Solving the math problem 1 Ellipse P 2 root number 2, 0 , Q 0, root number 5 to find the standard

Help you get it in the **, wait a minute.

Then, the first question is not very well understood......Did you say that the parabola crossed those two points? What does it have to do with the ellipse......

Unfortunately, when I saw the two words of the ellipse, I felt that I couldn't get points.

Obviously, p is the left endpoint and q is the upper endpoint of hand width.

A 2 Bi Xiliang 2, b 5

Therefore, the ellipse equation is found as:

x 2 8+y 2 Zen core 5 1

Calculate the sum of the distance from m to the two foci = 4, which is 2a so a = 2, and by the title, c = root number 2

Therefore b = root number argument 2

So the elliptic equation is x 2 4 + y 2 2 = 1

Let the equation be x 2 a 2 + y 2 b 2 = 1, and since the focal length is double with the sign 3, so c 2 = 3, so c 2 = a 2-b 2 = 3Then bring the point (with the sign 3, -1 2) into the equation to get 3 a 2 + 1 4b 2 = 1, and join the liquid equation system to get a 2 = 4, b 2 = 1, so the elliptic equation is x 2 4 + y 2 = 1, and the team will answer for you.

Obviously pq is on the axes, so it's the vertex.

So the focus is on the x-axis.

a=2√2b=√5

a²=8,b²=5

x²/8+y²/5=1

Let the elliptic equation x a y b 1

Two points are brought in:

That is: -2 root number 2 a 0 = 1

0 root number 5 b = 1

To solve the system of equations, find a, b,

Because it is a standard equation: from the meaning of the question: a=2 2, b=5

Then the equation is: x 8 y 5 1

Summary. If the elliptic focus is on the x-axis, and the root number 2 of c 2, e 2, then the elliptic equation is x2 8 + y2 4 1. The specific process will be sent by the teacher later**.

The elliptic focus is on the x-axis, and the root number 2 of c 2, e 2, find the elliptic equation?

If the elliptic focus is on the x-axis, and the root number 2 of c 2, e 2, then the elliptical square file hole is x2 8 + y2 4 1. The specific early dispersion process is sent by the old line of the dry division**.

The core examines the relevant knowledge points of ellipses.

The hyperbola is focused on the x-axis, and c 4, e 2, find the equation for the hyperbola?

First of all, the true/false question type is elliptical. Secondly, we read the question with a smile and found that we can go from the pre-shot value of E to A. Then, according to the square difference, the clear is struck to b. Finally, let's go straight to the elliptical to get the answer.

The ellipse is the sum of the distances from the plane to the fixed point f1 and f2 equal to the constant grinding (greater than the age of the key bucket |f1f2|F1 and F2 are called the two foci of the ellipse. The mathematical expression is: |pf1|+|pf2|=2a（2a>|f1f2|）。

The area formula for the extended ellipse is = (pi) ab (where a and b are the long half-grip axis of the ellipse, and the length of the short-medium half-axis respectively). or Duan Peichai s = (pi) ab 4 (where a and b are the major axis of the ellipse and the length of the minor axis respectively).

Classmates, I'm sorry, the platform stipulates high numbers, and the line generation can only dress up and ask and answer, (the rest is to explain the analysis service of Chang Jinshan) or limit the teacher to help other children. The main reason is that the difficulty of high-number line generation is high, there are many knowledge systems, the amount of calculation is large, and it is time-consuming to explain. If you have a lot of problems, you can upgrade to the unlimited round service, one-on-one tutoring, and help you solve it at one time.

If not much, you can determine the cavity resistance to the cheapest.

If the hyperbola is focused on the x-axis, and c 4, e 2, then the equation for the hyperbola is x2 4-y2 12 1.

The sought disadvantage burns as an ellipse.

The equation can be x a +y b =1, and the points p (-2 root number two are fronted, 0), q(0, root number five) given by the problem is brought in.

Get {8 a = 1

5/b²=1

i.e. {a = 8

b =5 i.e. the equation is x 8 + y 5 =1

The one sought is an ellipse.

The equation can be x a +y b =1, and the points p(-2, root number two, 0), q(0, root number five) given by the problem are brought into {8 a = 1

5/b²=1

i.e. {a = 8

b =5 i.e. the equation is x 8 + y 5 =1

Let the elliptic equation be x 2 a 2 + y 2 b 2 = 1, bring in (2,0 under the root sign -2), and a 2=8 bring (0, 5 under the root number) into b 2=5, so the equation is x 2 8 + y 2 5 = 1

These two points are the focus of the ellipse and the coordinate axis, so the square of a = 8 and the square of b = 5, and the equation comes out.