It could be a math problem, a math possibility problem

Updated on educate 2024-04-11
27 answers
  1. Anonymous users2024-02-07

    3 * 9 = 27 + 2 = 29 yuan, the explanation of this sentence is a wrong inducement.

    It should be counted as follows:

    Customer expenses, boss income, and small two income.

    Customer expenditure 3 9 yuan 27 yuan.

    The boss's income is 3 10 yuan, 5 yuan, 25 yuan.

    Primary 2 earns 2 yuan.

    So, 27 25 2

  2. Anonymous users2024-02-06

    That's not how it counts.

    Let's talk about paying first, each of them is 9 yuan, a total of 27 yuan.

    Besides, the boss gets 25 yuan, and the second child gets 2 yuan, a total of 27 yuan, so that the pay is the same as the get, so there is no money missing.

    You're wrong to add that.

  3. Anonymous users2024-02-05

    3*9+2 is a mistake, just don't add 2! Because at this time, the total amount cannot be calculated according to 30 yuan, it should be 27 yuan, the boss took 25 yuan, and Xiaosheng took 2 yuan!

    If it is calculated as 30 yuan, it is like this: 25 + 2 + 3 = 30

  4. Anonymous users2024-02-04

    3 * 9 = 27 + 2 = 29 yuan, your formula is wrong, because 2 yuan is the money received by the store owner and the money paid cannot be added.

    Discount 5 yuan, both (30-3 * 9) - (5-3 * 1) = 1, this yuan is here.

  5. Anonymous users2024-02-03

    The three of them each paid 9 yuan, 3 * 9 = 27 yuan. And the shopkeeper only charged 30-5=25 yuan.

    The shopkeeper kept 2 yuan for himself, 25 + 2 = 27 yuan.

    That's not how you calculate, it should be 3*9-2+5=30 yuan.

  6. Anonymous users2024-02-02

    In fact, it was 9 yuan per person.

    That's 27 yuan.

    Among them, 25 yuan for the room fee and 2 yuan were taken by the shopkeeper.

    So exactly 25 + 2 = 27

    Instead of 27 + 2 = 29, this 29 doesn't make sense.

  7. Anonymous users2024-02-01

    10 yuan for one person at the beginning, a total of 30 yuan;

    After that, the shopkeeper returned 1 yuan each, and the actual person paid 9 yuan, a total of 27 yuan, which included: 25 yuan from the shopkeeper and 2 yuan left by the shopkeeper.

    What does 27+2 mean? Nothing!

  8. Anonymous users2024-01-31

    There is no one yuan, and the three people pay a total of 9 * 3 = 27 yuan.

    Boss 25 guy $2.

    Isn't this equal, that one yuan is a misunderstanding.

  9. Anonymous users2024-01-30

    To make the probability of touching the black ball the most and the probability of touching the red ball the least, there should be a minimum of 12 3 + 1 = 5 black pinballs and a maximum of 12 3-1 = 3 red pinballs, as long as the number of remaining (yellow) pinballs is less than the black ball and more than the red ball, there are a total of 7 possible scenarios:

    1 red, 2 yellow, 9 black.

    1 red, 3 yellow, 8 black.

    1 red, 4 yellow, 7 black.

    1 red, 5 yellow, 6 black.

    2 red, 3 yellow, 7 black.

    2 red, 4 yellow, 6 black.

    3 red, 4 yellow, 5 black.

  10. Anonymous users2024-01-29

    To make the probability of touching the black ball the most and the probability of touching the red ball the least, then the number of black balls is the most and the number of red balls is the least.

    There are five scenarios:

    Number of black balls, number of yellow balls, number of red balls.

  11. Anonymous users2024-01-28

    To maximize the probability of touching the black ball, the probability of touching the red ball is the smallest, the number of black balls in the pocket is the highest, and the number of red balls is the least.

    There are 7 types of black, yellow, and red balls 543642651732741831921 in total.

  12. Anonymous users2024-01-27

    Although the sum is "7", there are 6 cases: 1, 6, 2, 5, 3, 4, 4, 3, 5, 2, 6, 1.

    In the case of "8", there are 5 kinds of 2, 6, 3, 5, 4, 4, 5, 3, 6, 2, a total of 5 types, and the probability of victory is higher.

    But Xiaodong doesn't necessarily win or lose.

    So choose C

  13. Anonymous users2024-01-26

    c.Xiaodong may lose.

    Because there are 12 numbers in 2 dice: 1, 2, 3, 4, 5, 6, 1, 2, 3, 4, 5, 6.

    The number 7 has 1+6,,2+5,3+4,4 3,5 2,6 1,6 possibilities.

    A score of 8 has 2+6, 3+5, 4+4, 5, 3, 6, 2, and 5 possibilities.

  14. Anonymous users2024-01-25

    You should choose A, because 123456 are relatively combined, then all get 7, and none get 8, so, Xiao Dongsheng wins.

  15. Anonymous users2024-01-24

    It can only be possible to lose, because the number and the probability of being are the same.

  16. Anonymous users2024-01-23

    The possible combinations of 7 are 1,6,6,1, 2,5 5,2 3,4,3

    The possible combinations of 8 are 2, 6, 6, 2, 3, 5, 5, 3, 4, 4

    So 7 has a better chance of winning.

  17. Anonymous users2024-01-22

    I think that choosing C is a question of probability, examining the understanding of probability, although the probability of Xiaodong winning is large, it is not 100% that he will win, and there is a possibility of losing.

  18. Anonymous users2024-01-21

    cBecause Xiaodong does not have a 100% chance of winning, it is possible to lose.

  19. Anonymous users2024-01-20

    The answer is C, the probability characterizes the probability of an event occurring, that is, for the future, the event with a small probability is not necessarily not going to happen, that is, the occurrence of extreme events cannot be prevented. So even if the two upstairs calculate that the probability of Xiaodong winning is higher, it cannot be said that he will definitely win, nor can it be asserted that Xiaochen will lose, this is the uncertainty of probability.

  20. Anonymous users2024-01-19

    1. Now there is A. Second. The students of Team C3 have the same life as the boys in each team.

    The ratio of the number of students in team A and team B is 6:5, and girls account for 3 2 in team AThe ratio of the number of girls in team A to team C is 5:4, and team B has 15 girls, so what is the total number of students in team three?

    The number of students in team A is 6, with girls in team A accounting for 3 2, girls in team A accounting for 4, and boys in team A accounting for 2;

    The number of boys in team B is 5, and the boys in each team have the same life, and the boys in team B account for 2 shares; In Team A, there are 3 girls, 15 girls, and 5 girls each;

    The ratio of the number of girls in team A to team C is 5:4, the number of girls in team C is 4*4 5 = shares, and the number of boys has 2 shares.

    So, what is the total number of students in the three teams?

    5*(6+5+ people.)

    2. The circumference of a semicircular patch is decimeter, its radius is (2 decimeters), and the area is (decimeter 2).

    Radius: 2*r+. 28,r=2

  21. Anonymous users2024-01-18

    1.The girls in the first team account for 3 2, it should be 2 3, right?

    Set: Team A Girls X, Boys Y, Team C Total Number Z.

    x+y):(15+y)=6:5

    x=2yx:(z-y)=5:4

    The solution is x=20, y=10, z=26

    So team A has 20 + 10 = 30 people, team B has 15 + 10 = 25 people, and team C has 26 people.

    A total of 30 + 25 + 26 = 81 people.

    2.2* is the radius).

    r=2 s=

  22. Anonymous users2024-01-17

    It's math and it's not math.

    It's a brain teaser.

    9 is 6 upside down, 6 + 11 + 13 = 30

  23. Anonymous users2024-01-16

    Math, of course.

    In decimacimal: 1+15+15=30 3+13+15=30 5+13+13=30 5+11+15=30 7+11+13=30 9+11+11=30

    In decimacimal: 3+15+15=30 5+13+15=30 7+13+13=30 7+11+15=30 9+11+13=30

    In decimacimal system: 5+15+15=30 7+13+15=30 9+13+13=30

    In heparchmental: 7+15+15=30 9+13+15=30 in hexadecimal: 9+15+15=30

  24. Anonymous users2024-01-15

    Three odd numbers are added together to give an even number.

  25. Anonymous users2024-01-14

    No, the sum of the three odd numbers is a cardinal number.

  26. Anonymous users2024-01-13

    <> Daxin circular general idea slip source, look at the cherry blossoms.

  27. Anonymous users2024-01-12

    <> ask for a sedan chair or a sedan chair.

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