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a) found that the denominator is twice the numerator plus one.
When the numerator and denominator are reversed, the order of size changes. For example, after adding or subtracting the same number from 6>5 1 6<1 5, the order of size remains unchanged. For example, 10>8 8>6 then reverse the numerator and denominator, and restore the order of size.
After the above operation is done with (one) numbers: 3 4 17 100 151, so the first smallest and the last largest. 151 301-3 7 = 22 301 two) 11 6 12 7 17 10 Larger than 1 The other three are smaller than 1.
Cross multiplication ratio 11 6 12 7 17 10 For example: 7x11>6x12 So 11 6>12 7
In summary: 12 61<1 5<6 29<17 10<12 7<11 6
The easiest way to do this is to decimalize it all and compare.
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Hello. Question 1.
151 301 maximum.
You can put them all in the same minute, i.e. multiply by the least common multiple of the denominator.
Or you can put molecules 2 at the same time
It can be found that the first digits are all smaller than the denominator after multiplying by two, and the last one is greater than the denominator.
i.e. the previous score 1 2 and the last 1 2
The second question, the same goes for it.
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B is 25% less than Zhiyun C, then B is equivalent to (1-25%) of C, the standard quantity in the lap beam is C, the standard quantity = the corresponding quantity corresponding to the fraction.
You can also think of it this way: 25% here is the part where B is less than C, which is 25% of C, that is, B = C - C 25%, and after the variation, B = C (1-25%), C = B (1-25%).
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Using the equation, let it be that there are x tons.
4/5 x + 45 +x =x + 5/4 x5/4 x - 4/5 x=45
x=100
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There were x tons in the warehouse.
4*[(1-1/5)x+45]=5x
16/5x+180=5x
9/5x=180
x = 100 warehouses with 100 tons.
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Suppose there were x tons of grain in the original warehouse.
1 - 1 5) x + 45 ] x = 5 : 4x = 45 * 5 : 4 (1 - 1 5) = 100 (tons).
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Set up a warehouse of x tons of original grain.
x - (1/5) x 45: x = 5:4
x=100
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