Elementary 2 Science Buoyancy Questions. I want to be clear about the process

Answer: Question 1:

To simplify the process, there are no units in the solution.

Let the mass of A and B be the same m, then, the volume of A v1 = mass density.

The volume of m B v2 = m

Because they are all put into the water, the density of the water is 1, which is obtained according to the buoyancy formula:

A's buoyancy: B's buoyancy = f A: f B = v1*1: v2*1 = 2:3 Question 2: Take two objects of the same volume A and B and throw them into the water, f A: f B = 1:1

Let the mass of A and B be the same m, then, the volume of A v1 = mass density.

The volume of m B v2 = m

Because they are all put into the water, the density of the water is 1, which is obtained according to the buoyancy formula:

A's buoyancy: B's buoyancy = f A: f B = v1*1: v2*1 = 2:3 Question 2: Take two objects of the same volume A and B and throw them into the water, f A: f B = 1:1

The force of the two objects is the same: f pulls vertically downward, g vertically downward, buoyancy vertically upward, and when the force is balanced, it is satisfied: f float = g + f pull, it can be seen that the pull force = f float - g;

The tension of the two balls is the same, so there are: fm-gm=fn-gn, water*g*vm- m*g*vm= oil*g*vn- n*g*vn, water-m)vm=(oil-n)vn, because, water-oil n, so, (water-m)>(oil-n), so, vmgmChoose A

I think the first floor is very right, and the process and the answer are the same as mine, but there are additions

Upstairs came to the conclusion GN>GM though correct

But according to fm-gm=fn-gn in the argument

fm-fn=gm-gn is obtained

And knowing gm, so fm-fn<0 fm should be selected as described above

This is my supplement only to recommend the landlord to take the first floor for

1. When the wooden block is completely pressed into the water, the buoyancy is calculated according to the volume of water discharged by the wooden block, f float = p water * g * v wood.

2. When the wooden block is stationary, the wooden block is only affected by gravity and buoyancy, and f float = g wood can be obtained.

G-wood = p-wood * v-wood * g

Buoyancy f = weight of drained water = 1nQuestion 2: f=mg=

f float = g matter (air) - g object (in water).

54n-34n

20nf float = p liquid v discharge g

V row = F float (p liquid g).

20n (100kg m (cubic) 10n kg) m matter = g g g =

P = m v .

Cubic) kg m3

A: It's made of aluminum.

Solution:1F float g g liquid 54n 34n 20n 2

F float p liquid v row g, 20n = 1000kg m3 v v row 10n kg, v row = 3m g g g=54kg, P = m V 2700kg m3, so it is aluminum.

1), buoyancy 20 N, (2) cubic meters, (3) the ball is made of aluminum.

f float = g - f pull. 54-34 = 20 N. Float pg = 20 N multiplied by 10 cubic times 10 N per kilogram = 2 times 10 minus 3 cubic meters... Kilograms divided by 2 times 10 to the minus 3 power = multiplied by 10 to the 3rd power, so it is aluminum.

Because it floats, so F float = g total = mg = (1500 tons + 5 10 3 tons) Ox kg = 63700000 N , the displacement of the ship refers to the total mass of the water discharged by the ship according to the Archimedes principle f float = g row, and the ship is in a floating state, it can be judged according to the knowledge of the balance of two forces: f float = g total, so it can be determined that g row = g total, so m row = m total = 1500 tons + 5 10 3 tons = 6500 tons.

Each bamboo can provide a maximum of buoyancy for cattle.

5 is 16,000 oxen.

So the number of passengers (including driving) = 16000 600 = , take 26 people as long as they do not sink, the buoyancy of the bamboo raft is equal to the full gravity.

f float = liquid v row g = number of people = (person) Because floating, the buoyancy force is equal to the gravitational force.