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Your question is not right, there is no such mask, the valid last octet mask should be: 0, 128, 192, 224, 240, 248, 252, 254, 255
The number of hosts corresponding to these masks should be 256-x-2. where x represents the mask.
The so-called mask is in a mask, that is, cover.
The computer has a 32-bit three-layer IP address, such as 11000000 10001100 00000001 00000001
Converted to a point system, it is.
Match it with a mask: 11111111 11111111 11111111 100000000 ( or 25).
The corresponding number of hosts should be "2 to the seventh power"-2=126
7 This party is because the mask indicates that from the 32-bit address, the first 25 bits are the network components and the last 7 bits are the host components.
The -2 above indicates that one subnet address and one broadcast address are subtracted.
If there is anything wrong, please point it out.
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The encyclopedia is very clear, you can take a look! There's no need to ask people all the time.
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Let's keep it simple.
A valid last octet mask should be: 0, 128, 192, 224, 240, 248, 252, 254, 255
Other books say it's okay, but it's not recommended.
The numbers above are characteristic, and if you convert them to binary, for example, 192 is 11000000
That is, the first two digits are 1, followed by 0, and 224 is three 1s, followed by 0
If it's 192, then the first 2 bits are 1, the IP address in a subnet, and the last section (host number) is converted to binary, and the first 2 bits must be the same.
To put it another way, if the subnet mask is 128, then his subnet has 256-128-2 (excluding the head and tail), and the remaining 126 IPs are 2-127 or 130-255
If it's 192, the subnet has 256-192-2 =62, 2-63 or 66-127 or 130-191 or 194-255
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Dividing the IP address into two parts, the network number and the host number, the designer must decide how many bits each part contains. The number of bits of the Wangluo number directly determines the number of networks that can be allocated (calculation method 2: the number of bits of the network number); The number of digits of the master number determines the maximum number of hosts in the network (calculation method 2: the number of bits of the host number -2). However, since the entire Internet may contain large or small networks, the designers have finally chosen a flexible solution:
How to figure out its network number. Host number.
This is more convenient from a binary point of view.
The IP address and mask are combined to obtain the network address, and the first 24 bits of the address (the number of masks 1) are supplemented with 0 to get the network address.
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Convert both the IP address and the subnet mask to binary, and the part of the IP address corresponding to all 0 of the subnet mask is the host bit sensitive number.
If it is coincidentally one, it is 2 broad-branched hosts, and if it is two, it is 4 hosts.
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Such as subnet masks.
1. It is 01111001101011110001010100001001 that the IP address is converted into binary
2. It is 11111111110000000000000000000000 to convert the subnet mask into binary
3. Match the IP address with the subnet mask, and you can get that the network number part is 0111100110, and the host number part is 1011110001010100001001
An IP address is a 32-bit binary number that is usually split into 4 "8-bit binary numbers" (i.e. 4 bytes). IP addresses are usually expressed in the form of "dot decimal", where a, b, c, d are decimal integers between 0 and 255.
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The host number is calculated in binary form.
Such as IP subnet masks.
1. It is 01111001101011110001010100001001 that the IP address is converted into binary
2. It is 11111111110000000000000000000000 to convert the subnet mask into binary
3. Match the IP address with the subnet mask, and you can get that the network number part is 0111100110, and the host number part is 1011110001010100001001
4. Expansion: The broadcast is any network number, and the host number is all 1, so just change the host number to 1, so it is: 01111001 10111111 11111111 11111111
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The host number is calculated in binary form.
Such as subnet masks.
1. The IP address is converted to binary.
2. The subnet mask is converted to binary.
3. Match the IP address with the subnet mask, and you can get that the network number is 01111001
10. The host number part is 101111
4. Expansion: The broadcast is any network number, and the host number is all 1, so just change the host number to 1, so it is: 01111001
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The IP address is, ie.
The subnet mask is: , ie.
Do the operation of IP address and subnet mask, ie.
The network address of the IP is.
take the subnet mask ( and operate, its IP is .
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is a Class C address, the default mask is, and the new mask indicates that the subnet is divided.
All 1 on the left identifies the network bits, all 0s on the right side identify the host bits, and the new mask network bits borrow 2 from the host bits, and the identities are divided into 2 subnets to the 2nd power = 4.
Bit change, corresponding to IP
All bits of the host 1 are broadcast addresses.
The first to fourth subnet range, excluding the network address and broadcast address of each subnet, each subnet has 2 fewer available IPs.
Available host addresses.
Available host addresses.
Available host addresses.
Available host addresses.
To find the network address, take the first subnet as an example, convert the new mask and IP into binary, and then calculate the network address (the subnet).
Network address.
All bits of the host 1 are broadcast addresses.
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Subnet mask. and IP addresses.
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