Liberal Arts Mathematics Ensemble Questions, Math Ensemble Questions

Updated on educate 2024-04-11
20 answers
  1. Anonymous users2024-02-07

    If the number of people who participate in AB is X, then the number of people who only participate in A is 33-X, and the number of people who only participate in B is 33-X, and the number of people who do not participate in AB is more than one-third of the number of people who participate in AB: the number of people who do not participate in AB is (X 3) + 1, and the total number of people is 50.

    So the column equation: (x 3)+1+(33-x)+x+(30-x)=50, get x=21, so the people who only participate in A and do not participate in B are: 33-21=12 people, the number of people who only participate in B and do not participate in A is 30-21=9, and the number of people who do not participate in AB is 21 3+1=8 people, over!

  2. Anonymous users2024-02-06

    Draw a Venn diagram.

    Let the part where A and B intersect is X, that is, the number of people who participate in both AB is X, then the number of people who do not participate in A and do not participate in B is 1 3X+1

    The number of people who only participate in A and not in B is 33-x

    The number of people who only participate in B and not in A is 30-x

    The sum of the four terms = 50 x + (1 3x + 1) + (33-x) + (30-x) = 50

    Solution x=21

  3. Anonymous users2024-02-05

    X is neither A nor B.

    Y is all participating.

    Equation: a+b-y+x=50

    1/3*y=x+1

    Solve equations x=5,y=18

    Therefore, the number of people who only participate in A and those who do not participate in B is A-Y=33-18=15 people.

  4. Anonymous users2024-02-04

    Solution: Let the number of people who participate in AB be x, and the number of people who do not participate in AB is (1 3) x + 1.

    According to the meaning of the problem, the equation 33+30-x+(1 3)x=50 is obtained, and x=21

    So there are 21 people who participate in AB, and because the people who participate in A include those who participate in AB, there are 33-21 = 12 people who participate in A and do not participate in B. There were 9 people who participated in B and did not participate in A, and 8 people who did not participate.

  5. Anonymous users2024-02-03

    First of all, the " " sign in (2) is wrong, it should be (a b) c(1) because a={x丨-1=3

    Solution m>=-6

    Solution m<=-10 3

    Take the intersection to get -6<=m<=-10 3

    In summary, the range of m is -6<=m<=-10 3, that is, the interval [-6, -10 3].

    Will you?

  6. Anonymous users2024-02-02

    infinity, -1 3) (1, +infinity).

    a∩b=(-1,-1/3)∪(1,3)

    a∪(crb)=a∪[-1/3,1]

    Root number (m +64)] 4

    m + root number (m + 64)] 4 3

    m<-10/3

    m-root number (m +64)] 4 -1

    m>-66<m<-10/3

  7. Anonymous users2024-02-01

    Draw a Venn diagram.

    Let the part where ab intersect is x

    That is, the number of AB participants is X

    The number of people who do not participate in A and do not participate in B is 1 3x+1

    Then the number of people who only participate in A and not in B is 33-x

    The number of people who only participate in B and not in A is 30-x

    Quadruple orange preparation = 50 x + (1 3x+1) + (33-x) + (30-x) = 50

    Solution x=21

  8. Anonymous users2024-01-31

    s: x<-1 or x>5;

    sut=rt: -1≤x≤5;

    3a should be to the left of -1 and a+8 to the right of 5, so that it will be r

  9. Anonymous users2024-01-30

    If you take the test in a small question, you may just give a few inequalities, and then find the range or something, if it is part of the big question, it is to define the domain and the interval.

  10. Anonymous users2024-01-29

    As shown in the figure below, because A+8 must be 5, A must be -1, and the union of s and t can get R

  11. Anonymous users2024-01-28

    Question 17 is generally trigonometric functions or sequences, 18 questions are probability and statistics, 19 is solid geometry, 20 is basically a conic curve, 21 is a derivative, choose 1 out of three

  12. Anonymous users2024-01-27

    The answer to this question is as follows.

  13. Anonymous users2024-01-26

    The intersection of the two shades is the set sought.

  14. Anonymous users2024-01-25

    The intersection is to take the range of two ranges that coincide.

  15. Anonymous users2024-01-24

    Intersection is the part that is included in two intervals at the same time, the common part of the two, this kind of simple problem that already knows the interval, draw a number line, draw the two intervals separately, and look at the superimposed parts of the two.

  16. Anonymous users2024-01-23

    Are you good at Chinese? If you have a good understanding of the language, you will be able to do it quickly.

  17. Anonymous users2024-01-22

    Because these are two sets, x and y are just symbols, and have no real meaning, as long as they correspond to the numbers.

    A set of words:

    The set is the value of x, x belongs to r, and has nothing to do with y, so the set in a is the rb set

    The set is full of y, but y is related to x, because x is in the range of 0, and all y is 1

    So the intersection of a and b is a set of 1 and a set of real numbers r.

    It can be expressed as, of course it can also be expressed as, and it can also be at the same time.

    Do you understand??

  18. Anonymous users2024-01-21

    The x and y are just symbols and can be replaced with other symbols.

    a: x belongs to r

    b:y 1 can replace them with t

    Then t 1 is generally used to represent the solution in x, so replace t with x.

  19. Anonymous users2024-01-20

    One is x and the other is y refers to the content of the set, a set is equivalent to finding the definition domain of y=x+1 that is, r, and b set is equivalent to finding the value range of y=x 2+1, i.e., b=, so a b=r =, if you don't understand, you can ask again.

  20. Anonymous users2024-01-19

    Draw and then you look at the range, whether it's x or y

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