Two days later, what are the review points to grasp in the final exam of senior one chemistry? The

Updated on educate 2024-05-04
12 answers
  1. Anonymous users2024-02-09

    1. See what experiments are available.

    2. Take a look at those basic definitions.

    3. Formulas related to calculations.

    4 basic elements.

    5. Special properties.

  2. Anonymous users2024-02-08

    I don't know what you've learned**, I'll try to help, maybe the textbooks are not the same, but the content is similar.

    1 For the separation and purification of substances, it should be remembered that sodium yellow potassium violet (flame color reaction). At the same time, remember the inspection of carbonate ions, sulfate ions, chloride ions, etc. Especially for sulfate ions, we must remember to exclude the interference of silver ions, carbonate ions, and sulfite ions.

    The steps of the preparation of the solution must be examined, and it is often wrong, pay attention to the specifications of the volumetric flask, and indicate it. The steps of distillation, extraction and separation, as well as evaporation precautions, and crystallization and recrystallization steps.

    2 Metallic elemental part: pay attention to the valence of iron, the strong oxidation of ferric ions (Cl2>Br2>Fe3+>I2), and the amphoteric of aluminum.

    Extending an equation might use al3+ +3alo2- +2h2o===4al(oh)3

    3. For the non-metallic element part, it is known that the products of sodium and oxygen are different at different temperatures, and it is known that the dehydration of MgCl2*6H2O should be heated and dehydrated in a dry HCl gas stream.

    4 Sulfur and nitrogen, strengthen the equation, this is not easy to make mistakes, and it is basically not wrong to be proficient.

  3. Anonymous users2024-02-07

    Judgment of oxidation and reducibility.

    1) According to the valency of the element.

    The element in the substance has the most **, the element is only oxidized; An element in a substance has a lowest valence, and the element is only reducible; The element in the substance has an intermediate valence, which is both oxidizing and reducing. For the same element, the higher the valence state, the stronger its oxidation; The lower the valence, the more reducible it is.

    2) According to the redox reaction equation.

    In the same redox reaction, oxidation: oxidant" oxidation product.

    Reducibility: Reducing agent" reducing product.

    The stronger the oxidation of the oxidant, the weaker the reduction of the corresponding reduction product. The stronger the reducing agent, the weaker the oxidation of its corresponding oxidation products.

    3) According to the difficulty of the reaction.

    Note: (1) The strength of redox is only related to the difficulty of the atom to gain and lose electrons, but not the number of electrons gained and lost. The stronger the electron-gaining ability, the stronger its oxidation; The greater the ability to lose electrons, the more reducible it is.

    2) There is no redox reaction between adjacent valence states of the same element.

    4) Common oxidants.

    Reactive non-metals, such as Cl Common oxidants: 2, Br2, O2, etc.;

    Elements (e.g., Mn, etc.) are oxides with high valency, such as Mno2, Kmno4, etc.

    Oxygenated acids when elements (such as S, N, etc.) are in high valency, such as concentrated H2SO4, HNO3, etc.

    Salts when elements (such as Mn, Cl, Fe, etc.) are in high valency, such as KmNO4, Kclo3, FeCl3, K2Cr2O7

    Peroxides, such as Na2O2, H2O2, etc.

    5) Valency formula.

    monovalent potassium hydrochloride sodium silver; Divalent oxygen, calcium, barium, magnesium, zinc, trialuminum, tetrasilicon, pentanitrogen phosphorus; 23 iron, 24 carbon, 24 6 sulfur are all Qi; Copper-mercury bivalent is the most common.

  4. Anonymous users2024-02-06

    Probably less than 50, just find a workbook and you can see, from the amount of matter to the experiment, chemistry is very simple, figure out these knowledge points, and then do comprehensive questions, little by little, to be steady, now if you start to score more than 50 points, the college entrance examination is also more than 80, I tutored several students this year are not bad.

  5. Anonymous users2024-02-05

    Principles of inorganic, organic, chemical reactions.

  6. Anonymous users2024-02-04

    This is not my field, I dare not answer randomly, I wish you to find the answer as soon as possible!

  7. Anonymous users2024-02-03

    This chapter is more difficult to understand, and for most children, the content of this book is the most difficult! (Of course, organic chemistry is also difficult, so it is relatively easy to understand and memorize).

    First, all chemical reactions have an equilibrium constant k (this needs to be calculated, it is a function of temperature, and it has nothing to do with other external conditions), special ones are water kw (by the way ph), dissolved ksp

    Second: the problem of particles in solution, pay attention to the conservation of elements, charge balance, and can be equivalent to a system that is not the number of substances in the question, and the overall elements do not change.

    Third: ionization, strong acids are all ionized by default, weak acids are also acidic, pH value weak acids are also about 3, salt hydrolysis, or pay attention to Le Charrett principle.

    Fourth, chemical equilibrium: the simple understanding is that the reaction is lazy, and if you move it once (if you change the conditions, it will move in the direction of the weakening conditions), the degree of movement is always not as good as the previous one, that is, there is a certain resistance (or Le Charlett's principle).

    That's pretty much it.

  8. Anonymous users2024-02-02

    You have to name the textbook that you use.

  9. Anonymous users2024-02-01

    This question is very simple, you should know that the HCl added before is excessive After neutralization, at this time, Al3+ happens to exist alone in the solution, Al3+ ions, Al ions are conserved, then.

    2.Shen Tan Hui defeated there is so much need naho is also 200ml is over Forget it is so complicated to do?

    The first question is to see the trembling precipitation to see what the precipitation is This question is decisively al(ho)3 According to the first sentence, you can get al3+, then the precipitation of aluminum hydroxide is yes Look at the mass of more oxygen than the Biye mass of hydrogen The answer comes out by direct oral calculation.

    The second question is even more boring The key is to see the question clearly Another question is from the precipitation to the complete disappearance The question is about the process 1mol aluminum hydroxide consumes a hydroxide 1 to 1 So there are three consumption Then 200ml is clear enough This kind of question Don't look at the process Don't care about the change Always conserve aluminum ions Those who get stupid calculations are reckless.

  10. Anonymous users2024-01-31

    Hello Al2O3 + 6HCl ==2ALCl3 + 3H20The maximum precipitated mass is the amount of precipitate formed by the complete reaction of aluminum chloride and sodium hydroxide.

    The maximum precipitation of AlCl3+3NaOH==Al(OH)3+3NaCl is.

    Method 1As you can see from the figure, it costs 20ml first

    The maximum precipitation to 20 that piece, yes.

    The last fast potato is Al(OH)3+NaOH==Naalo2+2H2ONaOH is.

    Then v=n c=(

    Method 2The precipitate just disappears, and the amount of sodium hydroxide substances added is equal to the sum of the amounts of substances of Cl- and AlO2- before the addition of ALO2-, the amount of sodium hydroxide substances added is equal to the sum of the amounts of CL- and ALO2-, and the volume of sodium hydroxide solution is several groups of state y, then there is, y*1(mol l)=, and c[HCL]=[ can be obtained from the figure

    Therefore y=, i.e. 820ml.

  11. Anonymous users2024-01-30

    Chemistry is a relatively systematic discipline.

    It will be divided into many chapters, pay attention to the title of the chapter. Compare this chapter with the nature of acids, and we have to look at it.

    It is best to sort out the syllabus in this chapter by yourself, and the chemistry exam is still mainly based on calculations, writing equations, and testing experiments. Fill a vacancy. Select Auxiliary.

    There should be between 3-5 chemistry experiments in a semester, and you should watch them several times and look at the details. Pay more attention to the calculation methods involved in the questions given at the end of the book, as well as several equations related to experiments. There are not many contents that can be tested in experiments and calculation questions, but there are many tricks, on the contrary, the content of fill-in-the-blank selection involves a wide range of content, but most of them are the outline content of the book, and it is not a big problem to pay more attention.

    The other thing is to do more questions. In previous years, the test papers were also good, pay attention to the question type, the basic school papers, the content of last year's test will not be tested this year, and pay more attention to the calculation equations involved in other major experiments and calculation questions.

  12. Anonymous users2024-01-29

    Find 3-5 copies of last year's exam questions from the Internet to do, list the knowledge points of each question, understand it thoroughly, and ask teachers and classmates if you don't know, you will achieve good results.

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