Solve this math problem, thank you! A math problem, solve thank you!

This is a collection problem, draw a set diagram to better solve it, and let the people who do it right are x. Logically speaking, except for those who do everything wrong, it is the sum of those who do the right experiment and those who do it right. That is, 40+31-x=50-4All get out x=25

Solution: If there are x people who do both kinds of experiments correctly, then there are (40-x) people who only do the experiment on A, and there are (31-x) people who only do the experiment on B, and from the title, x+(40-x)+(31-x)+4=50

Solution x=25

A: There were 25 people who got the two experiments right.

Solution: According to the meaning of the question, it can be seen that the people who are both wrong or right are: 2 50-(40+31)=29 (people).

Because it is also known that there are 4 people who did both experiments wrong.

So the people who were right in both experiments were 29-4=25 (people).

Those who do at least one question correctly (ab all do it right + only one question): 50-4 = 46 people ab all do it right*2 + only do one question correctly: 40 + 31 = 71 people ab all do it right: 71-46 = 25 people.

First of all, let's say that the person who does everything right is x, so the person who only does a right and does not do B right is 40-x person, the person who only does B right but not the right A person is 31-x, and the person who is completely wrong is 4 people, so use x+31-x+40-x+4=50 to get x=25 people.

There were 4 people who got the test wrong, and 46 people who got at least one right.

If the title has told 40 people to do the right A experiment, it means that 6 people only do the right B test.

At the same time, 31 people did the right B test, which means that 15 people only did right A and did B wrong.

So the answer to the question is 50-4 (all wrong) - 15 (A is true and B is false) - 6 (B is true and A is false) = 25 people.

m+2）y=8，y=8/(m+2)

Finding the solution of positive integers, then the divisors of 8 have 1, 2, 4, 8, then bring y into respectively.

m

1. The area of weeding surface per person per hour is.

72 12 sq.

In the afternoon, the area of weeds can be pulled.

Square 2, paved with 35 square floor tiles of 1 square meter. So the living room area is 35 square meters, the living room area is 23 square meters larger than the kitchen area, the kitchen area is 35-23 = 12 square meters, 35 can be allocated as 5x7, each floor brick yard is square, the side length is 1, the perimeter of the bottom of the living room is 5 + 7 + 5 + 7 = 24

a+c=2b

So a, b, and c are in a series of equal differences.

a^2+b^2-c^2=-ab

By (1) A2+B2-(4B2-4AB+A2)+AB=05AB-3B2=0

So a b = 3 5

Let the three sides be: x, y, z

Then there are: xy=root2, xz=root3, yz=root6 can be found: x=1, y=root2, z=root3

It's not easy to draw here, just remember it, let the underground surface be xy, then its diagonal ac=[root number (x 2+y 2)] = root number 3

Because Z = root number 3, according to the triangle principle, it can be known that the length of the diagonal line of this box = [root number (ac 2 + z 2)] = root number 6

It's a bit abstract.,Let's take a good look at it!

Solution: Suppose there are x monkeys in group A and y monkeys in group B.

From the title: 3x+4y=705 4x+3y=716:

y-x=-11

y=x-11 substitutes for :

3x+4（x-11）=705

x=107y=107-11=96

So there are 107 in group A and 96 in group B.

Ask for adoption, and I will be upgraded with only one adoption.

(1) p(3,4) is substituted with input = 2

2) When 0 < 1, f(lg1 100) f(.

Proof of: F(LG1 100) = F [LG10(2)] = A (3).

f( set exponential function y = the monotonic function of x at r when 0 f(lg1 100) 1, the function f(x) increases monotonically at r, -3> is f(lg1 100), f(.

3）f（lga）= 100

lga-1 = 100

lga）/ a = 100

lga ^ =？Record 10 10 as the base 10 3 lg a = 10 bases in the log 3a

3a logs to 10 3a = 3

It's a = 3

Won't ask for it.

Let A have x and B have y.

3x+4y=705

4x+3y=716

The solution is x=107 and y=96

That is, there are 107 monkeys in group A and 96 monkeys in group B: (716 4-705 3) (4 4-3 3) = 107 (pieces) B: (705-3x) 4 = 96 (pieces).

The total number of monkeys in the two groups of A and B:

716+705) 7=203 (only).

Number of monkeys in group B: (according to each monkey eating 3 peaches, the more peaches eaten is the monkey that eats 4 peaches) 705-203*3=96 (only).

Number of monkeys in group A: (according to each monkey eating 3 peaches, the more peaches eaten is the monkey that eats 4 peaches) 716-203*3=107 (only).

or 203-96=107).

Solution: Let the two groups of monkeys A and B each have x and y.

3x+4y=705

4x+3y=716

Solution: x=107

y=96

(705+716) 7=1421 7=203 (A and B have a total of 203).

B: 705-203*3=705-609=96 (only).

A: 203-96=107 (only).

Because the number of morning and evening is exactly the opposite, so the difference between the two groups of monkeys is 716-705 11, and the number of peaches fed twice is average, and a group of monkeys has to feed 7 and peaches, which is also the average number of monkeys, so half of the addition and subtraction of 11 is used to get 96 and 107. That's the number of two groups of monkeys. I don't use the equation, I hope to adopt it.

Let A have x and B have y.

3x+4y=705

4x+3y=716

The solution is x=107 and y=96

Neither will I, but I can understand your feelings.

Establish a planar Cartesian coordinate system.

Think of the original y as the sum of the distances (x,0) from (x,0) to (0,1) and (x,0) to (3,3).

on the x-axis. If you want a distance and a minimum, just do (0,1) the symmetry point (0,-1) about the x-axis and connect (0,-1) and (3,3), and the distance between the two points is the minimum value of y———5

Rectangular ABCD area = 120

Rectangle ABEF area = 60, o is the intersection of EF, FG, CF=6, triangle EFO+OGH=10*4 2+5*2 2=25, so shadow area = 60-25=35

Connect EF and remember that the intersection is m

then EF=10 because EF is parallel to GH

So GHM is similar to FEM

gh=1/dc

If the similarity ratio is 1 to 2, then the corresponding high ratio is also 1 to 2

So the area of EFM is 10*4*1 2=20 GHz, and the area of EFM is 5*2*1 2=5

So the shaded area is 60-20-5=35

The area is 45. If it's right, I'll give you another step.

Let EH and FG intersect at the point O, and connect FE, and the triangle EOF is similar to the triangle HogBecause gh=1 2dc, the similarity ratio of the triangle is 1:2, gh=5, ef=10, the perpendicular line perpendicular to ef through the o point, the intersection of ef at the point m, gh at the point n, easy to get om=4, on=2, so the area of eof is 20, the area of goh is 5, the area of the shaded part = the area of cdef - the area of eof - the area of goh.

The area of the shaded part is 36

Connect EF

EH and FG are handed over to O

The triangle EFO is similar to the triangle gho, and the height of the two triangles is H, HGH ef=h H=1 2

h+h=6h=2h=4

The area of the triangle EFO is 5*4 2=10

The area of the triangle GHO is 5*2 2=5

The EFCD area is 6*10=60

The shaded area is 60 10 5 45

Solution: sina:sinb:sinc=( 3+1):(3-1): 10

a:b:c=( 3+1):(3-1): 10, let a, b, c are: ( 3+1), (3-1), 10, get the maximum answer on the c side, c is the maximum.

According to the formula of Cartesian coordinates to the polar coordinates.

x=ρcosθ

y=ρsinθ

2）ρ²sinθcosθ=a

3）ρ+2sinθ=0

4）ρ²cos2θ=a²

The actual amount of money received by the company is x yuan, which is obtained by the title, x(1+9%) 5=70 1189 to get x=54093 yuan.