7 items how to find defective products to use several times

Updated on society 2024-04-14
8 answers
  1. Anonymous users2024-02-07

    How to find defective items for 7 items takes 2 times. Knowing the severity of defective products can be so few times. The way to ensure that defective products are found and the number of symmetries is to divide the items to be tested into 3 groups.

    For example, the remainder after dividing by 3.

    For 2, the remaining 2 are assigned to two groups, first let the two groups be symmetrical, flat, then take the third group into 3 groups (when there are more than 3), and repeat the appeal method. If the remainder is 1, assign the remaining 1 to the group that does not perform the first symmetry, and then do the same as if the remainder is 2. In this way, for every 2 times (3 times the original increase), the number of symmetries is increased by 1 time.

    Grouping principle: when using the balance to find defective products, ensure that the minimum number of times to find out the basic methods and skills of defective products. Divide the items to be tested into 3 parts.

    If it can be divided equally, it will be divided into 3 equal parts; If the score cannot be equalized, the difference between the more and the less points should be only 1. In this way, it is possible to ensure that the least number of weighings can be used to find defective products.

  2. Anonymous users2024-02-06

    The problem of finding defective products is regular.

    Generally, it is divided into three parts: a, a and b. b may be equal to or may be equal to a+1 or a-1, depending on the total.

    Put two A at both ends of the balance, if the balance is balanced, the defective product is in the B, if the balance is unbalanced, then find out which part of the defective product is according to the difference between the defective product and **.

    Once you've found it, continue to divide it into three parts.

    For 7 items, divide them into 2 for the first time, 2 and 3. Find out if it's in 2 or 3.

    You can find out the second time.

    Because 7 is special, it can also be divided into 3, 3, 1, and 3 parts.

    If you're lucky, you'll find it in one of them.

    If it's in 3 pieces, you need to weigh it again.

    To sum up, it should be said at least 2 times.

  3. Anonymous users2024-02-05

    The description is too simplistic. If there is only one defective product, and it can be displayed by weighing, etc.

    Divide things into 3 and 4 to see which side does not match the weight, and the defective product is on which side, and then divide it again.

  4. Anonymous users2024-02-04

    A minimum of one and a maximum of six.

  5. Anonymous users2024-02-03

    The number of times a defective product is found depends on many factors, such as the type of product, quality standards and manufacturing process. However, in general, in order to ensure the high quality of the product, it is often necessary to carry out multiple inspections and screenings. Therefore, the number of times a defective product is found can be determined by the situation.

    In the manufacturing process, if there are some steps that are prone to carry-over problems, then it needs to be inspected more frequently and more times to find defective products. However, if the production process is very well developed and there is enough automated equipment to help with inspection, then the number of defective product searches can be reduced.

    In addition, manufacturers need to determine product quality standards based on the type of product and market requirements. For example, for some high-precision mechanical products, more frequent inspections and screenings are required to ensure perfect workmanship and functionality. For some basic products, it is possible to inspect them a smaller number of times and determine their compliance standards.

    Finally, the number of defective products is related to the frequency of enterprise replacement. With the development of technology and the acceleration of modernization, companies need to launch new products faster to meet the needs of the market, which requires more testing and screening processes to ensure that the quality and performance of products meet the standards.

    In short, there is no definite standard for the number of times you can find defective products. It depends on factors such as the type of product, quality standards, and manufacturing processes. However, in order to ensure the high quality of the product, manufacturers need to check and screen as much as possible. <>

  6. Anonymous users2024-02-02

    From the meaning of the title, I think that the quality of defective products is not the same as that of **, assuming that the defective products are lower than the ** quality, then.

    I weigh it on a scale for the first time, and I put 450 parts on the left and right sides respectively, and the defective product is on the light side.

    For the second time, divide the 450 parts containing the defective product into two parts, and place 225 parts on the left and right sides of the balance.

    Weigh the third time, and put 112 parts on the left and right sides of the balance.

    Weigh the fourth time, and put 56 parts on the left and right sides.

    Weigh the fifth time, and put 28 parts on the left and right sides.

    Weigh the sixth time, and put 14 segments on the left and right sides respectively.

    Weigh the seventh time, and put 7 parts on the left and right sides.

    Weigh the eighth time, and put 3 parts on the left and right sides.

    Weigh the ninth time, and put 1 grip sock part on the left and right sides.

    Therefore, I think that by weighing at least nine times a fierce reed on a scale, this defective product will be found.

  7. Anonymous users2024-02-01

    1.Know whether the defective product is heavy or light.

    1st 1 - 17 - 17

    17 vs 17 equal weight, then 1

    17 vs 17 Unequal weight, choose the side in question (depending on whether the problem is heavy or light) and score 1-8-8

    2nd 1 - 8 - 8

    8 vs 8 equal weight, then 1

    8 vs 8 Unequal weight, choose the side in question (depending on whether the problem is heavy or light) and score 2-3-3

    3rd 2 - 3 - 3

    3 vs 3 equal weight, then 2, again, for a total of 4 times.

    3 vs 3 Unequal weight, then choose the side in question (depending on whether the problem is heavy or light) Score 1-1-1 Again, a total of 4 times.

    2.I don't know if the defective product is heavy or light.

    1st 3 - 16 - 16

    16 vs 16 equal weight, then 3 points 1-1-1 up to 2 times to find the defective product.

    16 vs 16 unequal weight, each divided into 8 - 8 & 8-8, find the side with different weights, up to 2 times to find the defective pile, and you can know whether the defective product is light or heavy.

    a:8 b:8 c:8 d:7+1

    Take two piles of A, B and other weights = > ab for normal products, then take a bunch and compare them with A, and the weight or light of C+D indicates the weight or light of defective products.

    Take two more piles of a, c equal weight = > ac for normal products, then d is a defective pile.

    Unequal weight = > c is the defective heap.

    Take two piles of A first, B unequal weight => ab is the defective pile, then take another pile and compare it with A, and the weight or light of A+B indicates the weight or light of the defective product.

    Take two more piles of a, c equal weight = > ac for normal products, then b is a defective pile.

    Unequal weight = > a is the defective heap.

    So far, it has been used up to 3 times.

    The 4th, followed by 8 defective piles.

    Look for 2 - 3 - 3 again.

    3 vs 3 equal weight, then 2 is divided into 1-1 and then 1 time to find out, a total of 5 times.

    3 vs 3 unequal weight, take the defective product pile and divide it into 1-1-1, 1-1 equal weight, the third is the defective product, 1-1 is unequal, and the problem side is the defective product, a total of 5 times.

    Therefore, know whether the defective product is heavy or light, up to 4 times.

    It is not known whether the defective product is heavy or light, up to 5 times.

  8. Anonymous users2024-01-31

    The rule of thirds can be used to find out the defective product as quickly as possible.

    That is, the item is divided into three parts each time, and two copies of the same quantity are weighed and inspected.

    If the weight is the same, the defective product is in the third part; Otherwise, the defective product is in the lighter one.

    defective products are known to be lighter).

    600 items - >200->66 or 67->22 or 23->7 or 8->2 or 3-> to find the defective product, at least 6 times to find the defective product.

    n items have a defective product, at least m times to find the defective product, can be by equation 3 (m-1) 1800, at least 7 times can find the defective product.

    4578 pieces, at least 8 times can find out the defective product.

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