Senior one chemistry, can you explain it in detail? High School Chemistry??

After consuming y mol of silver nitrate, the total amount of chloride ions can be obtained as y mol;

After consuming xmol sulfuric acid, bacl2 can be obtained as xmol, and the amount of chloride ions contained in bacl2 is 2xmol;

Therefore, the amount of chloride ions contained in NaCl is (y-2x)mol, and the amount of sodium ions is also (y-2x)mol;

Based on this, it is known that the concentration of sodium ions in the original mixed solution is (y-2x)a

n(sulfuric acid)=n(SO42-)=n(ba2+)=xmol;

n(silver nitrate)=n(ag+)=n(cl-)=ymol;

According to the chemical formula or conservation of charge: 2N(Ba2+)+N(Na+)=N(Cl-).

i.e. 2x+n(na+)=y

n（na+）=y-2x

So c(na+)=n(na+) v=(y-2x) a

The first part consumes sulfuric acid: x; That is, there is also ba: x mol in the first part;

The second part consumes silver nitrate: y, i.e., the second part also has cl: y mol cause, and the first part is equally divided with the second part;

Therefore, the second part of NaCl is: Y-2*X

All sodium ions are: 2(y-2x).

So, the concentration of sodium ions is 2(y-2x)a

The molecular formula of water is H2O, the two elements in water are hydrogen and oxygen, so it is possible to determine whether there is electron transfer, the hydrogen in the water is +1 valence, oxygen is -2 valence, and the above A and B have gas precipitation, and the valency has changed. c and d have no change in valency.

The two elements in water (H2O) refer to the negative bivalent of oxygen (O) and the positive bivalent of hydrogen (H), and options A and B are redox reactions that generate elemental matter, and the hydrogen and oxygen elements in hydrogen and oxygen are all zero-valent, and the valency has changed.

Option c is a chemical reaction, not a redox reaction, and the valence of hydrogen and oxygen in the product calcium hydroxide has not changed.

Option d is a redox reaction, with a nitrogen element valency of nitrogen dioxide of +4 and an oxygen element valency of -2; The nitrogen element in the product nitric oxide is +2 valence, and the oxygen element is still -2 valence. The nitrate is -1 valence, and the hydrogen element valency is still +1 valence. Therefore, choose D.

The chemical formula of water H2O, so the two elements in water are hydrogen and oxygen, the meaning of this question is that hydrogen and oxygen have not undergone valence, hydrogen in water +1, oxygen -2

Option A produces hydrogen, and the hydrogen element valence changes from +1 to 0, wrong;

Option b produces oxygen, and the oxygen element changes from -2 to 0, error;

Option c is not a redox reaction, without any elemental valence, false;

Option d has the valence of nitrogen, which is a redox reaction, and the hydrogen element oxygen element does not undergo valence, so d is the correct answer.

<> should choose C. The two elements in water are hydrogen and oxygen.

Sodium carbonate is.

The carbonate ions contained in it are:

First of all, we must calculate its molar mass, which is how much it weighs in layman's terms. Then divide it by the actual mass to calculate the amount of its substance, which is how many parts there are. And because there are two carbonate ions in one serving, it is multiplied by two. Hope to adopt, thank you.

28. From the meaning of the title, n2 + 3h2===2nh3 start (mol) 0

Transformation (mol) a b c

Final ( mol) d

From the above column, we can find b=

So a=, c=, d=

1）v(h2)=[

v(n2)=(

v(nh3)=(

2) After 2min, there is still N2 left, so its concentration c = (3) The conversion rate of nitrogen f = (

Speed. h2：（ mol/(l•min)

mol/(l•min)

nh3： mol/(l•min)

Concentration. N2 reaction concentration (

N2 residual concentration.

N2 concentration conversion.

29.Let N2 react to x, then H2 reacts to 3x and NH3 generates 2x.

Then N2 is left 4-x, then H2 is left 8-3X, and NH3 produces a 2x volume ratio equal to the quantity ratio of the substance.

So the container is left with 4-x+8-3x+2x

Then the NH3 volume ratio is 2x = solution x = 1

I calculated it myself.

The Peugeot that reaches equilibrium is the positive reaction rate = reverse reaction rate, and the concentration of various components no longer changes.

The rate of formation of A:A2 is the rate of the reverse reaction, and the rate of decomposition of AB is also the rate of the reverse reaction, hence the error.

B: The generation of 2 N mol Ab is the positive reaction rate, and the generation of 1 N molA2 is the reverse reaction rate, and 1 N mol A2 corresponds to 2N MoLab, V (positive) = V (inverse). Hence the balance.

C: Breaking a-a is a positive reaction, only the reverse reaction consumes a-b will break a-b, and 1n mol a2 corresponds exactly to 2n molab, v (positive) = v (inverse). Hence the balance.

D: The concentrations of A2, B2 and AB no longer change, and the characteristic of equilibrium is that the concentrations of various components no longer change, and the equilibrium is reached. Flatness has nothing to do with the ratio of the number of molecules.

So the answer is b, c, d

Solve the problem with the three-step method:

2n2o5(g) =4no2(g)+ o2(g)。

Start: 4mol 0mol 0mol

Amount of change: 4mol * Calculated by the ratio of the change ratio equal to the number of measurements) when 5min:

1)υ（no2) = =

o2）= =

2) The fraction of N2O5 in the volume of the gas mixture is (*100%=62%.

cIf it is all gas, it depends on the relationship between na+mb<=>pc+qd.

n+m>q+p, the pressure increases, the reaction reacts in the direction of volume reduction, the equilibrium is positive, and the positive reaction rate increases. The reverse can also be pushed.

n+m doesn't know what I'm talking about, do you understand? If it's good, give it a call, and if it's not, continue to interrogate until it's good.

I'm all here! If you have any chemistry problems in the future, try to mention them, and I basically took 90 100 in high school. I wonder if it's okay for me to say that?

It seems that you have to consider the solubility of gas water.,I've encountered this kind of question before, it's all n answers or wrong.。。。

A non-metallic element in the various oxygenated acids it forms.

The oxygenated acid with the highest valence state of the element is called the element's.

The most ** oxygenated acids.

For example, sulfur is sulfurous.

The sulfur element in sulfurous acid is:

The sulfur element in 4-valent sulfuric acid is +6 valence.

Therefore, sulfuric acid is the most ** oxygenated acid of sulfur.

Sodium sulfate is present in the short-cycle version.

Sodium perchlorate. Sodium carbonate, sodium nitrate.

Sodium silicate, sodium phosphate.

Solution:1Let the average formula r

2r+2h2o=2roh+h2

n(h2)=

Therefore, the quality of the r.

Therefore, r phase original mass = 6

k phase original mass 39 30; The quality of the other alkali metal phase should be 30, so AB is selected

Strong oxidizing properties of Na2SO3, Nai, and Nabr: SO32 I br; Therefore, the oxidation order of SO32, I and BR oxidized products is: first Na2SO4, its I2BR2 (the original products are NaCl), bromine is volatile, iodine is easy to sublimate.

Capacity: Na2SO3, Na2SO4, NAI, NaBR, NaClNa2SO4, NaBR, NaCl

Na2SO4 and NaCl were selected as AB

⒈2ki+cl2=2kcl+i2

What is the phenomenon of this reaction?

To generate iodine element, starch is generally used, which is the reaction principle of starch potassium iodide test strips, which turns blue.

Why can't clo- coexist in large quantities with ferric iron or iodide ions or sulfite?

Positive monovalent Cl has strong oxidizing properties, which will oxidize ferrous iron to iron and sulfurous acid to sulfuric acid.

cl2+na2so3+h2o=na2so4+2hcl

cl2+agno3+h2o=agcl↓+hno3+hclo

What's the reaction of these two? I know that in the first case, because silver nitrate has no reducing properties, chlorine gas must first react with water to form hydrochloric acid and hypochlorous acid, and then hydrochloric acid is used as a reducing agent to react with silver nitrate, but why is it not hypochlorous acid and silver nitrate reaction? Please help me explain, please be more detailed!

There is a problem with what you said, the reaction between hydrochloric acid and silver nitrate is not a redox reaction, just an ordinary displacement reaction, and secondly, chloric acid will not react with silver nitrate, and the silver in silver nitrate should be replaced with a reducing agent, and hypochlorous acid is a typical strong oxidizing agent.

4HCl+mNO2 = Heating = MCl2+2H2O+Cl2

The book says that when there is enough manganese oxide, the concentrated hydrochloric acid will dilute after a period of time, so the actual chlorine gas produced is less than 1 mole. Why is it less than 1 mole? What the hell is going on?

This reaction is not written correctly, 4HCl (concentrated) + mno2 = heating = mnCl2 + 2H2O + Cl2

It is necessary to concentrate hydrochloric acid, and after the reaction is dilute hydrochloric acid, it will not react, so there is residual hydrochloric acid and insufficient chlorine.

Option: aFirst of all, don't confuse the effect of external conditions on the rate with the effect on the balance.

The effect of pressure is only for the gas reaction, and for the rate: increase the pressure, accelerate the chemical reaction rate, decrease the pressure, slow down the chemical reaction rate.

For the equilibrium system: only talk about the movement of equilibrium, the reason for the equilibrium movement is that the positive and inverse rates are no longer equal.

Increasing pressure: both positive and reverse rates increase; The equilibrium moves in the direction of the reduction in the volume of the gas.

In this reaction: the equilibrium is shifted forward, so the positive rate is greater than the reverse rate of the decreasing pressure: both the positive and reverse rates decrease; The equilibrium moves in the direction of the increase in the volume of the gas.

In this reaction: equilibrium is reversed, so the inverse rate is greater than the positive rate, from this, it can be seen that:

Therefore, you can only choose a

If O2 is excessive, the reaction is: 2H2S + 3O2 = 2H2O + 2SO2 Let the H2S participating in the reaction be 2 volumes and O2 be 3 volumes. Because it is in standard condition, the water is in a liquid state. Therefore, according to the equation, the volume becomes 5-2=3 volume smaller.

According to the title, the actual reduced volume is 90ml, so each volume is 30ml.

In this way, the volume of H2S and O2 involved in the reaction is greater than 100ml, which does not match the topic, so O2 can not be excessive, only H2S excess.

So the correct reaction is: 2H2S+O2=2H2O+2S or 2 reactions coexist, so the remaining gas may be (1)H2S

2) H2S and SO2

So choose b, e

(1) Pallet balance.

Because it is the main one, it is a pallet balance.

Filtrate: AlCl3 and aluminium chloride.

Ferrous chloride. FeCl2 and HCl hydrochloride

Iron and hydrochloric acid do not produce trivalent iron, because hydrochloric acid is excessive, so there is a surplus). In the slag: cusi. For filtration: beaker,

Glass rods (for drainage), funnels.

3)al3+

3oh-al(oh)3↓h++

oh-=h2oal(oh)3

oh-alo2-

2h2ofe2+

2oh-fe(oh)2↓

4) The percentage of AL is (

Due to the caustic soda solution.

is saturated, again at a certain temperature, so in solution.

Sodium hydroxide. Quality score.

No change, the pH in the solution does not change.

2na2o2+

2h2o=4

naoh+o2

The reaction consumes water, the mass of the solution decreases, and sodium ions are present in the solution.

Decrease, C2 chlorine is denser than air, hide in higher places; It is not necessary to drink more soy milk and milk, because chlorine will only enter the lungs. By possession.

Soft cloth masks with soapy water are also needed, because soapy water is alkaline 3Cl2+H2O=HCO+HCl

Sunlight exposure. 2hclo=2hcl+o2c4

Choose D, option C sulfate not only moves to PBO2, but also moves to PB, 1:1 relationship, option E acid continues to decrease, pH value should increase, only D is correct, because the density of sulfuric acid is greater than water, sulfuric acid decomposes, and the density of the electrolyte of course decreases.

Items b and c should be selected.

Because H2S and O2 may react in the following three ways:

1) 2H2S+O2=2H2O+2S (insufficient oxygen in this reaction) If only this reaction occurs, the remaining gas is only H2S, which is in line with the topic.

2) 2H2S + 3O2 = 2H2O + 2So2 (sufficient oxygen in this reaction) If only this reaction occurs, the remaining gas has the following conditions:

a.Only SO2

b.It is a mixture of SO2 and O2.

3) If 1) and 2) occur at the same time, i.e., there is no remaining H2S and O2, then the remaining gas is SO2

It is known that the remaining gas is only 10ml, and the gas should be 90ml, if only the reaction occurs2) the volume of H2S can be set to xml, then there is: x+

3/2x=90

x=36ml

36mlH2S can produce 36mlSO2, and the volume of SO2 alone is already more than 10ml, so 2) this situation does not exist.

3) Two reactions occur at the same time:

2h2s+o2=2h2o+2s

2h2s+3o2=2h2o+2so2

10 ml is calculated from 10 ml SO2 to calculate the volume of H2S and O2 consumed in the two reactions, which is in line with the topic.

So 10ml of residual gas could also be SO2