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Just make a Newtonian iterative formula and calculate it.
Algorithm idea: f(x)=9 x+5 x-92;
f'(x)=(9^x)*(2ln3)+(5^x)ln5;
x1=x0+f(x)/f'(x);
Arbitrarily specify an initial value x0, substitute the above equation to get x1, use x1, substitute x0, and then find x1 until x1-x0 reaches the accuracy you need, then stop the calculation.
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When encountering this kind of exponential equation problem, one is the same bottom, which is done with the properties of exponential functions;
There is another type of different bottom, which can be logarithmic on both sides.
The original form can be written as: 9 x + 5 x = 92
Take the logarithm of both sides: xlg9+xlg5=lg92
x(lg9+lg5)=lg92
xlg45=lg92
x=lg92/lg45=log45(92)
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Solution: According to the logarithmic properties, the original formula can be written as: 2xlg3+xlg5=lg92x(2lg3+lg5)=lg92; x(lg9+lg5)=lg92 ;
xlg45=lg92 ;Then: x=lg92 lg45 can get the final result by looking up the logarithmic table.
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Summary. Solution: According to the problem, it is decomposed as: 6x+15=95-2x6x+2x=95-15
8x =80
x=10Answer: The solution is that x is equal to 10.
3 (2x+5) = 95-2x. Untie.
Solution: According to the problem, it is broken down into only disturbances: 6x+15=95-2x6x+2x=95-15 8x=80 x=10Answer: The solution is equal to 10. Sell digs.
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3x is equal to 6xSubtracting 3/2x equals 3/2 x 5
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92-5x) 3 +(92-5x) 3 +x=38 solution: both sides of the equation are multiplied by 3 at the same time
92-5x+92-5x+3x=114
Merge similar items].
184-7x=114
7x=184-114
7x=70 divided by 7 on both sides of the equation
x=10
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92-5x ) 3+ (92- 5x) 3+ x = 38 remove parentheses 92 3 - 5x 3 + 92 3 -5x 3 +x=38Shift, merge like.
5x/3 + 5x/3)+x = 38 -(92/3 +92/3 )
7x 3 = 38 x 3 - 92 x2) 3 calculates 7x=70
The coefficient is one x=10
Or. 92-5x ) 3+ (92- 5x) 3+ x = 38 extract common factor (92-5x) (1 3 +1 3) + x=38 pass 2 (92-5x) 3 + 3x 3=38 shift terms, calculate 2 (92-5x) +3x=38 x 3=114 remove parentheses 184 -10x+3x =114
Combining homogeneous terms -7x=114-184=-70 is a x=10
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