Elementary 1 math problems solve them with equations and write a written description of which step

Answer:1silver coins.

If this dress is worth x money, the reward for one year is x+10 and the monthly reward is equivalent to (x+10) 12

There are still 5 months left to complete the year, so 5 months' remuneration is deducted, which is 10-2 = 8 silver coins.

2.List price 320 yuan.

Set the list price to be X yuan, profit margin = profit cost 100%.

Profit = Cost = 250 Substituting the above formula, we get:

3.12 per carton.

Assuming that there are x products per box, the products produced by type A machine for one day are: 8x+4 One machine A produces one day: (8x+4) 5

The products produced by the B-type machine for one day are: 11x+1 The production of a non-B machine for one day is: (11x+1) 7

Each type A machine produces 1 more product a day than the type B machine, then:

4.Answer: After 2 hours, the speed is equal and the speed of the car is 70 km/h.

Let the speed be the same after x hours, and after x hours, the speed of a large car is: 30+20x the speed of a small car: 90-10x

Vehicle speed = 30 + 2 * 20 = 70 km/h.

1) The per capita quota is less than 45

Let the per capita quota for this month be x, then there are:

The total amount of work in Group A is: 4x+20 The total amount of work in Group B is: 6x-20

The per capita workload of group B = (6x-20) 5, and the actual per capita workload of the two groups is: (4x+20+6x-20) (4+5)=10x 9

x<45

2) Quota per capita = 35

4x=140 x=35

3) Quota per capita = 55

4x=220 x=55

Solution 1: Let the clothes be x silver coins, and according to the equation that the average monthly salary is equal, we get x+10) 12=(x+2) 7 ...Average salary per month.

The solution is x=46 5=

A: This dress is worth silver coins.

2. If the price of each piece of this commodity is X yuan, then the equation can be listed according to the relationship between the sales of each piece at the time of 9% off, and x* the sales amount of each piece.

The solution is x=320

A: The price of this kind of product is 320 yuan per piece.

3.If there are x products per box, the daily production of each type A machine is:

8x+4)/5;

Then the daily production products of each type B machine are:

11x+1)/7;

According to the two machines, each type A machine produces 1 more product a day than the type B machine per day, and the equation can be obtained.

8x+4) 5=[(11x+1) 7]+1 gives x=12

A: There are 8 products per carton.

4. If the speed of the two cars is equal after x hours, the speed of car A after x hours is 30+20x;

Then the speed of car B after x hours is 90-10x;

Now the speed of the two cars is equal, then the equation is obtained.

30+20x=90-10x

The solution is x=2, and the speed of the vehicle is 30+20x=30+20*2=70

A: After 2 hours, the speed of both cars is equal. At this time, the speed is 70 km/h.

5.If the per capita quota for this month is x, the average workload of Group A is: (4x+20) 4;

Then the average workload of group B is: (6x-20) 5;

1) The actual per capita workload of the two groups of workers in this month is more than that of group B, i.e., x>(6x-20) 5

Solution x>20

A: The average quota per person for this month is more than 20.

2) The average monthly workload actually completed by the workers in group A is 2 more than that of group B, that is: (4x+20) 4=[(6x-20) 5]+2 solution x=35

A: The per capita quota for this month is 35 pieces.

3) The average monthly workload actually completed by the workers in group A is 2 pieces less than that of group B, that is: (4x+20) 4=[(6x-20) 5]-2 solution x=55

A: The per capita quota for this month is 55.

1. If he does not work for five months, he will lose 8 silver, then his salary for a month is 8 5, and his salary for a year is 12 (8 5) = silver, and the price of his clothes is.

2, set the price is x, 250 (1 means the purchase price profit x=3203, let the output of the machine in row b be x, a box of y, then the output of machine A is x 1y=[5(x+1)-4] 8 5 (x+1) means the output of machine A in a day, 4 means just 8 boxes left, 8 means how many boxes are in 1 box.

y=[7x-1] 11 has the same meaning as above.

x＝19 y=12

3. Let the speed be the same after x hours, 30 20x 90 10x 30 20x represents the speed of 20 per hour, the speed after x hours, 90 10x means the speed of 10 per hour, and the speed after x hours.

x=2, the velocity is equal after 2 hours, the velocity at this time is 30 2 20 705, rewrite the question again, there is ambiguity.

Give you an equation to solve by yourself, middle school students do more by themselves, not to mention that the x in it is not explained is all problems.

1. (x+10)/12=(x+2)/7

2. x*3. 8x+4-1=11x+1

4.After x hours, 30+20x=90-10x speed is 30+20x(x*4+20) 4>(x*6-20) 3 5(x*4+20) 4=(x*6-20) 3 5+2(x*4+20) 4=(x*6-20) 3 5-2

Solution: Set this dress x silver coins.

x+10) divide 12 times 7 = x+2 by yourself, x+10 is a year, dividing 12 is a month, multiplying 7 is seven months minus 2.

Solution: Set x per box.

The per capita quota is x

4x+20]/4=[6x-20]/5

x=45 i.e. the per capita quota is: 45 pieces.

If the average workload of workers in group A is 2 more than that of group B, then what is the per capita quota for this month?

4x+20]/4-[6x-20]/5=2

x=35 i.e. the per capita quota is: 35 pieces.

If the average workload of the workers in Group A is 2 pieces less than that of the group, then what is the per capita quota for this month?

6x-20]/5-[4x+20]/4=2

x=55 means that the quota is: 55 pieces.

1.(10-2) (12-7) = 8 5 (RMB) Monthly remuneration.

8 5*7-2=23 5 (yuan) The price of clothes.

You can know that the remaining 5 months' salary is 8 silver coins, that is, a silver coin month, and the 12 months of silver coins 12 * silver coins Then the ** of a piece of clothing is a silver coin.

Set the price x to set the equation as well.

That is, the equation can be solved.

X=360 set the daily product quantity of type A machine is A, type B is B, each box of products is X, 5 sets of type A machine are full of 8 boxes of products a day and there are 4 left: that is: 5A=8X+4

After 7 B-type machines fill 11 boxes of products in a day, there is still 1 left: that is: 7b=11x+1

Each type A machine produces 1 more product a day than the type B machine: then there is: a-b=1

Simultaneous can be solved: x=68

4.A large car, which used to travel at a speed of 30 kilometers per hour, now begins to accelerate evenly by 20 kilometers per hour, and a small car, which used to travel at a speed of 90 kilometers per hour, now begins to decelerate evenly, decelerates by 10 kilometers per hour. How long does it take for two cars to have equal speed?

What is the speed of the car?

If the time is set to t hours, the speed of the car after t hours is 30+20t and the speed of the car is 90-10t

It can be combined 30+20t=90-10t

The solution is t=2, and the speed of the vehicle at this time is 70km h

Example: Solve the equation 2x 2+4=6x 1 2x^2-6x+4=0 2.

x^2-3x+2=0 3. x^2-3x=-2 4. x^2-3x+ （

Add the wheel to 3 and a half squared, and at the same time -2 should also add the square of the 3 half of the sedan so that the two sides of the equation are equal) 5(a 2+2a+1=0 i.e. (a+1) 2=0) 6 7.

x1=2 x2=1 (a quadratic equation usually has two solutions, x1 x2).

Solution: If the purchase price is X yuan, the price will be X + 45 yuan.

x+45)×x=155

A: The purchase price is 155 yuan, and the price is 200 yuan.

Solution: If the purchase price of each handicraft is X yuan, the original price is X + 45 yuan.

x+45)*

I tidy it up and get it. x=155

155 + 45 = 200 (yuan).

The purchase price of each handicraft is 155 yuan, and the original list price is 200 yuan.

Solution: 1. If the purchase price of the calculator with a profit of 60% is x yuan, then its profit is x 60%, because it is a profit of 60 yuan. Therefore, the equation can be listed.

x×60%=60

Solution x=100

2. If the purchase price of the loss-making 20% calculator is Y yuan, then its loss is Y 20%, because it is a loss of 60 yuan. Therefore, the equation can be listed.

y×20%=60

The solution is y=300

Add the two items, i.e. 100 + 300 = 400

A: This store spent a total of $400 on these two calculators.

This store buys a profit calculator for x yuan, and a loss of y yuan x = 100

20%y=60

y=300, this store can get into these two calculators, a total of 60 + 300 = 360 yuan.

Solution: Suppose this store buys a profit calculator for x yuan, and the other loses y yuan to solve x=100

The solution is y=300

Then this store needs to spend 60 + 300 = 360 yuan to buy two calculators, I am in the second year of junior high school, please believe my answer.

I hope my answer is helpful to you.

Profit 60 means that the profit is 60 at the purchase price

So the purchase price is 1 = 60 60 = 100 yuan.

In the same way, the loss is 20, that is, the loss of money is 20 of the purchase price, and the purchase price is 2 = 60 20 = 300 yuan.

Solution: Set the purchase price of the profit to be X yuan, and the purchase price of the loss to be Y yuan.

From the question, 60 x = 60 x = 100

20％y=60 y=300

x+y=100+300=400

A: It costs a total of 400 yuan.

1)a+b=0, xy=1, original formula=-32)8x12+4=10 2, (n-2)x(n+2)+4=n 2

3) Height = 20x20x20 (100x5) = 16cm4) Set Hui Zhi Qi Qi Qi grade to participate in x people: Qianzi with 6x+8(65-x)=400520-2x=400

2x=120

x=60

12+4=10 squared (n-2) (n+2)+4=n squared.

20 20 Eliminate 100 5

400-6 65) (8-6).

1.-3 2.Outline. 3) I'm out of time, I'll write you the full answer another day!

1.Set 1 class with x size

x*75%=60 x=80

Class 2 has a Y size

x*50%=60 y=120

80 people in Class 1 and 120 people in Class 2.

2.Set the four raw materials for x tons, 3x tons, 10x tons, and 4x tons.

x+3x+10x+4x=36x=2

Cement, sand, gravel, and water are each 8 tons.

3.Let the total length be Wu slag x

x-x/2-(x/2)*(1/3)=40

x/3=40

x = 120 The total length of the embankment in this section of the Orange Mountain section is 120 meters.

If the average donation per person in the seventh grade is x yuan, then the average donation of the elderly in the eighth grade is x + 1 yuan, and the number of his people is 452-12.

So the equation is 452x+(452-12)*(x+1)=11144452x+440x+440=11144x=12, let the jelly and chocolate be x, y respectively, then the system of equations is established:

x+y=40

2x+3y=115

So x=5, y=35

Set up x and y large and small boats, and establish the Fang Huaicheng group:

x+y=17

10x+4y=

So x=10, y=7

If the two reservoirs A and B originally had x and y tons of water each, then establish a system of equations:

x+y=400

x+4=y-8

So x=194, y=206

Let the number of people be x and basketball ** be y, then a system of equations is established

10x-y=2

y-9x=6

So x=8, y=78, so the price of the basketball is 78 yuan.

Set up x people in the school and Y people in the private house, then build a system of equations:

x+y=160

146+x=3(78+y)

So x=142, y=18, so there are 142 people who go to school.