My son s math problem bc abc ddd abcd how much does abcd represent

bc+abc=ddd, written in the specific form is 10b+c+100a+10b+c=100d+10d+d, that is, 100a+20b+2c=111d, and you can know that a, b, and c are all natural numbers, and a, b, and d are not equal to 0

When d = 1, there is no solution (in fact, you can know from both sides of the above equation that the value on the left is even, so d must be even).

When d = 2, c = 1, a = 1, b = 6 or c = 1, a = 2, b = 1, from this we get 61 161 222 or 11 + 211 = 222

Next, the values of d can be satisfied with the following conditions: 22 + 422 = 444, 72 + 372 = 444, 33 + 633 = 666, 83 583 = 666, 44 + 844 = 888, 94 + 794 = 888

So there are 8 groups in total, and if ABCD represents different numbers, then there are only 3 groups that meet the conditions, which are 72 + 372 = 444, 83 583 = 666, 94 + 794 = 888

d=a, or a+1.

If d=a, there are too many answers, and it seems that the question should not be like this.

d=a+1, to be carried, b=5,6,7,8,9.

a=1100+2bc=222 61,61+161=222a=2200+2bc=333 Impossible.

a=3300+2bc=444 72 ,72+372=444a=4 impossible.

A = 5 500 + 2BC = 666 83, 83 + 583 = 666A = 6 is impossible.

a=7700+2bc=888 94,94+794=888a=8 impossible.

a=9 is not possible.

Obviously a=2, then d=8 and then b=0 c=7

Step by step, if a is not equal to 2, the number will not start with 1, and if d does not wait for the book to be rented at 8, the number will not end with a or 2. Since the first two digits are 18, then b is only equal to 0, since d = 8 b = 0 then 8 * 9 = 72, 10-7 3, then c = 7, because 7 * 9 = 63, can get 3Yu Youhong is the type of Qi 2078*9 18702

If we take a=1, then d=9, because 9*9=81, and then push down 19 9 2, it contradicts the assumption a=1, so we can only take a=2

Update 1:A and C cannot be the same age.

Two answers (1) a= 2

b = 1c = 8

d = 7 a > b

2 > 1 c > macro d

8 > Roll 7 21 x 87 = 1827 (2) a= 8b = 6c = 8

d = 0 a > b

8 > 6 c> d

8 > 0 86 x 80 = 6880 solution: a= 2

b = 1c = 8

d = 7 or a= 8

b = 6c = 8

d = 0

Summary. b=1,c=2;b=6,c=2

b=1,c=4;b=6,c=4

b=1,c=6;

b=1,c=8;b=6,c=8

b=1,3,7,9,c=5

The last two digits of BB*C are BC

So it can only be:

b=6,c=4;bb*c=66*4=264;The single digit of a*c is 4; But A and B are different. No solution.

b=9,c=5;bb*c=99*5=495;The single digit of a*c is 5; a=3,7, then the corresponding d=1,3

Therefore: 399*5=1995 or 799*5=3995

And because the question says d=1, there is only one answer.

ABB multiplied by A equals DBBC, where D equals 1, Q: How much BC equals.

Hello, glad to answer for you! 399*5=1995a=3 b=9 c=5 d=1

I'll type it out to you. Hold on.

Thank you. Thank you.

You're welcome, please remember to give me a thumbs up

Okay, give me a solution process, thank you.

Okay, give me a solution process, thank you.

Okay, wait a minute, I'll type.

Okay thank you. Okay thank you.

A number c multiplied by a different number b single digit is still c, and it is said that the fast cavity (b, c) can only be: b=1, c=2; b=6,c=2b=1,c=4;b=6,c=4b=1,c=6;b=1,c=8;b=6,c=8b=1,3,7,9,c=5 and the last two macro bits of bb*c are bc, so they can only be: b=6, c=4; bb*c=66*4=264;Explain that the unit digit a*c is 4; But A and B are different.

No solution. b=9,c=5;bb*c=99*5=495;The single digit of a*c is 5; a=3,7, then the corresponding d=1,3 Therefore: 399*5=1995 or 799*5=3995 and because the title says d=1, there is only one answer is 399 5=1995

Thank you. Thank you.

You're welcome, but remember to give me a thumbs up

Summary. Since d = 1, a a has a carry and the ten place is 1, and only 4 meet this condition

Can send**Oh!

Since d = 1, a a has a carry and the ten place is 1, and only 4 meet this condition

Because 1*1=12*2=43*3=94*4=165*5=25

The single digit of 4 b is b

The previous sentence is wrong, the unit of 4 b is c

Isn't it okay yet? 4*4=16, then b = 6 + 10 of b.

Your answer is correct.

It's over. I don't understand.

The unit digit of 4 b is c, b = 6 + the ten digits of 4 b are all known to be the difference between the unit digit and the ten digit of 4*b

I knew the answer was right, but I didn't know the algorithm, so I asked.

How does the 6 in b=6+4*b come about?

For example, if the number on the ten digit is y, the single digit can be seen from the vertical form that the single digit is cy+c=by+6=bc=6

So b=9, I'll explain it to you again.

First of all, how to know the value of a, because a*a has a carry, and the carry is 1, only 4*4 satisfies this condition, so a=4

How do you calculate the vertical type? First calculate the single digit and multiply this number, 4 times the single digit of b is c, and then calculate the ten digit and multiply the number of this bridge spring, only Qi 4 times refers to the elimination of the tomb with the ten digits of b plus the single digit for b and then calculate the hundred digits and multiply this number, 4 times the single digit of 4 (6) + 4 The ten digits of b are b

Find, then multiply the ten digits by this number, 4 times the ten digits of b plus the single digit is b, and then calculate the hundred and limb grinding digits and multiply this number, 4 times the unit digit of 4 (6) + the ten digits of 4 b are b, both of these equations appear 4 b, the ten digits are b, so the other number is equal, so 4 times the ten digits of b = 6

There was a typo on it, ignore it.

Found and then multiply the ten digits with this number, 4 times the ten digits of b plus 4 times the single digit of b for b and then calculate the hundred digits and multiply this number, 4 times the unit digit of 4 (6) + 4 b ten digits for b, these two formulas appear in the stool, the ten digits of 4 b are b, so the other number pants cherry pins are equal, so 4 times the single digit of b = 6

So look at 4 multiplied by which number has a single digit of 6? Only 4*4 and 4*9

And because ABC is different.

So b=9 brings back the vertical solution c

Because d+d=d, only 0 can do it.

Because A+A has a carry, A5, i.e., C=3 or 4, so C+C has no carry.

Because the end of b+b = c, c is an even number, i.e. c=4, a=8 If b=2, then b+b has no hunger bit, i.e., a+a=eb=16, which is inconsistent with b=2.

So b=7, i.e., a+a+1=eb=17, is true.

The final answer is 8740 + 8740 = 17480, thank you.

ABC+CBA=BBCB2 3-digit numbers are added together to get four digits, and the highest digit can only be 1, so B=1C=3, A=8813+318=1131

ABCD multiplied by 4 = BCBA, ABCD is.

0 to 9 numbers, so 4a is less than 10, a = 1 or 2, and because d times 4 mantissa is a, so a is even, so a = 2, d times 4 mantissa is 2, so d = 3 or 8, a = 2 substituting into the equation to get b greater than or equal to 8, b = 8 or 9. But if b = 8 or 9, 28cd or 29cd multiplied by 4 can't be more than 8000 or more than 9000, so, classmate, you made a mistake in the question... If you make a mistake, there is something wrong with the question.

d=0 a=1 b=8 c=3 that is, 183+830=1013 Don't ask me why, as a science student, I can go around you.