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Oval base area * high. The key is to find the area of the ellipse.
Ellipse area: o is called the center of the ellipse, a, a, b, b is called the "vertex", aa is called the "major axis", and bb is called the "minor axis".
In addition, the long OA A is called the "long radius" and the short OB is called the "short radius".
There are also those who call the ellipse "oblong".
When a b, the ellipse is a circle.
When denoting the area of an ellipse as s, the area of the ellipse can be found using the formula s ab. a b, of course, s represents the area of the circle.
When the long radius A3 (cm) and the short radius B2 (cm), its area is S3 2 6 (cm2).
In the examples so far, such as the length of the circumference, the length of the arc, the area of the circle, the area of the fan, the area of the bow, the area of the ellipse, etc., all use pi.
In this way, it is indispensable to calculate not only circles but also ellipses.
In summary, the ellipse area s = ab, (a, b are the lengths of the major and minor axes, respectively).
The volume of the oval tank = the area of the elliptical * the height.
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Hello, I am from Linchuan No. 1 Middle School, one of the top ten universities in China, and I responsibly say that the elliptic area cannot be calculated with a formula. Fill the cylinder with water, place the ellipse in the cylindrical water, and the overflow part is the volume of the ellipse.
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See if that jar is completely oval or flat up and down? (Just pay attention to it when you build a coordinate system.) The centroid of the ellipse is used as the origin to establish a spatial Cartesian coordinate system.
In summary, the coordinate system divides this elliptical tank into 8 equal volume sections. Then calculate the volume of the first hexagram limit and multiply it by 8, which is the volume of the tank, that is, the volume. When calculating, it is sufficient to use double integrals.
The integral region, if I establish the coordinates like this, should be that x is greater than 0 and less than a (a is the length of the ellipse's major semi-axis), y is greater than 0 and less than the equation of the ellipse circumference, and then use these two ranges to quadratically integrate the equation of the ellipse surface. (Don't say you haven't learned advanced math, if you haven't learned it, just take me as nonsense).
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Summary. The formula for ellipse area * tank height, ellipse area: s = ab, where is pi, a is the radius of the minor axis, and b is the radius of the major axis.
The ellipse is the sum of the distances from the plane to the fixed points f1 and f2 equal to the constant greater than |f1f2|The trajectories of the moving points p, f1 and f2 are called the two focal points of the ellipse. The mathematical expression is: |pf1|+|pf2|=2a(2a>|f1f2|)。
An ellipse is a type of conic curve, that is, the section between a cone and a plane. The circumference of an ellipse is equal to the length of a particular sinusoidal curve in a cycle.
The formula for ellipse area * tank height, elliptic area of the circle: s = ab, where is pi, a is the radius of the minor axis, and b is the radius of the major axis. The ellipse is the sum of the distances from the plane to the fixed points f1 and f2 equal to the constant greater than |f1f2|The trajectories of the moving points p, f1 and f2 are called the two focal points of the ellipse.
The mathematical expression is: |pf1|+|pf2|=2a(2a>|f1f2|)。An ellipse is a type of conic curve, that is, the section between a cone and a plane.
The circumference of the ellipse is equal to the length of a particular sinusoidal curve in a weekly period.
Take a look. v = 4 3 abc (a and b, c represents half of the x-axis, y-axis, z-axis slag positive). The area formula is s=2 c +2 ab sin( )e( ,k) (sin( )f( ,k) (cos( )cos( )c a; k^2=[a²(b²-c²)]b²(a²-c²)]a≥b≥c;where e( ,k) and f( ,k) are elliptic beam circle integrals.
v = 4 3 abc (a and b, c represents half of the x-axis, y-axis, z-axis slag positive). The area formula is s=2 c +2 ab sin( )e( ,k) (sin( )f( ,k) (cos( )cos( )c a; k^2=[a²(b²-c²)]b²(a²-c²)]a≥b≥c;where e( ,k) and f( ,k) are elliptic beam circle integrals.
I don't understand. What should be the head area of the storage tank 500L specification 70 100 6 Hu degree 25
It's 2348
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Hello, to calculate the cubic meters of an elliptical tank, you need to know its length, width, and height, as well as the length of the major and minor axes of the ellipse. Then you can use the following formula to calculate the tie touch: volume = radius of the major axis radius of the minor axis height of the tank collapse, where is the pi, and the radius of the major axis and the radius of the minor axis are half of the major and minor axes of the ellipse, respectively.
For example, if the length of the long axis of an oval jug is 4 meters, the length of the minor axis is 2 meters, and the height is 3 meters, then its volume can be calculated as: volume = 2 meters 1 meter 3 meters = cubic meters Therefore, the capacity of this oval jug is a cubic meter.
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Hello, the formula is the ground area high. The volume of the cylinder = the bottom area x the high Qiling, that is, v = s the area of the bottom mold h=( r r)h. There is a fixed line and a moving line in the same plane, when this plane rotates around this fixed line, the surface formed by this moving line is called the rotating surface, this fixed line is called the axis of the rotating surface, and this moving line is called the bus bar of the rotating surface.
If the cylindrical surface is cut by two planes perpendicular to the axis, then the geometry enclosed by the two sections and the cylindrical surface is called a straight cylinder, referred to as a hidden cylinder.
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Summary. After knowing the total height and width of the U-shaped slot, divide it into two parts, the upper part is a cuboid and the lower part is a semicircle. Assuming that the height of the U-groove is a and the width is b, then the total area of the U-groove is: S total =.
After knowing the total height and total width of the cavity U-shaped groove, divide it into two parts to balance and calculate, the upper part is a cuboid and the lower part is a semicircle. Assuming that the height of the U-shaped groove is a and the width is b, then the total area of the socks of the U-shaped groove is: S total =.
What conditions do you need to know, length, width and height? Is the length, width and height the inner volume? What does b refer to? Width.
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The volume of the elliptical tank = the bottom area of the elliptical tank x the high elliptic area of the elliptical tank S = a b (where a and b are the length of the semi-major axis and the semi-minor axis of the ellipse, respectively).
Under the standard case, the oil tank is a cylinder, and the water is a ton of one cubic meter of oil, and the water in the barrel is transferred to water, that is, 13 5 cubic meters of bottom area, that is, 6 75 square meters multiplied by 0 75 meters, which is equal to 5 0625 cubic meters (water).
It should be noted that the size of the volume is closely related to the shape of the product. Since the shape of the bottle is not a standard geometry, it is not possible to calculate the volume according to the conventional formula, and can only be designed according to the shape of the product, the shrinkage of the product, and the required capacity.
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In the standard case, the oil tank is a cylinder, and the water is a ton of one cubic meter of oil, and the water in the barrel is 13 5 cubic meters, and the bottom area is 6 75 square meters multiplied by 0 75 meters, which is 5 0625 cubic meters (water).
Converted to oil, it is about 5,018 tons.
In addition, since it is a cylinder, it is about 5 022 tons to come out with 3 8 (0 75 2) directly with 15 * 3 8.
If your oil barrel smells weird, you won't be able to untie it.
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My round tank is long, wide and high, how many tons of water can I put? √
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1. The total volume is equal to the base area multiplied by the height (
How much liquid to hold: If the unit is fine, it's volume multiplied by density.
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