How is the trigonometric function calculated in the displacement

Depending on the type of question, there are generally three ways to find the period:

1. Definition: The title mentions f(x)=f(x+c), where c is a known quantity, then c is a minimum period of this function.

Example: Turn left|Turn right.

2. Formula method.

Trigonometric functions.

The function relation is formulated as: y=asin(wx+b)+c or y=acos(wx+b)+c, where a,w,b,c are constants. then the period t=2 w, where w is the angular velocity.

b is the phase angle and a is the amplitude. If the function relationship is formulated as: ACOT(wx+b)+c or tan(wx+b)+c, then the period is t= w.

Example: Turn left|Turn right.

3. Theorem: If f(x) is a function of several periods.

Algebraic and formal, i.e., the function f(x) = f1(x) + f2(x), and the period of f1(x) is t1, the period of f2(x) is t2, then the period of f(x) is t=p2t1=p1t2, where p1, p2n, and (p1, p2)=1

f（x+ p1t2）=f1（x+ p1t2）+f2（x+ p1t2）

f1（x+ p2t1）+ f2（x+ p1t2）

f1（x）+ f2（x）

f(x)p1t2 is the period of f(x), and in the same way p2t1 is the period of the function f(x).

ps: When t is the period of a trigonometric function, nt is also the period of this trigonometric function. where n is a positive integer that is not 0.

Example: Turn left|Turn right.

Calculated using the Pythagorean theorem. Because the angle AOB is a right angle.

The derivation is as follows: let the object move in a straight line with uniform acceleration, the acceleration is a, and the velocity through time t is greater from v0 (initial velocity) to vt (end velocity).

1. The formula of uniform acceleration average velocity v average = (vt + v0) 2....1

2. The displacement formula s=v average*t=(vt+v0)t 2....2

3. Acceleration formula: a=(vt-v0) t obtains: t=(vt-v0) a substituting 2 formula.

obtained: s=(vt+v0)t 2=(vt+v0)(vt-v0) 2a

If an object moves from the initial position to the last position in a certain period of time, the directed line segment from the initial position to the last position is called displacement. Its magnitude is the straight-line distance from the initial position to the last position of the moving object; The direction is from the beginning position to the last position.

The displacement is only related to the beginning and end position of the object's motion, not the trajectory of the motion. If the particle returns to its original position after a period of time during motion, then the distance is not zero and the displacement is zero.

x=x2-x1 (last position minus initial position) It is important to note that the displacement is a straight-line distance, not a distance.

In the International System of Units (SI), the principal unit of displacement is: meters. In addition: centimeters, kilometers, etc. The displacement formula of uniform variable speed motion is: x=v0t+1 2·at 2

Inference of the velocity and displacement of the uniform variable velocity: x=vot+ at

Note: v0 refers to the initial velocity vt refers to the terminal velocity.

AC 500 is obtained from Gougu's theorem, so the displacement length is 1100. The direction is the angle between AD and the horizontal plane (90 a).This angle is equal to the angle ACB is equal to arc tan ab bc

I can't see your image clearly, next, substituting the numbers you should understand. If ab bc is 4 3, the direction of displacement is 53 degrees to the horizontal plane. If it is 3 4, it is an angle of 37 degrees.

It is possible to connect two points of AB. Because the radius is equal to 50, the displacement ab is 50 times the root number 2, and the distance is two factions r 3 4. Hope.