Prep math problems I just entered prep class, and the questions are quite simple .

Question 1: Answer:

Because it is used up, and it is twice the remaining oil. So the remaining oil is.

Plus the ones that are used. It's how many kilograms there were. i.e. 1+.

Question 2: Answer x = 6

This is a non-ary equation that is not difficult. The teacher made no mistake.

Step 1: Remove the brackets to get: 18-6+8x=10xStep 2: Move 8x to the right of the equal sign, get: 12=2x so x=6 Question 3: Answer: 12l and 1000 bottles.

30ml= Since there is one bottle, so 400 bottles is the second question: since there are 30 liters, then a total of 30 bottles can be filled.

Question 4: Answer.

80cm=8dm.

Now we know the length, width and volume.

Isn't it tall to divide the volume by the length and width? i.e. 64 (Many of the answers on the first floor are wrong.) On the second floor, there was an error in the unit conversion. It should be 1dm=10cm

Kilogram. 18-6+8x=10x

2x=12x=6

ml = 12 liters.

30 ml = liters, 30 bottles.

Centimeter = decimeter.

64 2 = 32 decimeters.

Odd numbers within 6 are 1, 3, 5

Then, the fraction that is composed of less than 1 has 1 3, 1 5, 3 and 5

So the answer is to let the case choose C

27：（1）1/2；（2） 1/3；（3) 2/3

28: Any number n, greater than him is n+1;n+2；smaller than his digital n-1; n-2；Their sum bit n+(n+1)+(n+2)+(n-1)+(n-2)=5n, so it is divisible by 5.

75 centimeters = meters.

1413 digger 75 =6

It takes 6 minutes to pass the 1413-meter Zaoxiao Highway in Lusan.

Question 1: 8 times.

The volume is = edge length * edge length * edge length after becoming 2 times = (2 * edge length) (2 * edge length) (2 * edge length) = 8 * edge length * edge length * edge length is 8 times the previous one.

Question II: 64

After being sawn in half, there are two more cross-sections, each with a cross-sectional area of 32 2 16 square centimeters. Because the cross-section is square, the side length of the original cube is 4 cm (446 m), and the formula for the volume of the cube is the cubic of the side length. So, the original cube volume:

4 times 4 times 4 = 64 square centimeters.

Question 3: 40

It can be divided into three cases: they are cut from length, width, and height.

First: cut from the length, the increased surface area is the area of two sections, that is, 2 * width * height, that is, 2 * 5 * 4 40 (square centimeters).

Second: cut from the width, the increased area is the area of two sections, that is, 2 * length * height, that is, 2 * 6 * 4 48 (square centimeters).

Third: cut from the height, the increased area is the area of the two sections, that is, 2 * length * width, that is, 2 * 6 * 5 60 (square centimeters).

Question 1: 8

12 vi:12

cubic decimeters. 100,000 cubic meters.

24/11

The last question is incorrect, it is the gravity that changes to one-sixth rather than the weight, according to the scientific fact that 40kg should be 20 3 according to the thinking of the students in the preparatory class

With a 32-meter-long wooden strip, it can be cut just enough to build a rectangular frame, and the length, width, and height of the cuboid are all integer meters, and they are not equal.

So let the length of the cuboid be x, the width y, and the height z.

So 4x+4y+4z=32 (x,y,z are all integer meters, and none of them are equal) so x+y+z=8

So x,y,z can be 5,2,1 or 4,3,1, so the volume of this cuboid = 5 2 1 = 10 cubic meters or 4 3 1 = 12 cubic meters.

Sum of edge lengths of the box = (length + width + height) 4

Set length: x width: y height: z

x+y+z=8

x≠y≠z, and x, y, and z are unequal positive integers.

then x is not on topic.

x=5,y=2,z=1 or x=5,y=1,z=2 with a volume of 10x=4,y=3,z=1 or x=4,y=1,z=3 with a volume of 12x=3,y=4,y x is not on topic.

The least common multiple of 2 and 3 is 6, so divide each whole (1) into 6 parts, 10/3 is 1/3 is 2 points, and the 10 parts are 20, that is, 3 more than 2 parts, 1/3 is 3, 2 needless to say, 5/2 is 5 2/2, that is, more than 3 parts) Please adopt.