6th Grade Math Question Equation System! High score for answers.

x+1＜2 3x<1 x<1/3

2（x+3）-1≥5（x+1） 2x+6-1≥5x+5 0≥3x x≤0

So x 02, x-1 3x -1<2x x>-1 2x-1) 5 (x+1) 2 -1 5-1 2 x 2-x 5 -7 10 3x 10 x -7 3

So x>-1 2

x+5y=1 ①

2x-3y=-5 ②

3 5y+9y=16 y=8 7 Substituting or in the solution gives x=-11 14

5+ is not lost.

x 4+y 3=3 multiplied by 12 to get 3x+4y=36 multiplied by 10 to get 5x+2y=32

2 3x-10x=-7x=36-64=-28 x=4 substitute x=4 into or solve y=6

<1/3;

2x+5≥5x+5, 3x≤0,x≤0

So 1 3-1 2

1-1 x 2-x 5, -2 3x 10, x -20 3 so x>-1 2

3.Formula 2 x3 - Formula 14y=-14

y=1；x-1

4.One formula is y=9-3x 4 is substituted into two formulas.

x=4 and y=6

x+1＜22（x+3）-1≥5（x+1）

x<1/3

2x+6-1≥5x+5

0≥x0≥x

2、x-1＜3x

x-1 out of 5 x+1 out of 2

x>-1/2

2x-10≤5x+10

x≥0x≥0

x+5y=-1①

2x-3y=-5②

y=1 x=-1

x + y = 3 / 3

3x+4y=36①

5x+2y=32②

x=4 y=6

<1/3

3x<=0,x<=0

then x<=0

2x-2<=5x+5

3x>=-7

x>=-7/3

then x>-1 2

6x-9y=-15

14y=14,y=1

x=y=x=-6 If you make a mistake, yes.

then 3x+y=6x=4

x+1＜22（x+3）-1≥5（x+1）

Solution: 3x 2-1

3x＜1x＜1/3

2x+6-1≥5x+5

2x-5x≥5-5

3x≥0x≤0

x≤0、x-1＜3x

x/5-1≤x/2+1

Solution: x-3x 1

2x＜1x＞-1/2

x/5-x/2≤1+1

2x/10-5x/10≤2

3x/10≤2

3x≤2*10

x≥-20/3

1/2＜xx+5y=-1…….

2x-3y=-5………

Solution: From the can know:

6x=-1-5y

x=(-1-5y)/6…….

Bring in to:

2【(-1-5y)/6】-3y=-5

1-5y)/3-3y=-5

1-5y-9y=-15

14y=-14

y=1 brings y=1 into get:

x=-1x=-1、y=1

x/4+y/3=3……①

Solution: From the can know:

3x/12+4y/12=3

3x+4y)/12=3

3x+4y=36

y=(36-3x)/4……③

Bring in to:

36-3x) 20= Note:

36-3x)=54

3x=54-36

3x=18x=-6

Bring x=-6 into get:

y=(36+18)/4

y=54/4

x=-6、y=54/4

1, x is less than 1 3, x is less than or equal to 0 x is less than or equal to 02, x is greater than -1 2, x is greater than or equal to -20 3 x is greater than or equal to -20 33, x = -1, y = 1

4，x=-6，y=

x+1＜23x<1

Get x<1 3

2（x+3）-1≥5（x+1）

2x+6-1≥5x+5

0 3x x 0

2、x-1＜3x

1 2x gets x>-1 2

x-1)/5≤(x+1)/2

2(x-1)≤5(x+1)

3x 7 gets x 7 3

x+5y=-1

2x-3y=-5

Multiply the second equation by 3: 6x-9y=-15 and add it to the first equation.

Get -4y=-16, i.e. y=4

y=4 is substituted into the second formula: 2x-12=-5 gives x=7 24, x 4+y 3=3

From the second formula: y=(

Multiply the two sides of the first equation by 12: 3x+4y=36 to get 3x+54=36 x=-6

Teach me how to play symbols first.

.I'm also in the sixth grade, so why don't I seem to have studied these topics?

1. Let the team take x meters to the head of the team and take t seconds, then there is a time to come back, I don't know if you have learned the binary system of equations).

2. No matter how you dilute it, the salt content does not change, 5 * 20% = 1 kg, that there is 4 kg of water. It is necessary to add x kg of water.

then there is 1 (4+x)=15%.

3. Let the original width of the rectangle be x meters, then 20x (original area) (5 7) = 20 (x-4) (current area) perimeter = 2 (20 + x).

4. Let A and B be x y respectively

There is x+y=55 (1-3 5)x=y-6

If I can solve the equation, I won't solve it.

2. Calculate how much salt there is first.

5*20%=1 kg.

1 15% = 20 3, 20 3-5 = 5 3 kg.

3. Let the original width be x

20x*5/7=20(x-4)

x = 14 circumference is equal to 2 (20 + 14) = 68

4. If A has x kg of grain, then B has 55-x

1-3/5)x=55-x-6

x=35 So A is 350,000 kilograms and B is 200,000 kilograms.

Let this rope be x meters long.

The length of the first cut is (20%x+3) meters.

The length of the second cut is (1 3x-2) meters.

There are 6 meters left. From the equation x-(20%x+3)-(1 3x-2)=6, the solution of x=15 meters is obtained.

This rope is x meters long.

x-(20%x+3)-(1/3*x-2)=6x=15

The rope is 15 meters long.

Car B is 80 100 80 times the speed of car A, when car A has traveled 50, car B has traveled 50 * 80 40 from place B, and the difference is 1 40 60 of the whole journey

This 60 is 54 kilometers.

The distance is 54 60 90 km.

When car A arrives at place B, car B has traveled 80% of the whole journey, and it can be seen that the speed of car B is 80% of car A;

Therefore, when car A has traveled 50% of the whole journey, car B has traveled 40% of the whole journey, and car B is still 54 kilometers away from place B, and this 54 kilometers is 60% of the whole journey, so the whole journey between car A and car B is 54 60% = 90 kilometers.

When car A reaches 50%, car B is still 54 kilometers away from place B, and when car A reaches place B, car B travels 80% of the whole journey. It shows that car A is still at 40% when car B reaches 50%, 40% = 54, and this (40%=54) is regarded as 1, so 100% = multiplied by 40 = 100 is the whole process.

Solution: Set up a big monk x people, a small monk (100-x) people.

2x+(100-x)*

2x+x=40 has 40 big monks and 60 small monks.

Hello: Solution: Set up a big monk x people, a small monk (100-x) people.

2x＋（100－x）÷2＝110

2x＋50－

x 40 big monks 40 people, small monks have: 100 40 60 (people).

2x+(100-x)/2=110

2x+x=40 40 big monks, 60 small monks.

2x+(100-x)/2=110;

3x/2=110-50=60;

x=40;There are 40 big monks and 60 small monks.

Solve the equation and find x, such a simple problem for children, it is better to do it yourself and have enough food and clothing!!

Do it yourself like plagiarizing the answer and go to go on your own xiangdemei

8/9x-100=5500

Solution: 8 9x=5500+100 (-100 becomes +100.) ）

x=5600 9 8 (Divide by 8 9, divided by a number equals multiplied by its reciprocal.) ）

x=6300

9/8x-100=5500

Solution: 9 8x-100+100=5500+100 (add 100 on both sides at the same time, the solution of the equation does not change).

9/8x=5600

9 8x divided by 9 8 = 5600 divided by 9 8 (both sides are divided by 9 8 at the same time, the solution of the equation does not change).

1x=6300

x=6300

The solution of the equation is 6300

Phase shift 8x 9 = 5500 + 100

8x 9 = 5600

Multiply 9 on both sides at the same time to remove the denominator.

8x=5600×9

8x=50400

Divide both sides by 8 at the same time to get.

x=6300

Eight out of nine x-100 = 5500

8/9 x = 5500 + 100

Eight out of nine x = 5600

x=5600 8/9.

Eight out of nine x-100 = 5500

8/9 x = 5500 + 100

Eight out of nine x = 5600

x = 5600 divided by eight out of nine.

x=6300

Eight out of nine x-100 = 5500

8/9 x = 5500 + 100

Eight out of nine x = 5600

x = 5600x nine-eighths.

x=6300 No, forgive me, (*hee-hee.

!None of this will happen!

Eight out of nine x-100 = 5500

8/9 x = 5500 + 100

Eight out of nine x = 5600

x=5600 8/9.

x=6300

1. A box is rectangular on the bottom and 2 squares and 2 rectangles on the sides.

The other type of box is a box with a square bottom and 4 rectangles on the sides.

boxes of the same shape, but with different lids).

The proportions of square and rectangle of the box are 2:3 and 1:4 respectively, and the two kinds of boxes have x and y respectively, which can be obtained.

2x+y=90

3x+4y=180

x=36,y=18

1) The bottom is square, and the four sides are rectangular. The bottom is rectangular, one square on the left and one on the left, and one on the front and back.

2) Solution: Set.

What the hell does this mean? ）