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Not sure what it does?
What are the specific requirements.
And some other information?
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The landlord's narrative is a little problematic. After deletion, the data will be displayed in a column, and the data should be displayed in a row after deletion.
That's what happens when you delete print 2. because, print 2, b(i, j); It is to write the value of the element b(i, j) to file 2 ("the preceding drive letter path is to save the file to the current directory where the program file is located"), and does not wrap, and the subsequent output item is "compact" output.
Print 2, on the other hand, has no specific output and is followed by no semicolon or comma, which means that a line break will be output. In this way, because it is in the outer loop, there will be n lines of data in the output file, otherwise, there will be only one line without a line break in between.
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Take a look at these intrinsic functions and you'll know the result.
The answer is as follows: 2nd floor, a) 160
b) Today is: 10-17
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VB try it and the result will come out? Also asked here.
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dim a, b, c, d, e, f, g, h, i as integer
private sub rmbcound(byval rmb as double)
a = int(rmb / 100)
b = int((rmb - a * 100) / 50)
c = int((rmb - a * 100 - b * 50) / 10)
d = int((rmb - a * 100 - b * 50 - c * 10) / 5)
e = int((rmb - a * 100 - b * 50 - c * 10 - d * 5) / 1)
f = int((rmb - a * 100 - b * 50 - c * 10 - d * 5 - e * 1) /
g = int((rmb - a * 100 - b * 50 - c * 10 - d * 5 - e * 1 - f * /
h = int((rmb - a * 100 - b * 50 - c * 10 - d * 5 - e * 1 - f * g * /
i = (rmb - a * 100 - b * 50 - c * 10 - d * 5 - e * 1 - f * g * h * /
end sub
private sub text1_keydown(keycode as integer, shift as integer)
if keycode = 13 and isnumeric( then
call rmbcound(val(
print "100 yuan [.]" & a & "] sheets" &
50 yuan [.]" & b & "] sheets" &
$10 [.]" & c & "] sheets" &
5 yuan [.]" & d & "] sheets" &
1 yuan [.]" & e & "] sheets" &
5 corners [.]" & f & "] sheets" &
1 corner [.]" & g & "] sheets" &
5 points [.]" & h & "] sheets" &
1 point [.]" & i & "] sheets"
end if
end sub
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1. True 2, false, (2*3)>=5 is true, 12 3<=4 is true, true and true is true
3. Wrong, when a line cannot be written and needs to be written in line breaks, you need to add spaces and underscores at the end of the line".
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1, to 2, to 2, true, true and true to true
3. Wrong, you need to add spaces and underscores at the end of the line".
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Haha, this kind of is called the "Reach Out Party".
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You don't have to write it to him, it's just ......, don't be depressed :)
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VB is really programmed on click, if you want to learn VB, you can buy a book to learn by yourself, the textbook of our freshman year is a programming practice course, edited by Yin Jianxin, if you are interested, you can take a look.
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The demand has been received, so pay attention to the mailbox when the time comes!
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Your ** is not clear.
In the upper right corner, is it 1800 or 1600 yuan?
A few days ago, I met a similar one to you, and the salary range was "missing a ...... in the middle."
What should I do if it is below 2000 and above 1800 (is it 1800 that I can't see clearly)?
Set the focus. For example, if you make the text box text1 focus in the program, you can enter the text directly in the text box without clicking the text box with the mouse to make it focus before entering the content. >>>More
The data is stored in binary form in the computer, the decimal integer can be accurately converted to binary form, and there will be an error when the decimal number of the non-integer number is converted to a single-precision number or a double-precision number, and the non-integer number is used as a cyclic variable, and the step is also a non-integer number, so the number of cycles may not be as desirable. Therefore, you should avoid using non-integer numbers to control the loop. >>>More
Hehe, it's too simple, and there are many ways. Here's the simplest example: >>>More
Can absolutely my family too.
VB2005. >>>More
dim a as string 'Define variable a as a string.
dec_to_hex = "" 'The variable dec to hex is stored in decimal to hexadecimal is the result, and the initial value is an empty string do while dec > 0'If the decimal number dec to be converted is greater than 0, it goes into a loop. >>>More