Math Masters Advance! First Question!!

Old friend, this absolute value is the distance from the number to the origin on the exponential axis. Positive numbers and zeros are used as parentheses. If you have a negative number, you have to look at it as the opposite.

The usual way to remove absolute values is to discuss the positive and negative numbers in absolute values. It is to discuss when it is positive and when it is negative through equations or functions, which is the so-called piecewise function. There is also the square of the formula, remove the absolute value, and then solve it by substituting the whole and superimposing the formula.

Because of the topic, you send the specific topic to QQ and solve it at any time!! Wish!

It's very simple, if the absolute value is subtracted from the negative number, turn the number upside down and take it out of the absolute value, if it's a positive number, take it like that!! Let's think about it!! Do more questions!!

Positive numbers and zeros are used as parentheses.

If you have a negative number, you have to look at it as the opposite.

There's an absolute value.,Of course, we have to find a way to remove the absolute value.,For example, square first and then open the root.。。。 If the number inside the absolute value is.

If it is positive, use the absolute value as a parentheses, and if it is negative, remove the absolute value and add a negative sign before the number...

The absolute value of a positive number is itself, and the absolute value of a complex number is its opposite. In the specific operation, it is necessary to analyze it concretely. Actually, it's very simple, don't think it's too complicated.

The algebraic meaning of absolute values is: the absolute value of a positive number and 0 is itself, the absolute value of a negative number is its opposite, and the absolute value of 0 is 0. The absolute values of two numbers that are opposite to each other are equal.

The absolute value of a positive number is itself. The absolute value of a negative number is its opposite. , the absolute value is non-negative, 0. The absolute value of 0 is still zero. Positive numbers and zeros are used as parentheses.

If you have a negative number, you have to look at it as the opposite.

1. Higher-power calculation questions like this cannot be hard calculated. x=-1 3 gives you 3x+1=0 you get 3x 5+x 4=0, 3x 4+x 3=0 and so on.

The values in () in the following calculations are all 0

Original = (3x 5+x 4)-18x 4+12x 3+6x 2+9x+8

6(3x^4+x^3)+18x^3+6x^2+9x+8

6(3x^3+x^2)+9x+8

3(3x+1)+5

5 2.Let f(x)=x 4-ax 2-bx+2=(x+1)(x+2)(x 2+mx+n)=(x 2+3x+2)(x 2+mx+n).

It's better not to take it apart here. It is more troublesome to take apart 9 items. The coefficients are calculated by brain, and you can dismantle them.

Needless to say, the fourth-power ones. The coefficient of the cubic is 0. So m+3=0 and m=-3

The original formula becomes f(x)=(x 2+3x+2)(x 2-3x+n).

The coefficient of the quadratic is -aSo n+(-9)+2=-a

The coefficient of the primary square is -bSo 3n+(-6)=-b

The constant term is 2, so 2n=2

The solution yields n=1, b=3, a=6

3.Similar to the second question, the substitution coefficient method is also used.

f(x)-7=2x^3-3x^2+ax+b-7=(x+1)(2x^2+mx+n)

f(x)-5=2x^3-3x^2+ax+b-5=(x-1)(2x^2+px+q)

I won't do the specifics, just like the previous question, the coefficients of the terms of the same power are equal. List a few equations to solve a, b

You don't have to worry about too many unknowns!

4.This question is also similar to the second and third questions. From the question, x 4+6x 2+25=(x 2+mx+n)(x 2+ax+b).

3x^4+4x^2+28x+5=(x^2+mx+n)(x^2+cx+d)

Forget it, right? Because the coefficient of the cubic is 0, some unknowns can be calculated in one step. Give it a try.

5。Counter-evidence.

It is known by the title. a1, a2, a3 are solutions for f(x)-1=0.

So there is f(x)-1=k(x-a1)(x-a2)(x-a3)=0 (k is not 0).

If f(b)=1 then b is also a solution of f(x)-1=0. B is different.

Then f(x)-1=k(x-a1)(x-a2)(x-a3)(x-b)=0 must be true! (k is not 0).

In this way, f(x) must have kx 4 to the fourth power. Contradiction! And so the conclusion was confirmed.

What does that one on x mean.

2) Solution: OD is the bisector of AOCR.

doc=1/2＜aoc

OE is the bisector of COB.

coe=1/2∠cob

o is a point in a straight line.

aoc∠cob=180

doe=∠doc+∠coe=1/2＜aoc1/2∠cob=1/2（＜aoc

doc+∠coe=1/2（＜aoc

cob）=1/2x180=90

The conditions are wrong, right? It will be ao=76 bo-70???

This question can't be done, and the known conditions given are not enough! You take a good look at this question and send it back I'll do it I'm also a first-year junior high school student I'm okay with this study!

1. a/x+b/(x-1)+c/(x+1)=[a(x+1)(x-1)+bx(x+1)+cx(x-1)]/ [x(x-1)(x+1)]

(a+b+c)x²+(b-c)x-a]/ [x(x-1)(x+1)]

x²/ [x(x-1)(x+1)]

So there is a+b+c=1;b-c=0；a=0

The simultaneous solution yields a=0, b=c=1 2

2.The method is the same as in question 1.

3.Rational numbers and rational numbers are combined, and irrational numbers and irrational numbers are combined, and the essence is the same as in the first question.

I helped you find a very similar question (2) on the "Solution", the solution idea is the same You see, what will not be the question in the future, go to the solution to see, the above He Jue question library is very large, basically will not be the question are searched, mathematics, physics and chemistry have Zen poor posture, especially in the past years, the exam questions, mock questions, textbook questions, and the answer to the Qing limb case is very detailed, there may be similar questions without the original question, I wish you progress in learning, come on.

1、-x-2

3. T questions are incomplete.

to the nth power = s mm.

s=n squared n>1

If n=6 then s=64

Thickness: Fold in half 5 times.