Can a multiple of three be any number in the single digit?

Multiples of 3 can be any number in the single digit.

Because of the multiple of 3, as long as the number on all the digits is added together is a multiple of 3, then the number on the single digit can be filled in arbitrarily, and there are other digits added together to be a multiple of 3.

The judgment of the multiple of three is based on whether the sum of the numbers of each rank of the number is a multiple of three, and if the sum of the various digits is a multiple of three, then this number is a multiple of three. According to this principle, multiples of three can be any number in the single digit, such as 30, 21, 12, 33, 24, 315, 246, 27, 18, 129, and so on.

For a single digit, the single digit cannot be any number, it can only be 0, 3, 6, 9 to divide 3.

For two-digit numbers, the addition of these two digits must be divided by 3, so when the ten digits are 1, the single digit can be 2, 5, 8; When the ten digit is 2, the single digit can be 1, 4, 7; When the number of tens is 3, the single digit can be 0, 3, 6, 9;When the ten digits are 4, the single digit can be 2, 5, 8; When the number of tens is 5, the single digit can be 1, 4, 7; When the number of tens is 6, the single digit can be 0, 3, 6, 9;When the ten digits are 7, the single digit can be 2, 5, 8; When the number of tens is 8, the single digit can be 1, 4, 7; When the number of tens is 9, the single digit can be 0, 3, 6, 9.

Hope it helps!

Yes, multiples of 3 can be any number in the single digit.

Yes, as long as the sum of the numbers is a multiple of 3, such as 111, because 1+1+1 3 is a multiple of 3, so 111 is a multiple of 3.

For example: 120, the sum of the three numbers on the unit, ten and hundred places is 3, which is a multiple of 3, and 120 is a multiple of 3, and for example: 25320, the sum of the five numbers on the unit, ten, hundred, thousand, and ten thousand places is 12, which is a multiple of 3, and 25320 is also a multiple of 3.

Regardless of the size of the number, as long as the sum of the numbers on each digit is a multiple of 3, the number is a multiple of 3.

This is a characteristic of a number that is divisible by 3: if the sum of the digits of a number is divisible by 3 (a multiple of 3), then the number is also divisible by 3 (a multiple of 3). Such as 3288, because.

3+2+8+8 21,21 is divisible by 3 (a multiple of 3), so the number 3288 is divisible by 3 (a multiple of 3).

For example, 785, 7+8+5 20, 20 is not a multiple of 3, so the number 785 is not a multiple of 3.

Similarly, the sum of the digits of a number is a multiple of 9, and this number is also a multiple of 9.

The meaning of this sentence is that the number you write out, all the numbers add up to a multiple of three, then this number can be divisible by three, such as 123, the number on each bit is 1, 2, 3, and the sum is 1+2+3=6, then, 123 can be divisible by three.

Use a concatenated letter to represent multiple digits, ABCD means that the thousand digits are A, the hundred digits are B, the ten digits are C, the single digits are the four digits of D, and the sum of the numbers on each digit is a + B + C + D, if a + b + c + d is a multiple of 3, then ABCD is a multiple of 3.

Verification: 1111 1+1+1+1=4 is not a multiple of 3, so 1111 is not a multiple of 3.

1230 1+2+3+0=6 is a multiple of 3, so 1230 is a multiple of 3.

That is, whether a number is a single digit, ten digits, or hundreds of digits, etc., it is a multiple of three, so the whole number can be divisible by three.

Multiples of 3: The sum of the digits of a number is a multiple of 3, and this number is a multiple of 3.

Example: 1926:

The number on each digit is 1, 9, 2, 6, 1 9 2 6 18, which is a multiple of 3 (18 3 6). i.e. 1926 is a multiple of 3 (1926 3 642).

For example, the number 123, 3 in the single digit plus 2 in the 100 digit plus 1 in the 100 digit is equal to 6, 6 is a multiple of three, and the number 123 is a multiple of three.

What is the order of the sum of the numbers on each digit from the single digit observation of the 5th grade Math 3 multiple? What is their quantitative relationship to three?

Several are multiples of three, 9, 12, 15

The sum of the digits on each digit of a number is a multiple of 3, and this number is a multiple of 3.

The sum of the digits of a number is a multiple of 3, and this number is a multiple of 3.

For example, the numbers in 15 digits and tens add up to 6, and 6 is a multiple of 3, so 12 is a multiple of three.

I didn't understand the question, if it's true/false, it's wrong, the single digit of 13 is a multiple of 3, but 13 is not.

If the sum of the numbers on a number is divisible by three, then the number is divisible by three.

Wrong. The number in a single digit is a multiple of 3, and it cannot be said that this number is a multiple of 3.

If the sum of the digits on each digit of a number is a multiple of 3, then that number is a multiple of 3.

For example, the number 6 in the single digit of 16 is a multiple of 3, but 16 is not a multiple of 3.

The sum of the digits on each digit of 126 is 1+2+6=9, which is a multiple of 3, then 126 is a multiple of 3.

Proof: Look at the two-digit first, such as the digital AB combination.

a+b is a multiple of 3.

Then 10*a+b=9a+(a+b).

9a is divisible by 3 and a+b is divisible by 3, so 10+b is divisible by 3.

Then look at the three-digit ones, such as the digital ABC combination.

a+b+c is a multiple of 3.

Then 100*a+10*b+c=99a+9b+(a+b+c).

99a, 9b, (a+b+c) are all divisible by 3, so 100*a+10*b+c is divisible by 3.

Actually, for any natural number a(1)a(2)a(3)a(4)...a(n)

If a(1)+a(2)+a(3)+a(n) is a multiple of 3.

Then a(1)*10 (n-1)+a(2)*10 (n-2)+a(n-1)*10+a(n)

a(1)*[10^(n-1)-1]+a(2)*[10^(n-2)-1]+.a(n-1)*9+[a(1)+a(2)+.a(n)]

Each of the items in between. are divisible by 3.

Therefore, if the sum of the digits of a number is a multiple of 3, then this number is a multiple of 3.

A number is a multiple of the three major disturbances. What is in the single position? The single digit is 0,,3,4,5,6,7,8,9.

We've had that experience in the future. When all the numbers of a number add up to the sum and can be divisible by 3, this must be divisible by three.

Like what. 1234567。

Because 1+2+3+4+5+6+7=28. It is not divisible by three.

So. 1234567 is not divisible by 3.

Another example is 234567. Just because all the numbers add up, they are equal to 3 divisible. So, 234567 this number is divisible by 3.

Anything goes, as long as the sum of all the digits is a multiple of 3.

If a number is a multiple of 3, then the number in its single digit must also be a multiple of 3. (False).

For example, 21 is a multiple of 3, but the empty shout number 1 in the single digit of the fighting pants is not a multiple of 3.

Take a four-digit number as an example, let the four-digit number be abcd, and the value of this feast number is:

1000a+100b+10c+d

999a+a+99b+b+9c+c+d

999a+99b+9c+(a+b+c+d)9(111a+11b+c)+(a+b+c+d)9(111a+11b+c) 3=3(111a+11b+c) divisible by 3.

a+b+c+d) is the sum of the numbers, and if it is also divisible by 3, then abcd is divisible by 3.

For example, 12 and 15 are all numbers like this.

Summary. I'm glad to answer for you, because for an integer, such as x=(abcde), each letter is one, then x=10 4*a+10 3*b+10 2*c+10*d+e; =(9999+1)*a+(999+1)*b+(99+1)*c+(9+1)*d+e=(9999*a+999*b+99*c+9*d)+(a+b+c+d+e)=a+b

Why is the sum of the digits a multiple of 3, this number is a multiple of 3?

I'm glad to answer for you, this is because for an integer, such as x=(abcde), each letter is a state sedan position, then the sail is unbridled x=10 4*a+10 3*b+10 2*c+10*d+e; =(9999+1)*a+(999+1)*b+(99+1)*c+(9+1)*d+e=(9999*a+999*b+99*c+9*d)+(a+b+c+d+e)=a+b

This proof process is a bit complicated.

This certificate will not be tested in the exam.

Fourth-graders.

So just keep this conclusion in mind.

I don't understand. Be sure to keep this conclusion in mind.

Many types of questions need to be solved by this conclusion.

The process does not require mastery.

Summary. Hello! Multiples of 3 look at whether the sum of all numbers is divisible by 3. For example, 582, 5+8+2=15, 15 is divisible by 3, so 582 is also divisible by 3, which is a multiple of 3. You can't tell just by looking at the number in a single digit.

Hello! Multiples of 3 look at whether the sum of all numbers is divisible by 3. For example, 582, 5+8+2=15, 15 is divisible by 3, so 582 can also be divisible by 3, which is a multiple of 3. You can't see it just by looking at the number on the single digit of the shirt tassel.

This definition, these calculation methods have been studied by predecessors.

There is a definition that as long as the sum of each number is divisible by 3, the number is a multiple of 3.

How to get to the multiple feature of ** three.

Just like a number is divisible by 2, it is a multiple of 2.

How to remove the multiple feature of threeHow to remove the multiple feature of three.

This is the teaching process.

And this Zhonggong's.