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Shaft power = (flow head.
density) (3600 102 efficiency).
The shaft power is the effective power, which is the power left by the motor after removing the slip, and then removing the power after various losses.
Efficiency is divided into: mechanical efficiency.
Volumetric efficiency, hydraulic efficiency. Mechanical efficiency refers to the loss of disc friction, etc., volume refers to the loss of leakage, and hydraulic refers to the loss of friction of the medium. This efficiency is going to have different methods depending on the pump.
There is no one-size-fits-all formula for calculating efficiency, it is all corrected. If you want to know more about this, it is recommended to take a look at Guan Xingfan's modern pump technology manual, which is very detailed, because there are too many contents, I can't list them here.
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Pump power (kw) head h (m) flow rate q (cubic meters per second) flow weight (water is calculated as 1000) efficiency (take 70---90) 102
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Due to various losses in the operation of the pump, the actual (effective) pressure head and flow rate of the pump are lower than the theoretical value, and the power input to the pump is higher than the theoretical value.
In general, the efficiency of a pump is the ratio of the effective power of the pump to the shaft power. η=ne/n
The power input to the centrifugal pump by the motor is called the shaft power of the pump, which is denoted by n.
The effective power can be written as ne = qh g
Wherein, the effective pressure head of the h pump, that is, the energy obtained from the pump by the unit volume of liquid in the gravity field, m;
q Actual flow rate of the pump, m3 s;
Liquid density, kg m3;
ne The effective power of the pump, i.e., the mechanical energy obtained by the liquid from the pump per unit of time, W.
The efficiency test of the pump is determined by experimentation. The relationship between flow rate q and head h, shaft power n and efficiency is measured through experiments, and the characteristic curve is drawn, and the working principle of centrifugal pump is as follows
After the centrifugal pump is started, the pump shaft will drive the impeller to rotate at high speed, forcing the pre-filled liquid between the blades to rotate, and under the action of inertial centrifugal force, the liquid moves radially from the center of the impeller to the periphery.
The liquid medium gains energy during the movement of the impeller, resulting in an increase in the static pressure energy and an increase in the flow velocity. When the liquid leaves the impeller and enters the pump casing, it decelerates due to the gradual expansion of the flow channel in the casing, and part of the kinetic energy is converted into static pressure energy, and finally flows into the discharge pipeline in a tangential direction.
When the liquid is thrown from the center of the impeller to the periphery, a low-pressure area will be formed in the center of the impeller, and the liquid will be sucked into the center of the impeller under the action of the difference between the liquid level of the tank and the total potential energy of the center of the impeller. Thanks to the continuous operation of the impeller, the liquid is continuously sucked in and discharged. The mechanical energy obtained by the liquid in the centrifugal pump ultimately manifests itself as an increase in hydrostatic energy.
Power and efficiency of centrifugal pumps:
Due to various losses in the operation of the pump, the actual (effective) head and flow rate of the pump are lower than the theoretical value, and the power of the input pump is higher than the theoretical value, and the effective power can be written as ne = qh g
Wherein, the effective pressure head of the h pump, that is, the energy obtained from the pump by the unit volume of liquid in the gravity field, m;
q Actual flow rate of the pump, m3 s;
Liquid density, kg m3;
ne The effective power of the pump, i.e., the mechanical energy obtained by the liquid from the pump per unit of time, W.
The power input to the centrifugal pump by the motor is called the shaft power of the pump, which is denoted by n. The ratio of effective power to shaft power is defined as the total efficiency of the pump, i.e.
NE N Obviously, when the flow rate q is 0, the effective power Ne is 0. The efficiency is also 0, why is the shaft power n not 0? Because the motor is still spinning at this time, the power of the motor input to the centrifugal pump is still there, although relatively small.
Let's take a look at the classic centrifugal pump characteristic curve in the figure below
As can be seen from the figure, it is obvious that when the flow rate is 0, the shaft power n is not 0, and the efficiency is 0
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There can be a variety of reasons for the drop in centrifugal pump power. Here are some common reasons that can lead to a drop in pump power:
Worn or damaged impeller: The impeller is a critical component of a centrifugal pump and is responsible for transferring kinetic energy to the liquid. Wear or damage to the impeller can lead to a decrease in the efficiency of the pump, resulting in a drop in power.
Blockage or blockage: Blockage or blockage may occur at the inlet or outlet of the pump, resulting in a decrease in liquid flow. This can be due to solid particles, dirt, or other impurities. The reduced flow rate affects the power of the pump.
Poor Pump and Motor Misalignment: Poor alignment between pump and motor can lead to excessive vibration and wear, which can reduce pump efficiency and power.
Bearing wear: Wear on the pump's bearings can lead to a larger gap between the rotor and stator, reducing the pump's efficiency.
Seal wear: Wear and tear of mechanical or packing seals can cause fluid leakage within the pump, reducing the efficiency and power of the pump.
Changes in the nature of the fluid being delivered: Changes in the viscosity, density, or temperature of the liquid can affect the operating efficiency of the pump, resulting in a drop in power.
Incorrect installation or operation: Incorrect installation or operation of the pump may result in it not operating under optimal operating conditions, reducing efficiency and power.
Solving the problem of centrifugal pump power degradation requires inspection and maintenance of the pump to identify the root cause of the problem. This could include removing blockages, replacing worn parts, adjusting pump and motor alignment, or optimizing pump operating conditions. With proper maintenance and repair of your pump, you can restore its normal power and efficiency, ensuring efficient, reliable operation.
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Impeller wear or impeller damage: After prolonged use, the impeller surface may wear out, which can lead to reduced pump performance and increased power. In addition, the impeller can also be damaged due to collision or physical damage, which can also lead to reduced pump performance and increased power.
2.Blocked inlet or outlet of the pump: If the inlet or outlet is blocked, it will reduce the performance of the pump and increase the power.
3.Damage to the pump's bearing or mechanical seal: If the bearing or mechanical seal is damaged, punching will increase the frictional resistance of the pump, resulting in a decrease in the performance of the pump and an increase in power.
4.Changes in the density or viscosity of the fluid medium: If the density or viscosity of the fluid medium changes, it will lead to a decrease in the performance of the pump and an increase in the power of the pump.
5.Failure of the drive motor of the pump: If the drive motor fails, it can lead to a decrease in the performance of the pump and an increase in power.
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The ant god you asked is itPowerDecline? The decrease in power is generally due to the wear of the pump, the gap becomes larger, and the volumetric power decreases. For example, the filter cylinder is blocked, the pipeline air intake is blocked, etcCentrifugal pump evacuation and idling, the power will also decrease, the efficiency will be reduced, this is possible, similar to the exhaust fan, if the air duct is blocked, the exhaust fan will also be evacuated, after the load is reduced, the power will decrease.
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The specific speed of a centrifugal pump refers to the ratio of the rotational speed of the pump wheel to the outlet speed of the pump, which is usually expressed in ns. Volume loss refers to the energy lost by the medium as it flows through the pump due to seepage causes such as friction, bending, etc., and is usually denoted by δ p. There is a certain relationship between the specific speed of a centrifugal pump and the volume loss, as follows:
When the specific speed is lower, the volume loss is smaller, and the efficiency of the pump is higher.
When the specific speed is higher, the volume loss is greater and the efficiency of the pump is lower.
Within a certain range, as the specific speed increases, the efficiency of the pump first increases and then decreases, and there is a maximum efficiency point.
When the specific speed exceeds the maximum efficiency point, the efficiency of the pump drops sharply, which is easy to cause vibration and noise of the pump.
Therefore, when selecting a centrifugal pump, it is necessary to determine the appropriate specific speed according to the actual situation to achieve the best efficiency and performance. At the same time, when running the centrifugal pump, it is also necessary to pay attention to controlling the specific speed and avoiding exceeding the maximum efficiency point to ensure the safe operation and long life of the pump.
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The specific speed is directly proportional to the volume loss.
In general, the greater the specific width reduction speed of the centrifugal pump, the greater the volume loss.
Specifically, the larger the specific speed of the centrifugal hood pump, the larger the flow rate of the pump, which means that the impeller size of the pump is relatively smaller, and the corresponding flow channel will be smaller, which can easily lead to an increase in the volume loss of the pump.
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Centrifugal pump is the most commonly used fluid transfer equipment with slag, and its working principle is to convert energy into pressure to make the liquid flow. In a centrifugal pump, the maximum flow rate that can be delivered is determined by the design of the pump and the inlet macro.
When the flow rate increases, the volume of liquid entering the centrifugal pump increases, resulting in a decrease in the pressure inside the pump while the outlet pressure of the pump remains the same. This smaller pressure difference means that the pump needs to produce less head, so the power of the pump decreases as the flow rate increases.
This phenomenon can be explained by the Bernoulli equation. According to Bernoulli's equation, there is a transformation of kinetic energy, pressure energy, and gravitational potential energy between liquid particles moving at different positions, namely:
p1/ρ v1^2/2 + gh1 = p2/ρ v2^2/2 + gh2
Among them, P1 and P2 are the pressure of the inlet and outlet of the pump, which is the density of the liquid, V1 and V2 are the flow rates of the inlet and outlet, respectively, and H1 and H2 are the height difference between the two positions and the equivalent height difference caused by the pressure-energy conversion.
When the flow rate increases, the flow velocity at the inlet increases, and the kinetic energy of the liquid also increases, while the flow velocity at the outlet does not change, so the kinetic energy of the liquid cannot be converted into more pressure energy. In this case, according to the Bernoulli equation, the static pressure at the inlet decreases, resulting in a decrease in the head required for the pump. As a result, as the flow rate increases, the power of the pump decreases.
In addition, as the flow rate increases, the resistance to the pump also increases, which results in a certain amount of loss and heat, which also leads to a decrease in power.
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Summary. A centrifugal pump with low power should be chosen. The specific speed of a centrifugal pump refers to the number of revolutions per minute, while the power refers to the power per minute.
Therefore, if you want to choose a centrifugal pump with low power, you should choose a centrifugal pump with a lower speed than the rotational speed. Workaround:1
First of all, the speed and power of the centrifugal pump should be determined according to the actual needs. 2.Then, according to the speed and power of the centrifugal pump, choose the appropriate centrifugal pump.
3.Finally, the centrifugal pump is installed and debugged to ensure the normal operation of the centrifugal pump. In addition, when choosing a centrifugal pump, the flow, pressure, temperature and other parameters of the centrifugal pump should also be considered to ensure the normal operation of the centrifugal pump.
A centrifugal pump with low power should be chosen. The specific speed of a centrifugal pump refers to the number of revolutions per minute, while the power refers to the power per minute. Therefore, if you want to choose a centrifugal pump with low power, you should choose a centrifugal pump with a lower rotational speed.
Workaround:1First of all, the speed and power of the centrifugal pump should be determined according to the actual needs.
2.Then, according to the speed and power of the centrifugal pump, choose the appropriate centrifugal pump. 3.
Finally, the centrifugal pump is installed and debugged to ensure the normal operation of the centrifugal pump. In addition, when choosing a centrifugal pump, the flow, pressure, temperature and other parameters of the centrifugal pump should also be considered to ensure the normal operation of the centrifugal pump.
Can you elaborate on that a little bit more?
Our answer to this question is: you should choose less power. The specific speed of a centrifugal pump refers to the number of revolutions per minute, while the power refers to the power emitted by the engine per minute.
Therefore, if the specific speed is higher, the power should be less and vice versa. In addition, there is an important relationship between the specific speed and power of the centrifugal pump, that is, the higher the specific speed, the lower the power consumption, and vice versa. Therefore, if a centrifugal pump is required to be more efficient, a higher stool beam specific speed should be chosen to reduce power consumption.
In addition, the specific speed and power of the centrifugal pump are also affected by the structure and material of the centrifugal pump. The more complex the structure of the chaotropic coarse and heart pump, the higher the specific speed and the higher the power consumption; The lighter the material of the centrifugal pump, the lower the specific speed and the lower the power consumption. Therefore, when choosing a centrifugal pump, the appropriate specific speed and power should be selected according to the actual situation.
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The specific speed of a centrifugal pump is not necessarily proportional or inversely proportional to the power size, and the relationship between them depends on the specific design and use conditions of the centrifugal pump. Generally speaking, the larger the specific speed of the centrifugal pump, the larger the flow rate corresponding to the cleaning and annihilation, the corresponding head of the cover cavity will be reduced, and the required power will also be reduced. Therefore, when selecting a centrifugal pump, it is necessary to determine the appropriate specific speed according to the specific use conditions and requirements to achieve the best results and economy.
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Hello <> dear! <>
<> the effective power of the centrifugal pump is, the efficiency of the pump is 60%, then the shaft power of the pump is 6kw. The efficiency of the pump and its calculation formula refers to the ratio of the effective power of the pump to the shaft power. =PE P The power of the pump usually refers to the input power, that is, the power transmitted by the prime mover to the pump shaft, so it is also called the shaft power, which is represented by P.
The formula for calculating the shaft power of the water pump is the centrifugal pump: flow x head xx medium specific gravity 3600 pump efficiency flow unit: cubic hour, head unit:
m p = nwhere h is the head. The unit mq is the flow rate and the unit m3 hn is the efficiency of the pump.
P is the shaft power, the unit is KW, that is, the shaft power of the pump P=PGQH 1000N(kW)where p = 1000kg m3g = the unit of specific gravity is kg m3, the unit of flow is m3 h h the unit of head is m1kg = Newton, then p = specific gravity * flow * head * Newton kg = kg m3 * m3 h * m * Newton kg = Newton * m 3600 seconds = Newton * m 367 seconds = watt 367.
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This digression can only be misleading!