric acid is unstable and easy to decompose, which is one point, and the oxidation of nitric acid is stronger than that of potassium permanganate, so the oxidation of potassium permanganate cannot be reflected in the reaction, and the acidified potassium permanganate solution is usually used for redox titration (using color change), and with the addition of nitric acid, nitric acid will also participate in the redox reaction and cannot complete the titration. In addition, the product of nitric acid reduction is nitrogen oxides, which are toxic, harmful to people and pollute the air.

Therefore, instead of hydrochloric acid and nitric acid, sulfuric acid is used to acidify.

Because KMNO4 is highly oxidized, it does not react with hydrochloric acid, but oxidizes hydrochloric acid to produce chlorine gas.

It should be: 8kmNO4 + 15Ki + 13H2SO4 == 8mnSO4 + 5I2 + 5KIO3 + 9K2SO4 + 13H2O

In one reaction formula, iodine rises from -1 valence to 0 and +5 valence, and mn rises from +7 valence to +2 valence (down 5 valence), and iodine rises by 5 2 + 5 6 = 40 valence.

Therefore, MN needs to reduce the old 40 price in total, and the hole wisdom can be matched according to the conservation of elements with a coefficient of 40 5=8 of KMNO4.