C is a method of summing two numbers in C

#include ""

void main()

int numerator = 2, denominator = 1;Numerator is the numerator and Denominator is the denominator.

float total = 0, temp;

for (int i = 1; i <= 20; i++)temp = numerator / denominator;

total += temp;

denominator = numerator;

numerator = numerator + denominator;

printf("total = %", total);

The result is: total =

I'm also a beginner, and if you learn C++, you can see if this is okay in C.

#include

void main()

double a=2,b=1,i=0,sum=0;

dosum+=a/b;

a+=b;b=a-b;

i+=1;while(i<20);

cout<<"sum="<·· return 0, if the above is not possible, you can change it to this and try it.

The programming ideas and methods of using C language to write a sum of two numbers are as follows:

1.First of all, you need to define three variables a, b, and c, two of which are the numbers that are added, and the third is the sum obtained by the addition.

2.The scanf() statement is then used to receive the two numbers entered from the splitting keyboard and assign values to the variables a and b.

3.Guess the object and perform an addition operation on a and b, and assign the result to the variable c.

4.Finally, use the printf() statement to display the result on the screen.

5.**After the writing is completed, click Run to see the running results of the program Spike Source Liquid in the debugging window.

C language: Recursively summing the value of f(n) can be as follows:

#include

int sum(int n)

int main()

#include

int sum(int n)

int main()

It's roughly like this.,I'm not debugged.,zhi you try dao.

c Recursive approach.

The idea of copying is copied.

Class method members are allowed to call each other, and they can also call themselves by themselves. The du-like method is either direct or dao in the body of the fangzhifa

Indirectly calling oneself is called a recursive method.

The basic idea of recursion is to "invoke oneself". The recursive approach actually embodies the idea of "and so on" and "repeat with the same steps", and it can solve some complex computational problems with simple programs.

Recursive calls are particularly effective for completing factorial operations, series operations, power exponential operations, and so on.

When performing recursive operations, C stores the information from the recursion process in the stack. If you recursion indefinitely, or too many times, you get a "stack overflow" error.

Example: Use the recursive method to find factorials. The mathematical formula used is n!=n*(n-1)!。When n=0, n!=1。

**As follows: public

longf(intn)

Made with arrays, high-precision algorithms. Each element of the array puts a bit, e.g. a[0] for single bits, a[1] for tens, and so on.

Here's how the algorithm works:

c[0]=(a[0]+b[0])%10;c[x] is the result, a[x], and b[x] are the two additives.

overflow=(a[0]+b[0])/10;overflow is the value of the carry.

for(i=1;Of course, you should pay attention when reading, because the number of bits is too large, you can read it as a string, and then separate it by bits. (There may be other ways, not to enumerate) to give an example.

The unit digits are added c[0]=(a[0]+b[0])%10=(7+7)%10=4 and carry overflow=(a[0]+b[0]) 10=1

The addition of the ten digits c[1]=(a[1]+b[1]+overflow)%10= (8+8+1)%10=7 carry overflow=(a[1]+b[1]+overflow) 10=1

Hundreds, additive, c[2]=(a[2]+b[2]+overflow)%10=(9+0+1)%10=0, carry overflow=(a[1]+b[1]+overflow) 10=1

。The following is an analogy.

It's a math function, and you can include the header file.

a[100] is to define 100 elements, the subscript range is 0-99, you use 100 to cross the main requirement and there is no return value, but you return

c, that's not right.

To do it with an array, char[100] does the trick.

scanf("%d，%d",&a，&b);

The (comma) in this statement indicates incorrect!

Also note: 1. When entering, the two numbers are separated by commas;

2. When the program runs the input number, you should pay attention to the change of the input method, if ("%d，%d") is (,), the output result will also be incorrect;

3、scanf("%d，%d",&a，&b);The comma in (&a,&b) should be (,) must be consistent with the comma format of the C program, otherwise you will get an error!

The specific procedure is as follows:

Form 1: include

int main()

Form 2: include""

void main()

If you have any questions, please feel free to ask them again!

There should be nothing wrong with this program, except that when you enter two numbers, you should separate them with commas, and the values of a and b should be entered correctly.

When you enter a and b, they should be separated by a comma, otherwise if you enter 23 33, the value of b will record the value represented by the space between 23 and 33.

#include ""

main()

The two numbers are separated by a comma when entered.

When entering, the two numbers can be separated by a comma , or the two numbers can be removed ("%d，%d", & comma in the middle.

Did you type and hit enter?

C implements parallel summation algorithms:

1. Problem description.

Divide array a evenly into m fragments, and each array fragment has a maximum of (n+m-1) m elements. Each fragment of the array is partially summed by a thread, and the sum of the parts adds up to the sum of all the elements in the array.

2. Writing.

3. Precautions.

Dynamic array types are not allowed in the C language. For example, it is a mistake to use a variable to represent the length and want to dynamically state the size of the array. In this case, malloc is used to request the system to allocate a memory space of a specified size.

The void* type can be cast to any other type of pointer.

void type conversion

Malloc returns a type of void*: this does not mean that there is no return value after the function is called, but the address of a node is returned, and the type of the address is void, that is, the first address of a storage area, and its specific type cannot be determined, only according to the data of each domain value when used. It can be converted to another type by force.

Apply to the system for 10 contiguous int storage spaces, and use the pointer pi to point to the first address of the contiguous space. And use (int*) to convert the return type of malloc in order to assign the address of the int type data to the pointer pi.

For example: int *pd=null;

pi=(int *)malloc(n*sizeof(int)).

If you want to use a loop calculation, then the program is already complete and can be calculated correctly. For example, you want to calculate 1+2+3+......100, you should enter:

What are you asking? Please add.