Help me with function questions, function questions, help me.

1 is correct, substituting (-2,1) into the linear equation gives 2a-b=-1---4a-2b=-2

Substituting (2,1) into the parabola, then it is 1 4a-2b+3, which is easy to see that it is true For 2, you can connect b 2a and 4a-b=-2 to determine whether b exists, and the result should be calculated, I didn't calculate, mainly the method.

As for the minimum value of the ordinate is 3, use (4ac-b 2) 4a, after eliminating the b variant, 3-4a-5 a, a 0, so it is an increase function, and the minimum is 3

This topic is from junior high school, so if you think about it, you should be able to come up with it.

1=b-2a, 1=4a-2b+3=-2(b-2a)+3, so 1 is right.

y=a(x-1) 2+2-a, so 2 pairs.

3 Not true.

2a+b=1

b=2a+1 (a≠0)

y=ax 2-(2a+1)x+3 (a is not equal to 0) narrative 1 substituting x=2 then y=4a-4a-2+3=1 then passing the fixed point (2,1).

Narrative 2 Make the axis of symmetry x=1

then (2a+1) 2a=1

2a+1=2a The equation is unsolved, so the narrative is wrong.

Narrative 3 The ordinates of the parabolic vertices are .

12a-4a^2-4a-1）/4a

2-a-1/(4a)

The equation takes the minimum value of 3 at a=

So narrative 3 is correct.

The Kyungjeong images of y=1 e x and y=-1 e x are as follows:

Brief introduction. y=e x is an exponential function that is continuous over the entire field of real numbers, with a monotonically increasing pre-delta tremor.

y=e (1 x) is a composite function, at x=0 point is not a continuum of defeat, the left limit is 0, x=0+, y tends to +, y=1 is its horizontal asymptote, and when x tends to , y tends to 1. In (- 0) and (0,+ monotonically decreasing.

What you're trying to say is:

y = 1 - 1 2 * cos( x 3) x r right? When x 3 is an odd multiple of , y obtains a maximum value of 3 2, and when an even multiple of y, a minimum value of 1 2

That is, when x is 6k+3 (k is an integer), y obtains the maximum value of 3 2, and when x is 6k, y obtains the minimum value of 1 2

I don't think it's very difficult, but your formula is not very clear, and it is easy to cause ambiguity, so it is recommended to use the formula tool with word or use"Parentheses"Clearly express the rules of operation of the formula

cos x itself is a period of 2 periodic function, so, y should also be a period of 2 periodic function, just need to find the maximum and minimum value in a period, find the zero point of cos x, the minimum point, the maximum point, one by one substitution y, I think you should be able to get the result!

1. All students will not improve mathematics in this way, and the teacher assigns homework not to answer correctly, but to learn to think independently.

The method I handed over to you can only solve the urgent need, but I can't take a salary from the bottom of the kettle! You have to think for yourself before you know it.

Solution: One. Bring the points a(1,2) and b(-1,-4) into y=kx+b to get a system of binary linear equations:

2=k+b，╰ 4=-k+b

The solution gives k=3 so the analytic formula for this function is y=3x-1

b = -1 two. The method is the same as above, the points a(-2,2) and points b(2,-4) are brought into y=kx+b to obtain a system of binary linear equations:

2=-2k+b，╰ 4=2k+b

The solution gives k= -3 2 so the analytic formula of this function is y=-3 2x-1

b=-1

1. The image passes through these two points, indicating that these two points are in the function, that is, satisfying the function relation, so it obtains:

2=k+b;

4=-k+b:

The solution is: k=3, b=-1, so the analytic expression of the function is y=3x-1.

2. The language description of the solution process is the same as above.

2=-2k+b；

4=2k+b；

The solution is: k=-3 2, b=-1, so the analytic formula of the function is y=3 2*x-1.

1.Substituting a, b into the analytic formula gives 2=k+b....4=-k+b...The formula is added to give k=3 and b=-1. then y=3x-1

2.Substituting a, b into the analytic formula yields 2=-2k+b....4=2k+b...The addition of the formula gives k=-3 2, b=-1.

then y=-3 2x-1

From the inverse proportional function y=x/k image and y=x-3/3 image with respect to x-axis symmetry, k=-3 is known

Since the image of the inverse proportional function y=x/k and y=3/x-symmetry with respect to the x-axis, then k = -3

Find m=-1

Bring x=-1, y=3 into y=ax+2, a=-1

With respect to x-axis symmetry, x does not change, and y becomes the opposite number, so, k=-3, so y=-3 x, bring y=3 into it, there is x=-1, so m=-1, and likewise substitute a(-1,3) into y=ax+2, and we get a=-1

Proportional: y=k*x k is not equal to 0 (* is a multiplier sign) The image is a straight line through the origin (I won't draw it), property 1with respect to origin symmetry; 2.When k>0, the function is incrementing at (-oo, +oo), and vice versa when k<0;

Inverse proportionality: y=k x The image is hyperbolic (the left is the case where k is positive, and within each quadrant, the single subtraction is single, and the right image is opposite in nature) The image is symmetrical with respect to the origin.

Primary function: y=k*x+b k is not equal to 0 The image is a straight line (the proportional function is a special case when the primary function crosses the origin, i.e., b=0) When k>0, the function is an increasing function at (-oo, +oo), and vice versa when k<0; and with respect to point (0,b), point symmetry (i.e., the intersection of the image with the x-axis and y-axis).

af=6x/(3-x) 3>x>0;

3 times x squared (3-x);

No, the functional formula is meaningless, the graph cannot form a triangle, and the ep is parallel to ab.