The root number math problem of the first volume of the first volume of the first 3 is urgent!

x*x*x*x+2x*x+1=

x 2+1) 2 = x 2+1>0 and followed by |x*x+1|-|x*x+3|=-2<0 contradicts and has no solution.

If you are not limited to the junior high school level, you can still solve it, and the solution is as follows.

x 2 + 1 = -2 gives x 2 = -3, then there is x = - root number 3 * j (j is an imaginary number).

If the absolute value sign is followed by (x 2+1)-(x 2+3), because x 2 cannot be negative, so (x 2+1) is less than (x 2+3), then the equation is negative, but before the equation is x 4+2x 2+1= (x 2+1) 2=x 2+1

Then the number before the equation is positive, and the number after the equation is negative, so there is a problem with the question.

x 4 = x to the power of 5.

x*x*x*x+2x*x+1=

x 4+2x 2+1 = recipe.

x^2+1）^2=

Because (x 2+1) must be greater than 0.

x^2+1）^2

x 2+1 again it =|x*x+1||-x*x+3|So x 2+1=|x^2+1|-|x^2+3|Because (x 2+1) must be greater than 0

So |x^2+1|=x^2+1

So x 2+1=(x 2+1)-|x^2+3|-x^2+3|=0

x^2+3）=0

x 2 = 3x = plus or minus root number 3

There's a problem on the right side of the equation, isn't there a mistake?

Left = x*x*x*x+2x*x+1= (x 2+1) 2=x 2+1 (x squared plus 1).

x*x+1|-x*x+3|What do you mean.

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Problem cavity slag description:

Let the integer part of the root Zen conjunction sign 5 be a and the decimal part be b, and find the value of the root number 5 (a square + a b).

Analysis: a=2 b=(root number 5)-2 root number 5 (a square + a b) = root number 5 (4+2 root number 5-4) = 10

Compare the size of the two sides.

Let's not look at the minus sign for a comparison:

Of course 47 50

Then: add the minus sign, and the big one turns out to be small:

Everything outside the root number is moved into the root number:

3 2 also has a cuboid volume of 25 cm3, ab

The ratio of the three sides of c is 2

13. Find his surface area a

The ratio of the three sides of BC is 2:1:

3. Let the three sides of ABC be: 2x, x, 3x∴

2x· x3x=

6x³x³= 25/6

x = 25/6 36

of the cube root. Then, surface area =

2【（2x x）+（2x

3x）+（x

3x）】22x²

22· (25/6 36.)

of the cube root.

55/3 three root number 30.

The original is (x+1)*(x-1)=x 2-1

x to root number 2-1

Perfectly squared publicity brings in answers 2-2 root number 2

The original formula is simplified to x 2-1

For example: (a-b) 2 c=(a 2+b 2-2ab) c 2 can be calculated according to the above formula x 2 = 3-2 times the root 2

Then x 2-1 = 2-2 times root 2

Because they are quadratic radicals, x-y=2, i.e., x=2+y, substitute x=2+y into x+y-1 and 3x+2y-5.

2y+1 and 5y+1 because they are the same kind of radical so.

2y+1=5y+1 so y=0 x=2 thanks.

Because it is the same radical, x-y=2. So x=y+2x+y-1=2y+1 3x+2y-5=5y+1 because they are the same radicals, so the two of them are equal 2y+1 =5y+1. So y=0 so x=2 complete

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Good afternoon, dear, I'm glad to answer for you [happy] Quadratic radicals: Generally, formulas are called quadratic radicals. The knowledge points of the quadratic radical formula of junior high school mathematics are summarized and noted:

1) If this condition is not true, it is not a quadratic radical; (2) is an important non-negative number, ie; Important formulas: (1), (2) 3The arithmetic square root of the product:

The arithmetic square root of the product is equal to the product of the arithmetic square root of the factors in the product; 4.Multiplication of quadratic radicals:5.

The method of quadratic radical comparison of sizes: (1) the approximate value is used to compare the sizes; (2) Move the coefficient of the quadratic root formula into the quadratic root number, and then compare the magnitude; (3) Separately squared, and then compared to the size. 6.

The arithmetic square root of the quotient: , the arithmetic square root of the quotient is equal to the arithmetic square of the divided** to the arithmetic square root of the dividing formula. 7.

The division rule of quadratic radicals: (1); (2);(3) The method of rationalization of the denominator is as follows: the numerator of the fraction and the denominator are multiplied by the rationalization factor of the denominator, so that the denominator becomes an integer.

8.The simplest quadratic radical: (1) the quadratic radical that satisfies the following two conditions is called the simplest quadratic radical, the factor of the open square is an integer, the factor is an integer, and the open square does not contain an endless factor or factor that can be opened; (2) In the simplest quadratic radical, the number of the square cannot contain decimals and fractions, and the number of letter factors is less than 2, and there is no denominator; (3) When simplifying the quadratic radical, it is often necessary to decompose the number of the open square first into the factor or factor; (4) The final result of the quadratic radical calculation must be reduced to the simplest quadratic radical.

10.Homogeneous quadratic radicals: After several quadratic radicals are converted into the simplest quadratic radicals, if the number of squares is the same, these quadratic radicals are called homogeneous quadratic radicals.

12.Mixed operations of quadratic radicals: (1) The mixed operations of quadratic radicals include six algebraic operations: addition, subtraction, multiplication, division, multiplication, and square, and all formulas and arithmetic laws within the range of rational numbers that have been learned before are applicable to the mixed operations of quadratic radicals; (2) The operation of the quadratic radical should generally be appropriately simplified first, such as:

It can only be merged if it is the same kind of quadratic radical; Division: Sometimes it is easier to convert the denominator to rationalize or reduce the denominator; Use multiplication formulas, etc.

Solution: From r=6400km, h=, d= 2hr

16 (km), A: The value of d at this time is 16km

Original = [(6 35) 6 35)] = 6 35 6 35 2 6 (35) = 12 2

Principle; Square the original first and then open the square = the original.

To do this kind of problem, you have to come out of the square under the root number, and you can only square it, so you have to make it completely flat in the way. Do the math yourself.

You're right to calculate x 2-1, but x = - 3 3 you don't simplify 6 = 2 * 3

6- 3 3= 2* 3- 3 3 Then the numerator denominator is divided by 3 at the same time, and the value is constant.

Then bring in x 2-1 and get: ( 2-1) -1 = 2 -2 2+1-1 (actually the same as the perfect square formula for positive numbers, except with a root number) Note: 2 = 2

The answer is 2-2 2

I'm doing this process for parsing, and I hope you can adopt it.

The original formula is simplified to x 2-1

For example: (a-b) 2 c=(a 2+b 2-2ab) c 2 can be calculated according to the above formula x 2 = 3-2 times the root 2

Then x 2-1 = 2-2 times root 2

The original is (x+1)*(x-1)=x 2-1

x to root number 2-1

Perfectly squared publicity brings in answers 2-2 root number 2

You're simplifying wrong

x= 6- 3 3 up and down multiplied 3= 18-3 3

x-1)^2+2(x-1)

The side length is twice as long, and the area is four times as long. Here's why:

Let the original side length be a, then there is:

2a)^2/a^2=4

If you want to double the area, the side length should be twice the original root number. You can get the result by listing it like the equation above.

Faint ......The new altar is 4 times larger (2a on the side, 4a on the side).

The side length should be 2a (the side length is 2a and the area is 2a).

√1<√2<√3<√4

The decimal part of 2 is (2-1).

The decimal part of 3 is (3-1).

2·a+√3·b-

The integer part of 2 is 1 and the decimal part is (2-1).

The integer part of 3 is 1 and the decimal part is (3-1).

2·a+√3·b-5

2*(2-1)+3*(3-1)-5 are counted as brackets.

Got - (2 + 3).

1< 2< 4 i.e. 1< 2<2, the decimal part of 2 a= 2-1;

In the same way, the decimal part of 3 b= 3-1, 2*a+ 3*b-5= 2*( 2-1) + 3*( 3-1)-5= - 2- 3