How to do this math problem? The bottom edge of the isosceles right triangle is 10cm, and what is it

In the triangle ABC, the angle A = 90°

Connect vertex a and the bottom midline to meet the bottom edge at d

The isosceles triangle is three lines in one.

AD BC right triangle hypotenuse midline is equal to half of the hypotenuse.

ad=5cm

s=5×10÷2=25cm²

The bottom edge of an isosceles right triangle is 10 cm, and the middle line of the hypotenuse of the right triangle is equal to half of the hypotenuse, then its height = 10 2 = 5 (cm).

Using the triangular area formula, the bottom * height * 1 2 so its area is 1 2 * 10 * 5 = 25 (square centimeters).

A: Its area is 25 square centimeters.

From the Pythagorean theorem: a +a =10 so the length of the right-angled side a=5 2, so the area is: s=a 2=(5 2) 2=25 cm

The middle line of the bottom edge of the isosceles right triangle is the same line as the perpendicular line, and because the middle line on the hypotenuse of the right triangle is equal to half of the hypotenuse, the high position of the bottom edge is 5cm, and the area is 10*5 2=25cm 2

The area is 25cm, and the middle line on the hypotenuse of a right triangle is equal to half of the right angled side.

The height on the hypotenuse of an isosceles right triangle is exactly the midline.

Individuals give you a relatively simple method. You put these four triangles together, and the right angles coincide. You will find that the sum of the areas of the four triangles is 10*10=100 square centimeters.

And the area of the four triangles is equal, so the area of one triangle is 25 square centimeters. Beg.

Have you learned the Pythagorean theorem?

h=root(10 2+5 2)=x s=1 2*h*10=xx

A right-angled side is regarded as the bottom, and the other right-angled side is the height on the bottom of the vertical bar of the forest, this question is an isosceles right-angled triangle, indicating that the two right-angled sides are equal, that is to say, the bottom and the height are equal to 20 centimeters.

Then apply the area formula: s=a b 2

i.e., s = 20 20 2 = 200 (square centimeters.

Because the area of the square = 1 2 diagonals squared, therefore, half a square ascending Sun is an isosceles right triangle, so its closed area = 1 4 pairs of noisy chain angles squared = 1 4 10 = 25 (cm).

It is known that a right-angled isosceles triangle has an area of 100 cm and a length of 10 cm on both sides.

The area of the ruler finger of the isosceles right-angled triangle with an hypotenuse length of 20cm is equal to the product of the two right-angled sides divided by 2, so the product of the multiplied cm of the two right-angled sides is 100*2 200, and the length of a right-angled side is 10 times the root number of the god staring 2, according to the Pythagorean theorem, the length of the hypotenuse can be calculated to be 20cm

Method 1: Because it is an isosceles straight hand horn triangle, the longest side is the bottom edge.

Let the side of the waist be long x, then according to the Pythagorean theorem, there is: x 2 + x 2 = 10 2, so x = 5 2

So, area = 1 2*x*x

Method 2: Because it is an isosceles right triangle, the midline of the potato on the bottom edge is equal to half of the bottom edge, which is 5

Area = 1 2 * 5 * 10 = 25

The height of the bottom edge is 5 centimeters.

Area: 10x5 2 = 25 square centimeters.

Hope, thank you.

Solution: 1 A squared + b squared = c squared a = b so c squared = 2 * a square so a square = squared.

The area of the triangle is s=squared=squared=

Solution 2 Do the auxiliary high line from the right angle to the hypotenuse, then the area s=high can be proved to be high=hypotenuse=5, so the area s=

Proof: Isosceles right triangle, the hypotenuse is high and bisects the top angle, the bottom edge is bisected, and the two triangles formed are isosceles right triangles, which can be simply calculated by the inner angle of the triangle and the formula.

So there is high = hypotenuse.

Solution 3 square root of s= square root of b=c*cos(c)=10*.

So the square root of s=*the square root of *=25

The above way is written, 1 2 is written.

Since it is an isosceles triangle, if the length of the two right-angled sides is equal, then both are set to x

And because it is a right-angled triangle and the hypotenuse is 10 long, according to the Pythagorean theorem: the sum of the squares of the two right-angled sides is equal to the square of the hypotenuse, and x=50 under the root number

Finally, the base multiplication height is divided by two to calculate the area of this triangle s=25

Let the side length be x, then x*x+x*x=10*10, x*x=50; And the area of the triangle is long multiplied by the width divided by 2 equals x*x 2, so the area is equal to 25 square centimeters.

Since it is a question in the fifth grade of primary school, I will use the simplest method to calculate, and regard the side length of 10 centimeters as one side of a square, and four such figures are a square.

10x10)/4=100/4=25cm

Using the Pythagorean theorem, find the two waists, and you can forget it.

Isosceles triangle, waist length 20, bottom edge 30, as the base brother height = (20 2-15 2) fight attack;

Tangent of the bottom angle = half of the height of the bottom =

20 2-15 2).

Primary School Mathematics Tutoring: It is known that one side of an isosceles right triangle is 10cm, and the area of the triangle is found.