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Because the numerator and denominator of the fraction are added to the same number, the difference between the numerator and the denominator of the fraction does not change.
Denominator: (19-3) (7-5) x7=56 or; (19-3)/(1-5/7)=56
Numerator: (19-3) (7-5)x5=40 56x5 7=40 Then the added number is: 56-19=37 or 40-3=373 The denominator of 19 is 16 more than the numerator, and the denominator of 5 7 is 2 more than the numerator.
Because the difference between the numerator and the denominator of the fraction does not change, the numerator and denominator of 5 7 are enlarged at the same time (19-3) (7-5) = 8 times. Then the 5 7 after the covenant is before the covenant.
5 7 = (5x8) (7x8) = 40 56 then the added number is; 40-3=37 or 56-19=37
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Since the numerator denominator of 3 19 is added to the same number, and the difference between 3 and 19 is 16, then the difference between the numerator and denominator of this fraction before the reduction should also be 16. Now after the approximation of 5 7, and the difference between 5 and 7 is only 2, to make their difference 16, the numerator and denominator should be expanded by 8 times, so that we get 40 56, so we get the number added at the same time is 56-19=37 (40-3=37). So the added number is 37!
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If the fraction is 37 points, the numerator and denominator of 53 next to the orange, and the same number is added, the fraction obtained is true, the fraction is 5/7 of seven+, and the number of the royal belt is how much is the number of the circle, that is to say, 70/50 37, it is -7/5, and the topic is that he calculates.
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Let the number added by the yardstick be x, then according to the meaning of the question, there is (53+x) (37+x)=7 5, and the elevation of this square can be solved to obtain x=6 2=3. From this, it can be seen that the number added is equal to mold 3.
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It is equivalent to asking 29+x=7y, 5+x=9y, and finding x?
then 29*9+9x=5*7+7x
So tease stool x=-113
To verify, (29-113) Shanmai Brigade (5-113) = (84) (108) with good = 7 9
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The arithmetic late spike method is the same.
31-9) (7-5) = 11
The number to be added is 46 Dan Sakura.
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Let this number be m, then there is (9 m) (31 m) 5 7Sixth-grade students should know that two inner terms are equal to two outer terms. The hereditary is counted as (9 m) 7 (31 m) 5Solution: m 46
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Solution: (31 + number) (43 + number) = 4 5
There are 5 (31 + numbers) = 4 (43 + numbers).
155 + 5 number = 172 + 4 number.
5 numbers - 4 numbers = 172-155
Number = 17 i.e. this number is 17
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A fraction of 17 49 numerators, the denominator is added to the same number, about 9 13, what is the addition of this number?
Solution: Let the number added be x
17+x)/(49+x)=9/13
13(17+x)=9(49+x)
221+13x=441+9x
13x-9x=441-221
4x=220
x=55
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This kind of question is done by, well, and in turn take that 9 13 a certain number, and then make 9 + this number equal to 1713 and this number is equal to the one that is a multiple of 49. So the medicine is fit, so I.
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A fraction of 17 49 numerator, the denominator is added to the same number, after the fraction is 9 13, the number added is (55), 49*9-17*13) (13-9).
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The numerator and denominator differ by 34-7=27
The ratio of the numerator and denominator is 5:14
So the molecule is 27 5 (14-5) = 15
So this number is 8
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Let the number added be x
7+x)/(34+x)=5/14
5(34+x)=14(7+x)
170+5x=98+14x
9x=72x=8 adds the number 8
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