C programming, enter three integers to find the largest one

1 Enter three numbers.

2 Compare the first two to get the greater of the first two.

3 Compare the higher value with the third number to get the maximum value.

4 Outputs. ** Below:

#include <

int main()

int a,b,c,m;

scanf("%d%d%d", &a,&b,&c);Enter three numbers.

m = a>b?a:b;

if(m

main()

int x,y,z,t;

scanf("%d%d%d",&x,&y,&z);

if(x>y)

t=x;x=y;y=t;}

if(x>z)

t=x;x=z;z=t;* Save the smallest number in x * if(y>z).

t=y;y=z;z=t;}

printf("%d",z);

z is the largest number.

int main()

int arr[100]=;

int n=0;

scanf("%d",&n);

for(int i=0;imax)

max=arr[i];

maxindex=i;

if(arr[i]min=arr[i];

minindex=i;

printf("The maximum value is %d and the position is %d",max,maxindex+1);

printf("The minimum value is %d and the position is %d",min,minindex+1);

return 0;

In addition, the virtual machine group is on the product**, which is super cheap.

Three numbers are larger than the size of the C language programOutput Maximum:

#include <

void main()

int a,b,c,max

scanf("%d %d %d",&a,&b,&c)if (a <= b)

max = b

elsemax = a

if (max <= c)

printf("%d",c);

else<>

Meaning:

Enter three numbers (separated by spaces), compare the size of the first two numbers, assign the larger number to max, and then compare the size of max with the third number to output the larger number.

Enter three numbers, determine the first two numbers, assign the number to max ab, assign the small number to min ab, and compare max ab with c. If c is greater than or equal to max ab, then c, max ab, min ab are output, if c is less than max ab and greater than min ab, max ab, c, min ab is output, if c is less than min ab, max ab, min ab, c is output.